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Units & Dimensions Test - 9

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Units & Dimensions Test - 9
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  • Question 1
    1 / -0

    Which of the following sets cannot enter into the list of fundamental quantities in any system of units ?

    Solution

    We define length and time separately as it is not possible to define velocity without using these quantities. This means that one fundamental quantity depends on the other. So, these quantities cannot be listed as fundamental quantities in any system of units.

  • Question 2
    1 / -0

    Which of the following is not the unit of time

    Solution

    Parallactic second is the unit of distance because parallactic second is an abbreviation of parsec. Parsec = Parsec is the Unit for larger distances.It is the distance at which a star would make parallax of one Second of arc.

  • Question 3
    1 / -0

    The unit of impulse is the same as that of :

    Solution

    The newton second (also newton-second, symbol N s or N.s) is the derived SI unit of impulse. It is dimensionally equivalent to the momentum unit kilogram metre per second (kg.m/s). One newton second corresponds to a one-newton force applied for one second.

  • Question 4
    1 / -0

    Which of the following is not the unit of energy?

    Solution

    F = ma
    [F] = kg m/s2

  • Question 5
    1 / -0

    If the unit of length is micrometer and the unit of time is microsecond, the unit of velocity will be :

    Solution

    Unit of velocity = m/s
    1m = 106  Micro meter
    And 1 sec = 106  Micro sec
    Thus 1 m/s = 106 106  micro meter /micro second

  • Question 6
    1 / -0

    What is the physical quantity whose dimensions are M L2 T-2 ?

    Solution

    Dimension of KE is ML2T-2
    That of pressure is ML-2T-2
    That of momentum is ML/T 
    That of power is ML2T-3

  • Question 7
    1 / -0

    A unitless quantity :

    Solution

    A dimensionless quantity can have unit. for example angle (radian). But oppisite is not true. A unitless quantity can never have dimensions.it is the unit that give dimensions.

  • Question 8
    1 / -0

    If a and b are two physical quantities having different dimensions then which of the following can denote a new physical quantity

    Solution

    Quantities with different dimensions cant be added or subtracted. Also the dimension of the product of the quantities in power is always one. But when two quantities are multiplied the dimension of the product is the product of the dimensions of the initial quantities.

  • Question 9
    1 / -0

    Two physical quantities whose dimensions are not same, cannot be :

    Solution

    The two physical quantities which do not have the same dimensions can’t be added or subtracted in the same expression because doing so would lead to equating two quantities of different dimensions, which is non possible. Ex [F]  [P].

  • Question 10
    1 / -0

    Choose the correct statement (S)

    Solution

    Correct Answer :- d

    Explanation : a) A topological sort of a directed acyclic graph (DAG) is any ordering m1, m2, …, mn of the nodes

    of the graph, such that if mimj is an edge then mi appears before mj . Any topological sort of a

    the dependency graph gives a valid evaluation order for the semantic rules. 

    b) The parse tree can be annotated with synthesized or inherited attributes. The parse tree can also be indicated with an arrow mark to indicate the manner in which the value gets propagated between the nodes of the parse tree. This graph is called as dependency graph as it indicates the dependency between nodes for deriving the values. This graph is an acyclic graph which doesn’t have a cycle. The presence of a cycle indicates that the graph is incorrect as the dependence of nodes for deriving values cannot be predicted. Edges in the dependence graph show the evaluation order for attribute values and thus the graph is a directed one.

  • Question 11
    1 / -0

    Planck's constant has the dimensions of :

    Solution

    We know that E = hv , where E is energy and v is frequency.
    Thus we get h = E/v
    And [h] = [E/v] = ML2T-2 / T-1
    = ML2T-1
    [P] = MLT-1
    [F] = MLT-2
    [Angular momentum] = [P x r] = ML2T-1

  • Question 12
    1 / -0

    Electron volt is a unit of

  • Question 13
    1 / -0

    The dimensional formula of RT is same as that of:

    Solution

    The vander Waals gas equation is 

    where P is the pressure, V is molar volume and T is the temperature of the given sample of gas. R is called mola gas constant, a and b are called vander Waals constants.

  • Question 14
    1 / -0

    Which pair of following quantities has dimensions different from each other

    Solution

    Moment of inertia =1/2​×mass×(Radius of gyration)2=[M1L2T0]
    Moment of force = torque =N.m=[M1L2T−2]
    Both are different from each other.

