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Electric Current Test - 9

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Electric Current Test - 9
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  • Question 1
    1 / -0

    An electric bulb is rated 220 volt - 100 watt. What will be the power consumed by it when operated on 110 volt?

    Solution

    100 = (220)2/R
    P = (110)2/R
    ⇒ P = 25 W

  • Question 2
    1 / -0

    The resistance of a bulb filament is 100Ω at a temperature of 100°C. If its temperature coefficient of resistance is 0.005 per °C, then its resistance will become 115Ω at a temperature of

    Solution

    R = R0(1 + αΔT)
    115 = 100[1 + 0.005(T - 100)]
    T = 130°C

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