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IMO - Mock Test - 4

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IMO - Mock Test - 4
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  • Question 1
    1 / -0

    How many consonants are there in the given arrangement, each of which is immediately preceded as well as immediately followed by a vowel?

    D, A, F, Q, R, R, Q, F, H, X, U, O, E, F, A, G, K, L, D, V, U, E, G

    Solution

    D, A, F, Q, R, R, Q, F, H, X, U, O, E, F, A, G, K, L, D, V, U, E, G
    There is only one consonant in the given arrangement which is immediately preceded as well as immediately followed by a vowel.

     

  • Question 2
    1 / -0

    What will come in place of the question mark?

    AK, DN, GQ, ?

    Solution

    A, K = 1, 11; 11 - 1 = 10
    D, N = 4, 14; 14 - 4 = 10
    G, Q = 7, 17; 17 - 7 = 10
    Pattern of the series of first numbers = 1, 4, 7, 10
    So, the next letter will be the 10th letter of the English alphabet, which is J.
    The next letter will be the (10 + 10)th = 20th letter of the alphabet, which is T.
    Thus, the correct answer is option 3.

     

  • Question 3
    1 / -0

    If the word ARROW is coded as CRTOY, then how will the word CONTAIN be coded in the same code-language?

    Solution

    A + 2 = C

    R + 0 = R

    R + 2 = T

    O + 0 = O

    W + 2 = Y

    Similarly,
    C + 2 = E
    O + 0 = O
    N + 2 = P
    T + 0 = T
    A + 2 = C
    I + 0 = I
    N + 2 = P

     

  • Question 4
    1 / -0

    Which of the following series does not follow any pattern?

    Solution

    Difference between 4 and 11 is 7.

    Difference between 11 and 19 is 8.
    So, this series does not follow any pattern..

     

  • Question 5
    1 / -0

    What will be the next number on the scale if the readings are as follow?

    5.8, 6.2, 6.6, __

    Solution

    In this, the decimals are increasing by the number 0.4, so 6.6 + 0.4 = 7.0 or 7.

     

  • Question 6
    1 / -0

    Arrange the given words in the sequence in which they occur in the dictionary and then choose the correct sequence.

    1. Adopt
    2. Admire
    3. Advertise
    4. Admission
    5. Admit

    Solution

    The correct order is: Admire, Admission, Admit, Adopt, Advertise (2, 4, 5, 1, 3).

     

  • Question 7
    1 / -0

    Find the next number in the series.

    59.6, 60.5, 61.4, 62.3, ____

    Solution

    Each number increases by 0.9.

     

  • Question 8
    1 / -0

    If THINK is coded as UJJPL, then how will WRITE be coded?

    Solution

    THINK is coded as follows:

    T + 1 = U
    H + 2 = J
    I + 1 = J
    N + 2 = P
    K + 1 = L
    Similarly,

    W + 1 = X

    R + 2 = T

    I + 1 = J

    T + 2 = V

    E + 1 = F

     

  • Question 9
    1 / -0

    Choose the odd one out.

    (1) ipod
    (2) ipad
    (3) iphone
    (4) iball

    Solution

    iball is the name of the company, rest all are the apple products.

     

  • Question 10
    1 / -0

    Find the ratio of 30 days to 30 hours.

    Solution

    1 day = 24 hours
    So, 30 days = 30 x 24 hours
    Desired ratio = (30 x 24) : 30
    Thus, desired ratio = 24 : 1

     

  • Question 11
    1 / -0

    The marks of eight students in Science exam for Class 10, out of 50 total marks, are as follows:

    44, 38, 22, 44, 33, 28, 49, 20

    Find the range of the data.

    Solution

    Range = maximum value – minimum value = 49 – 20 = 29

     

  • Question 12
    1 / -0

    Write the equation for the following case:

    Rahul's age is 35 years old. He is 3 years older than two times the age of his son named Rohit. (Take Rohit's age to be X years.)

    Solution

    Rohit's age = X years
    So, Rahul's age = (3 + 2X) years = 35 years
    Or 3 + 2X = 35

     

  • Question 13
    1 / -0

    Find the value of polynomial 8x – 2x2 + 3, if x = 2.

    Solution

    Putting the value of x = 2, we get
    8x – 2x2 + 3 = 8 x 2 – 2(4) + 3 = 16 – 8 + 3 = 11

     

  • Question 14
    1 / -0

    Michael is driving a car at a speed of 210 km/hr. After every lap, he increases the speed by 5 km/hr. What will be his speed after 10 laps?

    Solution

    Initially, speed of Michael = 210 km/hr
    As after every lap, the speed is increased by 5 km/hr.
    Speed of Michael after one lap = (210 + 5) km/hr = 215 km/hr
    Speed of Michael after two laps = (215 + 5) km/hr = 220 km/hr
    Speed of Michael after three laps = (220 + 5) km/hr = 225 km/hr
    Speed of Michael after four laps = (225 + 5) km/hr = 230 km/hr
    Speed of Michael after five laps = (230 + 5) km/hr = 235 km/hr
    Speed of Michael after six laps = (235 + 5) km/hr = 240 km/hr
    Speed of Michael after seven laps = (240 + 5)km/hr = 245 km/hr
    Speed of Michael after eight laps = (245 + 5) km/hr = 250 km/hr
    Speed of Michael after nine laps = (250 + 5) km/hr = 255 km/hr
    Speed of Michael after ten laps = (255 + 5) km/hr = 260 km/hr
    So, the speed of Michael after 10 laps will be 260 km/hr.

     

  • Question 15
    1 / -0

    What is the value of (7.4 x 6.9 + 15.7)?