  • Question 15
    1 / -0

    If the error in measurement of radius of sphere is 1% , what will be the error in measurement of volume 

    Solution

    Volume=4πR3/3
    ΔV/V×100=3∆R/R×100
    =3×1/100​×100
    =3
    ∴ Percentage error in volume is 3%

  • Question 16
    1 / -0

    The velocity 'v' (in cm/s) of a particle is given in terms of time 't' (in s) by the equation

    v = at + 

    The dimensions of a, b and c are

    Solution

    As v = at + b / (t + c)
    We get that v, at and b / (t+c) have the same dimensions as they are equated and added.
    Similarly c and t have also same dimensions, [c] = T and [a] = L/T
     And [b] = L

  • Question 17
    1 / -0

    In case of measurement of ‘g’, if error in measurement of length of pendulum is 2%, the percentage error in time period is1 %. The maximum error in measurement of g is

    Solution

    Time period of oscillation of pendulam 

    where L is length of pendulam and g is acceleration due to gravity.
    hence we have  ...........................(1)
    hence 

  • Question 18
    1 / -0

    The time dependence of a physical quantity ?

    P = P0exp(_at2)

    where a is a constant and t is time. The constant a

    Solution

    We know that any quantity in power as a dimension of 1, thus [at2] = 1
    Thus we get [a] = T-2

  • Question 19
    1 / -0

    Force F is given in terms of time t and distance x by

    F = A sin C t + B cos D x

    Then the dimensions of  and  are given by

    Solution

    Dimension of [A]=[MLT-2]
    Dimension of [B]=[MLT-2]
     
     [A]/[B]= [ M0L0T0]
    CT=1
    Dimension of  [C]=1/[T]=[T-1]
    DL=1
    Dimension of  [D]=1/[L]=[L-1]
    [C][D] =[T-1]/[L-1]
    =LT-1
     
    A/B=Force/Force=[M0L0T0]
    Ct=∠⇒C=Angle/Time=1/T=T-1
    Dx=∠⇒D=Angle/Distance=1/L=L-1
    ∴C/D=T-1L-1 =[M0 LT-1 ]

  • Question 20
    1 / -0

     The Van der Waal equation for 1 mole of a real gas is

    where P is the pressure, V is the volume, T is the absolute temperature, R is the molar gas constant and a, b are Van dar Waal constants. The dimensions of a are the same as those of

    Solution

    The answer is PV2
    Solution,
    As we know the Vander Waals equation is {P+(a/V2)} (V−b) =RT
    Then,
    The dimension of a is,
    (a/V2) = (P)
    Or, a=PV2

  • Question 21
    1 / -0

     The dimensional formula of coefficient of viscosity is

  • Question 22
    1 / -0

    If force (F) is given by F = Pt_1 + Qt, where t is time. The unit of P is same as that of

    Solution

    According to the principle of homogeneity of dimension, an equation is dimensionally correct when each term has same dimension on both sides of the equation. 

    Since left side has dimension of force so the term Pt−1 will have also dimension of force. 

    Thus, [P][T−1]=[F]=[MLT−2]

    or [P]=[MLT−1]

    We know that the dimension of momentum is [p]=[MLT−1]

  • Question 23
    1 / -0

    The product of energy and time is called action. The dimensional formula for action is same as that for

    Solution

    Both are different from each other.
    Energy × Time=(M1L2T−2)×(T1)=M1L2T−1
    Force × Velocity=(M1L1T−2)×(L1T−1)=M1L2T−3
    Impulse × distance=(M1L1T−1)×(L1)=M1L2T−1
    Power=M1L2T−3
    Angular Energy=M1L1T−2

  • Question 24
    1 / -0

    When a wave traverses a medium, the displacement of a particle located at x at time t is given by y = a sin (bt - cx) where a, b and c are constants of the wave. The dimensions of b/c are the same as those of

    Solution

    Argument of sin is dimensionless and using principle of dimensional homogeneity, we get
    ∣bt∣=∣cx∣=[M0L0T0]
    Thus, ∣b∣=T−1 and ∣c∣=[L−1]
    Thus, dimensions of b/c are [LT−1], which is the same as the velocity of wave.

  • Question 25
    1 / -0

    In the above question dimensions of b/c are the same as those of

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