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Work, Energy and Power Test - 12

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Work, Energy and Power Test - 12
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  • Question 1
    1 / -0

    The scalar product of two vectors A and B is

    Solution

    Explanation:Scalar product means dot product and dot product of 2 vectors gives a scalar  , example  dot product of force and displacement gives work which is scalar

  • Question 2
    1 / -0

    Mass and energy are equivalent and are related by

    Solution

    Explanation:Mass–Energy equivalence states that anything having mass has an equivalent amount of energy and vice versa, with these fundamental quantities directly relating to one another by Einstein's theory of special relativity. It shows that matter (as mass) and energy can be converted into each other according to the famous equation E=mc2

  • Question 3
    1 / -0

    A railway porter is holding a weight of 100 kgs on his head and is standing still. What is the work done by him?

    Solution

    Explanation:W = Force x displacement in the direction of forceWork done will be zero because porter is stationary (i.e. displacement is zero)

  • Question 4
    1 / -0

    A person trying to lose weight (dieter) lifts a 10 kg mass, one thousand times, to a height of 0.5 m each time. Assume that the potential energy lost each time she lowers the mass is dissipated. How much work does she do against the gravitational force?

    Solution

    Explanation:Work done by force applied against gravity for one lift will be

    W = Fs = mgh = 10 x 9.8 x 0.5 = 49J

    So work done for 1000 lifts = 49 x 1000 = 49000 J

  • Question 5
    1 / -0

    A12-pack of Omni-Cola (mass 4.30 kg) is initially at rest on a horizontal floor. It is then pushed in a straight line for 1.20 m by a trained dog that exerts a horizontal force with magnitude 36.0 N. Use the work–energy theorem to find the final speed of the 12-pack if there is no friction between the 12-pack and the floor

    Solution

    Explanation:

    from work–energy theorem

    change in kinetic energy = work done

    ΔK = W

    Kf - Ki = Fs

    1/2mv2 - 0 = Fs

    m = 4.30 kg, s = 1.2m, F = 36N

    vf = vm/s , vi = 0

  • Question 6
    1 / -0

    The work done by the force is defined to be

    Solution

    Explanation:Work done is given by 

    W = (Fcosθ)d

    here Fcosθ is the component of applied force  in direction of displacement and d is magnitude of displacement.

  • Question 7
    1 / -0

    Power is defined as

    Solution

    Explanation:Power is the rate of doing work. It is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. In the SI system, the unit of power is the joule per second (J/s), known as the watt.The integral of power over time defines the work performed.

  • Question 8
    1 / -0

    A weight of 20kg falls from a height of 10 m. The work done by the gravitational force is (Take g = 10 mms-2)

    Solution

  • Question 9
    1 / -0

    S.I unit of power is

    Solution

    Explanation:The SI unit of power, equivalent to one joule per second, corresponding to the rate of consumption of energy (Work done).

  • Question 10
    1 / -0

    In which case is the work done zero?

    Solution

    Explanation:Work done is given as

    W = Fdcosθ

    Here θ is the angle between F and d  if both are perpendicular  then θ = 90 degree so cosθ = 0  and thus work done is 0 .

  • Question 11
    1 / -0

    Which of the following laws used to solve problems in collisions?

    Solution

    Explanation:If external force is absent then linear momentum of system remains conserved. In collision force of impact due to collision is internal and very large.

  • Question 12
    1 / -0

    A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min. If the tank is 40 m above the ground, and the efficiency of the pump is 30%,  how much electric power is consumed by the pump?

    Solution

  • Question 13
    1 / -0

    The S.I unit of force is

    Solution

    Explanation:In International System of Units (SI) the newton is the unit for force. It is equal to the amount of net force required to accelerate a mass of one kilogram at a rate of 1 m/sec2 in direction of the applied force. It is named after Isaac Newton in recognition of his work on classical mechanics, specifically Newton's second law of motion.

    1N=1Kgm/sec2

    Dyne is a  cgs unit of force. One dyne is equal to 10−5 N

  • Question 14
    1 / -0

    In an elastic collision

    Solution

    Explanation:kinetic energy is transferred to other forms of energy—such as thermal energy, potential energy, and sound—during the collision process. After collision if recovery of kinetic energy is 100% then it is called elastic collision.So that in an elastic collision the total kinetic energy of the system is the same after the collision as before.

  • Question 15
    1 / -0

    Work-energy theorem does not give information on

    Solution

    Explanation:According to work energy theorem :Net work done on a body equals change in its kinetic energySo it does not give any information about time dependence. 

  • Question 16
    1 / -0

    In an inelastic collision

    Solution

    Explanation:kinetic energy is transferred to other forms of energy—such as thermal energy, potential energy, and sound—during the collision process. After collision if recovery of kinetic energy is less than % then it is called inelastic collision i.e.. some part of kinetic energy is not recover. So that in an inelastic collision the total kinetic energy after the collision is less than before the collision

  • Question 17
    1 / -0

    Physically, the notion of potential energy is applicable only to

    Solution

    Explanation:Potential energy is the stored energy of an object. It is the energy by virtue of an object's position relative to other objects. Potential energy is often associated with restoring forces such as a spring or the force of gravity. It is applicable only for conservative forces.

