Electronic Devices and Communication Systems Test

Result

Electronic Devices and Communication Systems Test - 2

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Weekly Quiz Competition

Question 1
1 / -0

In Boolean algebra, if A = 0 and B = 1, then the value of A.A + B is

A
A

B
B

C
A + B

D
A.B

Solution

A.A = 0.0 = 0. Therefore, A.A + B = 0 + B = 0 + 1 = 1 = B.
Question 2
1 / -0

For conduction in P-N junction, the biasing is

A
high potential on N side and low potential on P side

B
high potential on P side and low potential on N side

C
the same potential on both P and N sides

D
indeterminate

Solution

For conduction in P-N junction, the biasing is high potential on P side and low potential on N side.
Question 3
1 / -0

NAND and NOR gates are called universal gates primarily because they

A
are available universally

B
can be combined to produce OR, AND and NOT gates

C
are widely used in integrated circuit packages

D
are easy to manufacture

Solution

Since all the gates can be obtained from NAND and NOR gates by using logical circuits or algebraic expressions, so these gates are universal gates.