Surface Tension Test

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Surface Tension Test - 4

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Weekly Quiz Competition

Question 1
1 / -0

Oil spreads over the surface of water whereas water does not spread over the surface of the oil, due to

A
Surface tension of water is very high

B
Surface tension of water is very low

C
Viscosity of oil is high

D
The viscosity of water is high

Solution

The surface tension of the water is more than oil. Therefore, when oil is poured over water, the greater value of surface tension of water pulls the oil in all direction and as such it spreads on the water. On the other hand, when water is poured over oil, it does not spread over it because the surface tension of oil is less than that of water, it is not able to pull water over it.
Question 2
1 / -0

The property utilized in the manufacture of lead shots is

A
Specific weight of liquid lead

B
Specific gravity of liquid lead

C
Compressibility of liquid lead

D
Surface tension of liquid lead

Solution

The free surface liquid drop always try to minimize the surface energy or surface tension, which is done by spherical shape of lead shots.
Question 3
1 / -0

The dimensions of surface tension are

A
[MLT⁻¹]

B
[ML²T⁻²]

C
[ML⁰T⁻²]

D
[ML¹T⁻²] This quantity S is the magnitude of surface tension

Solution

The surface tension is given as:
Question 4
1 / -0

A wooden stick 2 m long is floating on the surface of the water. The surface tension of water is 0.07 N/m. By putting soap solution on one side of the stick, the surface tension is reduced to 0.06 N/m. The net force on the stick due to surface tension will be:

A
0.07 N

B
0.06 N

C
0.01 N

D
0.02 N

Solution

Net force on stick = F₁−F₂= (T₁−T₂) × l

= (0.07-0.06) × l = 0.01x2 = 0.02 N
Question 5
1 / -0

Surface tension may be defined as:

A
the work done per unit area in increasing the surface area of a liquid under isothermal conditions

B
the work done per unit area in increasing the surface area of a liquid under adiabatic conditions

C
the work done per unit area in increasing the surface area of a liquid under isochoric conditions

D
free surface energy per unit volume

Solution

Surface tension of a liquid may be defined as the work done per unit area in increasing the surface area of a liquid under isothermal conditions.
Question 6
1 / -0

The energy needed to break a drop of radius R into n drops of radii r is given by:

A
4πT (nr² − R²)

B
4/3π (r³n − R²)

C
4πT (R² − nr²)

D
4πT (r²n + R²)

Solution

Energy needed = Increment in surface energy

= (surface energy of n small drops) – (surface energy of one big drop)

= n4πr²T − 4πR²T = 4πT(nr²−R²)
Question 7
1 / -0

The potential energy of a molecule on the surface of liquid compared to one inside the liquid is -

A
Zero

B
Smaller

C
The same

D
Greater

Solution

When the surface area of the liquid is increased molecules from the interior of the liquid rise to the surface. This work is stored in the molecules in the form of ofpotential energy. Thus, the potential energy of the molecules lying on the surface is greater than that of the molecules in the interior of the liquid.
Question 8
1 / -0

Two droplets merge with each other and forms a large droplet. In this process

A
Energy is liberated

B
Energy is absorbed

C
Neither liberated nor absorbed

D
Some mass is converted into energy

Solution

When two droplets merge with each other, their surface energy decreases.

W = T(ΔA) = (negative) i.e. energy is released
Question 9
1 / -0

Work done in splitting a drop of water of 1 mm radius into 10⁶ droplets is (Surface tension of water = 72 × 10^-3 J/m²

A
9.58 × 10⁻⁵ J

B
8.95 × 10⁻⁵ J

C
5.89×10⁻⁵ J

D
5.98×10⁻⁵ J

Solution

Work done in splitting a water drop of radius R into n drops of equal size
Question 10
1 / -0

The amount of work done in blowing a soap bubble such that its diameter increases from d to D is (T= surface tension of the solution)

A
4π(D² − d²)T

B
8π(D² − d²)T

C
π(D² − d²)T

D
2π(D² − d²)T

Solution

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Surface Tension Test - 4

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Surface Tension Test - 4

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Question 1

Surface tension of water is very high

Surface tension of water is very low

Viscosity of oil is high

The viscosity of water is high

Solution

Question 2

Specific weight of liquid lead

Specific gravity of liquid lead

Compressibility of liquid lead

Surface tension of liquid lead

Solution

Question 3

[MLT−1]

[ML2T−2]

[ML0T−2]

[ML1T−2] This quantity S is the magnitude of surface tension

Solution

Question 4

0.07 N

0.06 N

0.01 N

0.02 N

Solution

Question 5

the work done per unit area in increasing the surface area of a liquid under isothermal conditions

the work done per unit area in increasing the surface area of a liquid under adiabatic conditions

the work done per unit area in increasing the surface area of a liquid under isochoric conditions

free surface energy per unit volume

Solution

Question 6

4πT (nr2 − R2)

4/3π (r3n − R2)

4πT (R2 − nr2)

4πT (r2n + R2)

Solution

Question 7

Zero

Smaller

The same

Greater

Solution

Question 8

Energy is liberated

Energy is absorbed

Neither liberated nor absorbed

Some mass is converted into energy

Solution

Question 9

9.58 × 10−5 J

8.95 × 10−5 J

5.89×10−5 J

5.98×10−5 J

Solution

Question 10

4π(D2 − d2)T

8π(D2 − d2)T

π(D2 − d2)T

2π(D2 − d2)T

Solution

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[MLT⁻¹]

[ML²T⁻²]

[ML⁰T⁻²]

[ML¹T⁻²] This quantity S is the magnitude of surface tension

4πT (nr² − R²)

4/3π (r³n − R²)

4πT (R² − nr²)

4πT (r²n + R²)

9.58 × 10⁻⁵ J

8.95 × 10⁻⁵ J

5.89×10⁻⁵ J

5.98×10⁻⁵ J

4π(D² − d²)T

8π(D² − d²)T

π(D² − d²)T

2π(D² − d²)T