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Gravitation Test - 6

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Gravitation Test - 6
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  • Question 1
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    If a person can jump on the earth's surface  upto a height of 2m, has jump on a satellite where acceleration due to gravity is 1.96m/s2, will be-

  • Question 2
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    The mass of a planet is 5 times the mass of the earth but its diameter is the same as that of the earth. How much work is done in lifting a stone of mass 3 kg through a distance of 1 m on this planet?

    Solution

    We know that g∝Mp​, Where Mp​ is mass of planet. 

    So,  gp​=5×10=50 m/s2

    So work done in lifting a 3 kg stone by 1m =50×3×1=150J

  • Question 3
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    The earth is an approximate sphere. If the interior contained matter which is not of the same density everywhere, then on the surface of the earth, the acceleration due to gravity :

    Solution

    There's no such thing as zero gravity. Weightlessness and zero gravity are two different things. The earth's gravity keeps the moon in orbit. And astronauts are generally much closer to earth than the moon is, which means that the earth's pull on them has to be much stronger.

  • Question 4
    1 / -0

    The value of acceleration due to gravity on earth is.

    Solution

    The value of acceleration due to gravity on earth is g=9.8ms−2.

    Hence,

    option A is correct answer.

  • Question 5
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    The earth's gravitational force at someplace in space causes an acceleration of 7m/s2 in a 1kg mass.What will be the acceleration of a 5kg mass at the same place?

    Solution

    The acceleration due to gravity does not vary with the change in the mass of the object as it is a dimensionless quantity representing the amount of matter in a particle or object.
    Therefore, the acceleration of a 5 kg mass at the same place is 7m/s2.

  • Question 6
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    A ball is thrown vertically upwards. The acceleration due to gravity:

    Solution

    A ball is thrown vertically upwards. The acceleration due to gravity is in the downward direction.

  • Question 7
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    Radius of planet A is twice that of planet B and the dencity of A is one third that of B . The ratio of the acceleration due to gravity at the surface of A to that at the surface of B is.-

    Solution

    Given that,

    Radius of planet A is twice that of planet B and the density of A is one-third that of B.

    so, the radius is

    The ratio of the acceleration due to gravity at the surface of A to that at the surface of B is

  • Question 8
    1 / -0

    The diameters of two planets are in the ratio 4:1 and their mean densities in the ratio 1:2. The acceleration due to gravity on the planets will be in ratio

    Solution

    Acceleration due to gravity is given by the equation g = GM/R2 (at surface)

    so g1 = GM1 /R12 and g2 = GM2 /R22 (gravities at planets 1 and 2)

    also M1/M2 = V1p1/V2p2 = R13 p1/ R23 p2 (as V = 4/3 π r3

    Therefore, g1/g2 = R1 ρ1 / R2 ρ2 = (4/1) x (1/2) = 2:1

  • Question 9
    1 / -0

    Force of gravity is least at

  • Question 10
    1 / -0

    Two balls are dropped from the same height from places A and B. The body at B takes two seconds less to reach the ground at B strikes the ground with a velocity greater than at A by 10m/s. The product of the acceleration due to gravity at  the two places A and B is:

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