Self Studies

Electric Current Test - 22

Result Self Studies

Electric Current Test - 22
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    A brass disc and a carbon disc of same radius are assembled alternatively to make a cylindrical conductor. The resistance of the cylinder is independent of the temperature. The ratio of thickness of the brass disc to that of the carbon disc is ______. α is temperature coefficient of resistance & Neglect linear expansion

    Solution

  • Question 2
    1 / -0

    Out of the following which is not a poor conductor ?

    Solution


    J= {J0[(x/R)-1] 0 ≤ x ≤ R/2,     {J0(x/R) R/2 ≤ x ≤ R
     We know that,
    J=current/area
    ⇒ current=J Area
    Current= J1A1 +J2A2
    =J0{(x/R)−1}x(2πxdx)+J0 (x/R)(2πxdx)
    =∫0R/2J0{(x/R)-1} x (2πxdx) + =∫0R/2J0 x 2π (x2/R)dx
    = J0×2π∫0R/2 {(x2/R)−x}dx + (J0×2π/R) ∫RR/2 x2dx
    ⇒ i=J0×2π [(x3/3R)-(x2/2)] R/2 + (J0×2π/R) [x3/3]R2/R
    ⇒i=J0×2π [(R2/24)−(R2/8)]+ (J0×2π/R)[(R3/3)-(R3/24)]
    =J0×2π(−2R2/24)(J0×2π/R)[7R3/24]
    i =(5/12)πJ0R2
     

  • Question 3
    1 / -0

     Under what condition current passing through the resistance R can be increased by short circuiting the battery of emf E2. The internal resistances of the two batteries are r1 and r2 respectively.

                          

    Solution

    The current through the circuit before the battery of emf E2​ is short circuited, is
    i1​=(E1​+E2)/r1​+r2​+R​​             ...(i)
    After short circuiting the battery of emf E2​, current through the resistance R would be
    i2​= E1/R+r1​ ​​            ...(ii)
    Since, from equation (i) and (ii), we get
    i2​>i1​
    ∴ E1/R+r1​ ​​> E1​+E2​​/R+r1​+r2
    This gives E1​r2​>E2​(R+r1​)

  • Question 4
    1 / -0

     ABCD is a square where each side is a uniform wire of resistance 1Ω. A point E lies on CD such that if a uniform wire of resistance 1W is connected across AE and constant potential difference is applied across A and C then B and E are equipotential.

                     

    Solution

    Wire of resistance =1Ω
    Keeping in view that, ABCD is a square where each side is uniform wire of resistance 1Ω. If a uniform wire of resistance 1Ω is connected across AE and a potential difference is applied across A and C, the points B and E will be equipotential; a point E on CD is CE​/ ED =√2/1
    ∴    CE:ED= √2​:1

  • Question 5
    1 / -0

    Two current elements P and Q have current voltage characteristics as shown below :

    Which of the graphs given below represents current voltage characteristics when P and Q are in series.

  • Question 6
    1 / -0

    Power of battery in resistor appears as

  • Question 7
    1 / -0

    A simple circuit contains an ideal battery and a resistance R. If a second resistor is placed in parallel with the first.

    Solution

    When a resistor is added parallel to other resistor in circuit it results in the reduction of overall resistance, since there are multiple pathways by which charge can flow. adding another resistor in a separate branch provides another pathway by which to direct charge through the main area of resistance within the circuit. This decreased resistance resulting from increasing the number of branches will have the effect of increasing the rate at which charge flows i.e. the current.

  • Question 8
    1 / -0

     Consider the circuit shown in the figure

                   

    Solution

    RAD=1/(1/10)+(1/3+4+3)=5Ω
    RCB=1/(1/10)+(1/3+5+2)= 5Ω
    i=28/5+5+4=2A
    current through 5Ω is 2A
    RCADB=RCB
    ⇒iCA=iCB=i/2=1A
    VCA=1x3=3V
    VCB=1x10=10V
    VAB=VCB-VCA=10-3
    VA-VB=7V

  • Question 9
    1 / -0

    A copper wire of radius 0.1 mm and resistance 1 kW is connected across a power supply of 20 V. How many electrons are transferred per second between the supply and the wire at one end ?

  • Question 10
    1 / -0

    A car has a fresh storage battery of emf 12 V and internal resistance 5.0 × 10-2W. If the starter draws a current of 90 A, what is the terminal voltage of the battery when the starter is on ?

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now