    Solution

    Multiply: 7.4 x 6.9 = 51.06

    Add : 51.06 + 15.7 = 66.76

     

  • Question 16
    1 / -0

    What is the length of a rectangular field whose perimeter is 45 m and breadth is 9.5 m?

    Solution

    Perimeter of a rectangle = 2(l + b)

    Perimeter of the rectangular field = 45 m

    Breadth = 9.5 m

    Perimeter of a rectangle = 2(l + b)

    45 m = 2(l + 9.5)

    (45/2 - 9.5) m = l

    l = 13 m

     

  • Question 17
    1 / -0

    Solve 4/160 + 0.035.

    Solution

    Simplify 4/160 to 1/40.

    1/40 = 0.025

    0.025 + 0.035 = 0.06

     

  • Question 18
    1 / -0

    Perimeter of a rectangle is 40 cm. If length of the rectangle is 14 cm, then what will be the width of the rectangle?

    Solution

    We know that, perimeter = 40 cm

    So, 2(l + b) = 40 cm

    We know that, length = 14 cm

    Putting this value

    2(14 + b) = 40 cm

    b = 6 cm

     

  • Question 19
    1 / -0

    Find the perimeter of a rectangular plot if its area is 60,000 mand breadth is 200 m.

    Solution

    Area of rectangular plot = Length x Breadth

    60,000 m= 200 m x Length

    Length = 300 m

    Perimeter of the plot = 2(Length + Breadth)

    = 2(200 + 300) m

    = 2(500) m

    = 1000 m

     

  • Question 20
    1 / -0

    Which angle will be the largest in a ΔABC, if AB is 5 cm, BC is 12 cm, and CA is 13 cm?

    Solution

    The angle opposite to the longest side in a triangle is the largest angle, which in this case is angle B, which is opposite to the longest side CA.

     

  • Question 21
    1 / -0

    Ram left for tuition at 4:15 p.m. and returned home at 6:55 p.m. For how long was Ram gone?

    Solution

    Ram went to tuition at 4:15 p.m.

    Ram returned home at 6:55 p.m.

    Ram was gone for 2 hours and 40 minutes.

     

  • Question 22
    1 / -0

    In how much time will Bob eat the whole cake, if he can eat one quarter of the cake in 13 minutes?

    Solution

    Bob eats 1/4 of the cake in 13 minutes.
    The whole cake will take him 13 minutes x 4 = 52 minutes.

     

  • Question 23
    1 / -0

    Ram had 400 biscuits in a jar. He sorted the biscuits into 20 different stacks. Each stack had the same number of biscuits. How many biscuits were there in each stack?

    Solution

    Total number of biscuits = 400
    Number of stacks = 20
    Number of biscuits in each stack = 400/20 = 20

     

  • Question 24
    1 / -0

    The temperature of a town is measured - 2°C on Monday, and it is going to get warmer each day by 3°C. What will be temperature of the town on Saturday?

    Solution

    Number of days from Monday to Saturday = 5

    Total increase in temperature over 5 days = 3oC × 5 = 15oC

    If on Monday, the temperature is - 2oC, then on Saturday, the temperature will be = - (2 + 15)oC = 13oC

     

  • Question 25
    1 / -0

    Jim has two pieces of cloth. One piece is 48 cm long and the other piece is 66 cm long. She wants to cut strips as long as possible from both the pieces of cloth, such that the strips are of equal length and no cloth is wasted. What should be the length of each strip?

    Solution

    To find the actual size of a strip, we need to find HCF of both the numbers.
    So, the prime factorisation of 48 is 2 × 2 × 2 × 2 × 3.
    The prime factorisation of 66 is 2 × 3 × 11.
    So, HCF = 6
    Thus, length of a strip = 6 cm

     

  • Question 26
    1 / -0

    How many letters will Ankit deliver in 97 days, if he delivers 2,569 letters in one day?

    Solution

    2569
    x 97
    ------------
    17983

    + 231210
    ------------------
    2,49,193
    ------------------

     

  • Question 27
    1 / -0

    Jack had 630 apples in a bag. He sorted the apples in groups of 25. Each group had the same number of apples. How many apples were left ungrouped?

    Solution

    Total number of apples = 630
    Number of apples in each group = 25
    Number of groups = 630/25 = 25 groups + 5 apples
    Remainder = 5

     

  • Question 28
    1 / -0

    On Monday, Gagan went to the market and bought 3 pens and 4 erasers and paid Rs. 33 to the shopkeeper. On the next day, he bought 6 pens and 3 erasers and paid Rs. 36. What was the cost of a pen?

    Solution

    According to question:

    Let the cost of one pen be Rs. p.

    And the cost of one eraser be Rs. e.

    Therefore,

    3p + 4e = 33--- eq(1)

    and, 6p + 3e = 36---- eq(2)

    Now, by using the elimination method,

    Eq(1) becomes-

    (3p + 4e = 33 ) x 2

    6p + 8e = 66--- (3)

    Subtract eq(2) from eq(3):

    6p + 8e = 66

    6p + 3e = 36

    --------------

    5e = 30

    e = 30/5

    e = 6

    Therefore, put e = 6 in eq. (1)

    3p + 4(6) = 33

    3p = 33 - 24

    3p = 9

    p = 3

    Therefore, cost of one pen = Rs. 3

     

  • Question 29
    1 / -0

    Danny bought 7 bags of apples. The red apples came in bags of 3 and the green apples came in bags of 2. Danny bought a total of 19 apples. How many bags of each type of apples did he buy?

    Solution

    Let the number of bags of red apples bought by Danny = a
    Number of bags of green apples = 7 - a
    So, 3a + 2(7 - a) = 19
    Or, a = 5
    7 - a = 2
    Thus, he bought 5 bags of red apples and 2 bags of green apples.

     

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