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Algebraic Expressions & Identities Test - 2

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Algebraic Expressions & Identities Test - 2
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  • Question 1
    1 / -0

    Sahil works as a postman. He gets paid for his work based on a formula: 3l(4l - 5) + 3, where l is the number of letters he delivers. If he delivers 5 letters on Monday, then how much (in Rs.) will he get paid for it?

    Solution

    The formula used to calculate his pay is: 3l(4l - 5) + 3 or (12l2 - 15l + 3)
    Now, he delivers 5 letters.

    Put l = 5 in the formula:
    12(5)- 15(5) + 3

    = 12(25) - 75 + 3
    = 300 - 75 + 3
    = Rs. 228

     

  • Question 2
    1 / -0

    Katie makes two rectangular boxes. One box has a length, breadth and height of 5a, 3a2 and 7a4, respectively, while the other box has a length, breadth and height of xy, 2x2y and 2xy2, respectively. Now, she joins them together to make a new rectangular box. Find the volume of the new box.

    Solution

    Volume of new box = Volume of first box + Volume of second box
    Now, volume of first box = 5a × 3a× 7a= 5 x 3 x 7 x a x a2 x a4 = 105 a7 ... (1)

    Volume of second box = xy × 2x2y × 2xy= 2 × 2 × xy × x2y × xy2
    = 4x4y... (2)

    Volume of new box = (1) + (2)
    = 105a+ 4x4y4

     

  • Question 3
    1 / -0

    Sumit opens a new account in ABS bank. In the first month, he deposits amount p in his account. In the second month, he deposits amount p2 in his account. In the third month, he deposits thrice the amount deposited by him in the first month. In the fourth month, he deposits an amount equal to the product of amounts deposited by him in the last three months. Find the amount deposited by him in the fourth month.

    Solution

    Amount deposited in the first month = p
    Amount deposited in the second month = p2

    Amount deposited in the third month = 3p
    Amount deposited in the fourth month = (p × p2 × 3p)

    = 3p1 + 2 + 1
    = 3p4

     

  • Question 4
    1 / -0

    A tortoise and a rabbit were having a race. For every (k(k - j) + j(j - h)) kilometres covered by the tortoise, the rabbit covered three times that distance and an extra h(h - k) kilometres. Find the distance travelled by the rabbit for every (k(k - j) + j(j - h)) kilometres covered by the tortoise.

    Solution

    Required distance = [3 × {(k(k - j) + j(j - h))} + h(h - k)]
    = [3 × {(k2 - kj + j2 - jh)} + h2 - hk)]

    = [3k- 3kj + 3j2 - 3jh + h2 - hk]
    = (3k+ 3j+ h- 3kj - 3jh - hk) kilometres

     

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