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Playing with Numbers Test - 6

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Playing with Numbers Test - 6
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Five bells toll together at an instant. After that, they separately toll at intervals of 3, 5, 7, 8 and 10 seconds. After how long will they again toll together?

    Solution

    Required interval is the least common factor of 3, 5, 7, 8 and 10.
    LCM of 3, 5, 7, 8 and 10 = 840 seconds

    Now, converting 840 seconds into minutes, we get: 840/60 = 14 minutes
    Hence, they will again toll together after 14 minutes.

     

  • Question 2
    1 / -0

    State 'T' for true and 'F' for false.

    (i) The sum of three odd numbers is even.
    (ii) Prime numbers do not have any factor.
    (iii) The product of two even numbers is always even.
    (iv) All prime numbers are odd.

    (i) (ii) (iii) (iv)
    (A) T F T F
    (B) F T T F
    (C) F F T F
    (D) T T F T

    Solution

    1. The sum of three odd numbers is even. False. Sum of three odd numbers is always odd.

    2. Prime numbers do not have any factor. False. A prime number has two factors, one and the number itself.

    3. The product of two even numbers is always even. True

    4. All prime numbers are odd. False. 2 is an even prime number.

     

  • Question 3
    1 / -0

    Read the following statements and mark the correct option accordingly.

    Statement-1: A number for which the sum of its factors other than the number is equal to that number itself is called a perfect number.
    Statement-2: The product of three consecutive numbers will always be a multiple of 6.

    Solution

    Statement-1 is true.

    A number for which the sum of all its factors is equal to twice the number is called a perfect number.
    Or in other words, a number for which the sum of its factors other than the number itself is equal to that number itself is called a perfect number.

    For example,

    Factors of 28: 1, 2, 4, 7, 14, 28
    Sum of the factors other than 28 = 1 + 2 + 4 + 7 + 14 = 28

    Statement-2 is true.

    The product of three consecutive numbers will always be a multiple of 6.
    For example: 7 x 8 x 9 = 504; and 504 is a multiple of 6.

     

  • Question 4
    1 / -0

    Fill in the blanks.

    (i) LCM of two co-prime numbers will be (A) of the numbers.
    (ii) HCF of two consecutive even numbers (B) .
    (iii) If a number is divisible by 6, then it must also be divisible by 2 and (C) .

    Solution

    (i) In case the two numbers are co-prime, their LCM will be the product of the numbers.
    (ii) Let two consecutive numbers be 2n and 2n + 2. So, both have highest common factor 2, so HCF of two consecutive even numbers is 2.
    (iii) If a number is divisible by 6, then it must also be divisible by 2 and 3.

     

  • Question 5
    1 / -0

    Find the value of x + y + z, if 821x is divisible by 8, 992y is divisible by 12 and 446z is divisible by 6.

    Solution

    If 821x is divisible by 8,
    then, the only possible value of x is 6, when last three digits of 821x is divisible by 8.
    So, x = 6

    992y is divisible by 12,
    9 + 9 + 2 + y = 20 + y is divisible by 12
    y = 4

    446z is divisible by 6,
    4 + 4 + 6 + z = 14 + z is divisible by 6
    z = 4
    x + y + z = 6 + 4 + 4 = 14

     

  • Question 6
    1 / -0

    Match the following.

    Column I Column II
    (i) 46 (a) Multiple of 11
    (ii) 121 (b) Multiple of 7
    (iii) 49 (c) Multiple of 9
    (iv) 81 (d) Multiple of 2
    Solution

    46 is a multiple of 2.
    121 is a multiple of 11.
    49 is a multiple of 7.
    81 is a multiple of 9.

     

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