Motion in a Plane Test 4

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Motion in a Plane Test 4

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Question 1
1 / -0

Which one of the following is not an example of projectile?

A
A bullet fired from a gun.

B
A kicked football.

C
Taking off of an aircraft.

D
A javelin thrown by an athlete.

Solution

Projectile motion is a natural phenomenon it is due to the gravity in earth surface .it doesn't need any external force .The flight seems to be same as an projectile motion but it differs as an external force is applied which is the aircraft engine which pulls the craft forward and hence oppose the force of gravity.
Question 2
1 / -0

A battle ship simultaneously fires two shells at enemy ships. Both are fired with the same speed but with different directions as shown. If the shells follow the parabolic trajectories shown, which ship gets hit first?

A
they get hit at the same time.

B
ship μ2

C
need more information about the trajectories.

D
ship μ1

Solution

Ship 2 gets hit first. The time of flight only depends on the y-component of motion, not the x-component. The higher you throw something up in the air, the more time it spends in the air. It can also be shown from equation-
y=v_0y t – ½ g t²=0
v_0y for projectile μ1 is greater than for μ2.
Question 3
1 / -0

If an object is dropped through the window of a fast running train. Then

A
the object moves straight horizontally.

B
to a man standing near the track, path of the object will be a part of parabola.

C
the object falls down vertically.

D
the object will follow an elliptical path

Solution

When an object is still held it is the part of a system in which the train is moving, once it is left it still has the same velocity as the train for a person from ground. Thus as the velocity is horizontal and acceleration is vertical, it would follow a parabolic trajectory.
Question 4
1 / -0

Which statement is true for a ball thrown at 20 degrees with the horizontal, when it is at the highest point in its trajectory?

A
Its velocity is zero but its acceleration is nonzero

B
Its velocity is nonzero but its acceleration is zero

C
Its velocity and acceleration are both zero

D
Its velocity is perpendicular to its acceleration

Solution

At the highest point in its trajectory, the acceleration (g) is acting in downward direction, whereas velocity of the projectile is only in the X (horizontal) direction.
Question 5
1 / -0

How many directions are possible for the same horizontal range?

A
4

B
3

C
2

D
1

Solution

We know that the horizontal range for any projectile motion let say R = 2u².sin 2a /g
Where u is initial speed, and a is the angle at which the particle is thrown, which is responsible for direction. So in between the possible range of a that is 0 - 90, there are maximum two equal values of sin 2a, thus the maximum number of directions for the same or equal range are 2.
Question 6
1 / -0

A body is thrown with a velocity of 10m/s at an angle of 60 degrees with the horizontal. Its velocity at the highest point is:

A
5 m/s

B
8.7 m/s

C
10 mis

D
0

Solution

At the highest point, its vertical velocity will become zero. Hence the only left velocity is horizontal which remains unchanged and is equal to 10 cos 60 = 5m/s
Question 7
1 / -0

The quantity which remains unchanged during the flight of an oblique projectile is

A
Horizontal component of acceleration

B
Vertical component of acceleration

C
Vertical component of velocity

D
Horizontal component of velocity

Solution

As there is no horizontal acceleration is present in oblique projection horizontal component of velocity is constant
Question 8
1 / -0

At the point of maximum height, the acceleration is:

A
minimum

B
g

C
maximum

D
zero

Solution

At a point of maximum height, the derivative of displacement i.e. velocity is zero but as the gravitational acceleration is equal at all near points to the surface of earth, acceleration at maximum height is still equal to g.
Question 9
1 / -0

At what angle should a projectile with initial velocity ‘v’ be thrown, so that it achieves its maximum range?

A
45⁰

B
90⁰

C
60⁰

D
30⁰

Solution

Sine of an angle has maximum value 1 when the angle is 90 degree Rmaxis obtained when 2ø = 90 degreeorø= 45 degree
Question 10
1 / -0

When a projectile is thrown up at an angle θ to the ground, the time taken by it to rise and to fall are related as

A
time of rise can be less than or equal to time of fall

B
they are equal

C
time of rise < time of fall

D
time of rise > time of fall

Solution

The time of fall or rise for a projectile depends upon its vertical component of initial velocity and the vertical acceleration. As the acceleration does not change and the motion of path is identical for the rise phase and the fall phase, we can easily deduce that time taken is also the same.

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Motion in a Plane Test 4

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Motion in a Plane Test 4

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Question 1

A bullet fired from a gun.

A kicked football.

Taking off of an aircraft.

A javelin thrown by an athlete.

Solution

Question 2

they get hit at the same time.

ship μ2

need more information about the trajectories.

ship μ1

Solution

Question 3

the object moves straight horizontally.

to a man standing near the track, path of the object will be a part of parabola.

the object falls down vertically.

the object will follow an elliptical path

Solution

Question 4

Its velocity is zero but its acceleration is nonzero

Its velocity is nonzero but its acceleration is zero

Its velocity and acceleration are both zero

Its velocity is perpendicular to its acceleration

Solution

Question 5

4

3

2

1

Solution

Question 6

5 m/s

8.7 m/s

10 mis

0

Solution

Question 7

Horizontal component of acceleration

Vertical component of acceleration

Vertical component of velocity

Horizontal component of velocity

Solution

Question 8

minimum

g

maximum

zero

Solution

Question 9

450

900

600

300

Solution

Question 10

time of rise can be less than or equal to time of fall

they are equal

time of rise < time of fall

time of rise > time of fall

Solution

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45⁰

90⁰

60⁰

30⁰