Simple Harmonic...

Two simple harmonic motions of angular frequencies 100 and 1000 rad s^-1 have the same displacement amplitude. The ratio of their maximum acceleration is:

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300 m/s. What is the phase difference between the oscillations of two points?

A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is:

A rectangular block of mass m and area of cross-section A floats in a liquid of density ρ. If it is given a small vertical displacement from equilibrium, it undergoes oscillation with a time period T. Then:

The displacement of a particle executing simple harmonic motion is given by,

y = A₀ + A sinωt + B cosωt.

Then the amplitude of its oscillation is given by:

The average velocity of a particle executing SHM in one complete vibration is:

Two pendulums have time periods T and 5T/4. They start SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation?

A simple harmonic oscillator has amplitude 'a' and time period T. The time required by it to travel from x=a to x = a/2 is

The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0 m. If the piston moves with simple harmonic motion with an angular frequency of 200 rad/min, what is the maximum speed?