  • Question 18
    1 / -0

    In a completely inelastic collision

    Solution

    Explanation:For perfectly Inelastic collision coefficient of restitution  is zero.coefficient of restitution e= relative velocity of separation / relative velocity of approache = 0so that relative velocity of separation will be zero means the colliding bodies stick together and move as one body after the collision

  • Question 19
    1 / -0

    A bolt of mass 0.3 kg falls from the ceiling of an elevator moving down with an uniform speed of 7 m/s. It hits the floor of the elevator (length of the elevator = 3 m) and does not rebound. What is the heat produced by the impact?

    Solution

    Explanation:

    Whole of the potential energy of bolt converted in to heat energy 

    heat produced by the impact = mgh =0.3×9.8×3=8.82J

  • Question 20
    1 / -0

    The work done by a conservative force

    Solution

    Explanation:A force is said to be conservative if work done by this force is independent of path and is dependent only on end points .

  • Question 21
    1 / -0

    In which of the following cases is the work done positive?

    Solution

    Explanation:Work done is positive when force applied and displacement are in same direction.

    W=F .s =Fscosθ

    in this case angle between force and displacement is zero (i.e. cosθ=1) so that work done is positive.

  • Question 22
    1 / -0

    The total mechanical energy of a system is conserved if the

    Solution

    Explanation:Mechanical energy is the sum of kinetic and potential energy in an object that is used to do work. In other words, it is energy in an object due to its motion or position, or both. In case of conservative forces total mechanical energy remains conserved because potential energy applicable only for conservative forces.

  • Question 23
    1 / -0

    The casing of a rocket in flight burns up due to friction. At whose expense is the heat energy required for burning obtained?

    Solution

    Explanation:Heat energy required for burning of casing of rocket comes from the rocket itself. As a result of work done against friction the kinetic energy of rocket continuously deceases and this work against friction reappears as heat energy. This results in reduction of the mass of the rocket.

  • Question 24
    1 / -0

    A tandem (two-person) bicycle team must overcome a force of 165 N to maintain a speed of 9.00 m/s. Find the power required per rider, assuming that each contributes equally.

    Solution

    Explanation:

    Total power required to overcome a force of 165 N and to maintain a speed of 9.00 m/s

    F = 165N

    v = 9m/s

    P = Fv = 165 x 9 = 1485 W

    if each rider contribute equal power, then power required per rider will be P/2 = 1485/2 = 742.5W

     

  • Question 25
    1 / -0

    For a ball dropped from a tower of height h the total mechanical energy is

    Solution

    Explanation:mechanical energy = sum of potential and kinetic energiesa falling ball will have both these energies in between topmost and bottomost points of its motion so mechanical energy is the sum of potential and kinetic energies.

  • Question 26
    1 / -0

    A trolley of mass 200 kg moves with a uniform speed of 36 km/h on a frictionless track. A child of mass 20 kg runs on the trolley from one end to the other (10 m away) with a speed of 4 ms−1 relative to the trolley in a direction opposite to the its motion, and jumps out of the trolley. How much has the trolley moved from the time the child begins to run?

    Solution

    Explanation:
    Mass of troly M = 200Kg
    mass of child m = 20Kg
    speed of trolley v = 36Km/hr=36 x 5/18 = 10m/s
    Let v' be the final velocity of the trolley with respect to the ground.
    Final velocity of the boy with respect to the ground = v,−4
    from conservation of linear momentum

    Time taken by the boy to run t = 10/4 = 2.5 sec
    Distance moved by the trolley = vt = 10.36 x 2.5 = 25.9 m

  • Question 27
    1 / -0

    A 50.0-kg marathon runner runs up the stairs to the top of a 443-m-tall Tower. To lift herself to the top in 15.0 minutes, what must be her average power output?

    Solution

    https://cdn3.edurev.in/ApplicationImages/Temp/485050_ee1debcc-c597-4ec1-9241-25680719afee_lg.PNG

  • Question 28
    1 / -0

    In which of the following cases is the work done positive?

    Solution

    Explanation:When a body is moving on a rough horizontal surface then their will be 2 forces acting on the body   1. Applied force ( in the direction of motion) 2. friction ( opposite to direction of motion)As applied force is in same direction as displacement so work done will be positive.

  • Question 29
    1 / -0

    The launching mechanism of a toy gun consists of a spring of unknown spring constant. When the spring is compressed 0.120 m, the gun, when fired vertically, is able to launch a 35.0-g projectile to a maximum height of 20.0 m above the position of the projectile before firing. Neglecting all resistive forces, determine the spring constant.

    Solution

    Explanation:

    Potential energy of spring converted in to potential energy

  • Question 30
    1 / -0

    If F is a force and d is the displacement in the direction of force then the work done by the force is given by

    Solution

    Explanation:Work done = force in the direction of displacement multiplied by displacement

    W=F.d

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