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Charges & Magnetism Test - 14

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Charges & Magnetism Test - 14
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  • Question 1
    1 / -0

    A charged particle with charge q enters a region of constant, uniform and mutually orthogonal fields  with a velocity  perpendicular to both , and comes out without any change in its magnitude or direction. Then 

    Solution

    When  are perpendicular and velocity has no change then qE = qvB i.e. v= E/B. The two forces oppose each other so, v is along  i.e., .
    As  are perpendicular to each other 

  • Question 2
    1 / -0

    A charged particle would continue to move with a constant velocity in a region wherein, which of the following conditions is not correct?

  • Question 3
    1 / -0

    The cyclotron frequency vc is given by 

    Solution

    In cyclotron the centripetal force is balanced by magnetic force, then
    qvB = mn2/r ⇒ qBr/m = v
    where v = 2πrv∴ vc = qB/2πm

  • Question 4
    1 / -0

    A charged particle is moving in a cyclotron, what effect on the radius of path of this charged particle will occur when the frequency of the radio frequency field is doubled?

    Solution

    As frequency of revolution in a cyclotron
    vC = Bq/2πm is independent of r.
    So the radius of path in the dees will remain unchanged. When the frequency is changed.

  • Question 5
    1 / -0

    A cubical region of space is filled with some uniform electric and magnetic field. An electron enters the cube across one of its faces with velocity v and a positron enters via opposite face with velocity - v. At this instant, which one of the following is not correct?

  • Question 6
    1 / -0

    A cyclotron is operated at an oscillator frequency of 12 MHz and has a dee radius R = 50 cm. What is the magnitude of the magnetic field needed for a proton to be accelerated in the cyclotron?

  • Question 7
    1 / -0

    If an electron is moving in a magnetic field of 5.4 x 10-4 T on a circular path of radius 32 cm having a frequency of 2.5 MHz, then its speed will be 

    Solution

    Here, B = 5.4 x 10-4 T;
    r = 32 cm = 32 x 10-2 m; v = 2.5 MHz = 2.5 x 106Hz 
    The speed of electron on circular path
    v = r x 2πv = 32 x 10-2 x 2 x 3.14 x 2.5 x 106
    = 502.4 x 104 = 5.024 x 106 m s-1 

  • Question 8
    1 / -0

    A proton and an α-partide enter in a unifoi magnetic field perpendicularly with same speed. The ratio of time periods of both particle (TP/Tα) will be

    Solution

    The time period of revolution of a charged particle in a magnetic field is 
    T = 2πm/Bq
    For proton, mP = m, qP = q ; ∴ TP = 2πm/Bq
    Now, for α-particle, mα = 4m, qα = 2q
    ∴ Tα = (2π(4m))/(B(Bq)) = 2(2πm/Bq) ⇒ TP/Tα = 1/2

  • Question 9
    1 / -0

    A proton, a deutron and an α-particle with same, kinetic energy enter perpendicularly in a uniform magnetic field, then the ratio of radii of their circular paths is

    Solution

    ∵ r = ∴ r ∝ √m/q
    Hence, rp : rd ; rα = 

  • Question 10
    1 / -0

    If an electron enters with a velocity  into a cubical region in a uniform electromagnetic field and the orbit of the electron is found to spiral down inside the cube in plane parallel to x-y plane then the configuration of electric field and magnetic field is 

    Solution

    The orbit of the electron spirals down inside the cube in the plane parallel to x−y plane. Therefore  must be along +z  direction and should be along x−axis.

  • Question 11
    1 / -0

    Which of the following is not correct about cyclotron?

    Solution

    The charged particles and ions in cyclotron can move along circular path only.

  • Question 12
    1 / -0

    The operating magnetic field for accelerating protons in a cyclotron oscillator having frequency of 12 MHz is (q = 1.6 x 10-19C, mp = 1.67 x 10-27 kg and 1 MeV = 1.6 x 10-13 j)

    Solution

  • Question 13
    1 / -0

    In the question number 34, the kinetic energy (in MeV) of the proton beam produced by the accelerator is (radius of dees = 60 cm)

    Solution

    Final velocity of proton is 
    v = r x 2πv = 0.6 x 2 x 3.14 x 12 x 106 = 4.5 x 107 m s-1

    = 10.6 MeV

  • Question 14
    1 / -0

    An electron is moving in a cyclotron at a speed of 3.2 x 107 m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?
    (q = 1.6 x 10-19 C, me = 9.1 x 10-31 kg)

    Solution

    v = 3.2 x 107 m s-1 ;B = 5 x 10-4 T
    The frequency of electron is

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