Simple Harmonic...

A particle moves according to the law x = a cos πt/2. The distance covered by it in the time interval between t = 0 to t = 3 s is

A particle executing SHM has a maximum speed of 30 cm/s and a maximum, acceleration of 60cm/s⁻². The period of oscillation is

The x−t graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t = 4/3​ s is

A tunnel has been dug through the centre of the earth and a ball is released in it. It executes S.H.M. with the time period:

Choose the correct statement regarding SHM,

The plot of velocity (v) versus displacement (x) of a particle executing simple harmonic motion is shown in figure. The time period of oscillation of particle is

The displacement of a body executing SHM is given by x=Asin(2πt+π/3).The first time from t=0 when the velocity is maximum is 

Time period of a particle executing SHM is 88 sec. At t=0 it is at the mean position. The ratio of the distance covered by the particle in the 1st second to the 2n second is:

Two particles execute SHM of the same amplitude and frequency along the same straight line. If they pass one another when going in opposite directions, each time their displacement is half their amplitude, the phase difference between them is

The time period of oscillation of a particle, that executes SHM, is 1.2s. The time, starting from mean position, at which its velocity will be half of its velocity at mean position is ?