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Squares And Square Roots Test - 7

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Squares And Square Roots Test - 7
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  • Question 1
    1 / -0
    Find the value of x in the given equation.


    Solution


    Squaring both sides, we get







    Now, again squaring both sides, we get

    x = 65,536
  • Question 2
    1 / -0
    What is the simplified form of ?
    Solution


    =

    =

    =

    =

    =
  • Question 3
    1 / -0
    = x, then the value of x is
    Solution
    = x

    0.09 + 0.25 = x2

    x =
  • Question 4
    1 / -0
    If , then x is equal to
    Solution












  • Question 5
    1 / -0
    Which among the following can definitely not be a square number?
    Solution
    Square numbers always end with digits 0, 1, 4, 5, 6, 9.
    So, from looking at the units digits in the given options, we can say that only 48542 can definitely not be a square number.
  • Question 6
    1 / -0
    A Google employee's age is multiplies by times itself and then 10 is subtracted from the product obtained. If the final result is 4490, then the age is________.
    Solution
    Suppose 'a' be the age of Google company employee's
    Then according to the question,










  • Question 7
    1 / -0
    The product of two numbers is 4,55,625. If one number is 9 times the other, find the numbers.
    Solution
    Let the first number be x; then the other number will be 9x.
    So, x(9x) = 4,55,625
    9x2 = 4,55,625
    x2 = 50,625
    x =
    x = 225
    Hence, the numbers are 225 and 2025.
  • Question 8
    1 / -0
    What is the smallest number by which 7776 must be divided to get a perfect square?
    Solution
    7776 =
    Since two digits (2 and 3) are not in pairs, the smallest number by which 7776 must be divided to get a perfect square is 2 x 3 = 6
  • Question 9
    1 / -0
    What is the square root of 10.24?
    Solution
    We will find the square root of 10.24 by long division method.



    Square root of 10.24 = 3.2
  • Question 10
    1 / -0
    What is the value of 1002 - 992 by observing the given pattern?

    22 - 12 = 2 + 1
    32 - 22 = 3 + 2
    Solution
    22 - 12 = 2 + 1
    32 - 22 = 3 + 2
    1002 - 992 = 100 + 99 = 199
  • Question 11
    1 / -0
    The ratio of the marks of four students is 2 : 3 : 5 : 6, such that the sum of their squares is 10,656. Find the marks of the four students, respectively.
    Solution
    The given ratio is 2 : 3 : 5 : 6.
    So, let the marks be 2x, 3x, 5x and 6x.
    (2x)2 + (3x)2 + (5x)2 + (6x)2 = 10,656
    4x2 + 9x2 + 25x2 + 36x2 = 10,656
    74x2 = 10,656
    x2 = 10656 ÷ 174
    x2 = 144
    x = 12
    The marks of the students are 24, 36, 60 and 72, respectively.
  • Question 12
    1 / -0
    The value ofis ______.
    Solution


    = 1.34 (approx.)
  • Question 13
    1 / -0
    What do we need to subtract from 99,999 to make it a perfect square?
    Solution


    We need to subtract 143 from 99,999 to make it a perfect square.
    99,999 - 143 = 99,856, which is the square of 316.
  • Question 14
    1 / -0
    Find the value of .
    Solution

  • Question 15
    1 / -0
    Find the respective square roots of the following numbers up to two decimal places:

    2.8 and 3.6
    Solution
  • Question 16
    1 / -0
    What will be the length of a square field if its area is given as ?
    Solution
    Let the length of the field be x.
    Area of the field =
    =
    =

    x = 4.5 m (approx.)
  • Question 17
    1 / -0
    The total fee of all students in a hostel is Rs. 48,672. Each student's fee is one half of the number of students. What is the total number of students in the hostel?
    Solution
    Let the total number of students be x.
    Each student's fee is half the number of students.
    According to the question,

    x2 = 97344
    x = 312
    So, the number of students in the hostel is 312.
  • Question 18
    1 / -0
    In a school assembly, the students are arranged in rows to form a perfect square; but in doing so, 25 students are left out. If the total number students is 1181, find the number of students in each row.
    Solution
    Total students who form a square:
    1181 - 25 = 1156
    Let the number of rows be x.
    So, x × x = 1156
    x2 = 1156
    x = 34
    Number of students in each row = 34
  • Question 19
    1 / -0
    A trust collects as many paise from each member of the trust as the number of members. If the total collection is Rs. 29.16, then what is the number of members in the trust?
    Solution
    Let the number of members in the trust be x.
    Then, amount received from each member = x paise
    Now, total collection = x2 paise
    x2 = (29.16 × 100)
    x =
    x = 54
    So, the number of members in the trust is 54.
  • Question 20
    1 / -0
    A charitable trust wants to fence a square plot whose area is given as 6448.09 sq. m. What is the side of the plot?
    Solution
    Side of the plot = = 80.3 m
  • Question 21
    1 / -0
    Find the value of .
    Solution


    =

    =

    =

    =

    = 5 - 0.16

    = 4.84
  • Question 22
    1 / -0
    Find the values of P, Q, R and S.

    i) The square root of 1002001 is P .
    ii) The square root of 2450.25 is Q .
    iii) The square root of 8445.61 is R .
    iv) The square of 58 is S .
    Solution
    For P: = 1001

    For Q: = 49.5

    For R: = 91.9

    For S: Square of 58 = 3364
  • Question 23
    1 / -0
    Which of the following statements is/are true?
    Solution
    (1) A number having 2, 3, 7, or 8 at the ones place is never a perfect square; in other words, no square number ends in 2, 3, 7, or 8.
    Example: None of the numbers 152, 7693, 14357, 88888 and 798328 is a perfect square because the unit digit of each number is 2, 3, 7, or 8.

    (2) The square of a natural number other than 1 is either a multiple of 4 or exceeds a multiple of 4 by 1.
    Example: 67, 146 and 10003 are not perfect squares as they leave respectively the remainders of 3, 2 and 3 when divided by 4.

    (3) Squares of even numbers are always even numbers and square of odd numbers are always odd.
    Example: 122 = 12 × 12 = 144 (both are even numbers)
    192 = 19 × 19 = 361 (both are odd numbers)
  • Question 24
    1 / -0
    Consider the following statements and mark the correct option accordingly.

    Statement I: The unit digit of the square of a natural number is the unit digit of the square of the digit at the ones place of the given natural number.
    Statement II: The square of a number n is equal to the sum of first n odd natural numbers.
    Solution
    Statement I: The unit digit of the square of a natural number is the unit digit of the square of the digit at the ones place of the given natural number.
    For example, let's find out the unit digit of the square of (i) 146 and (ii) 321.
    Solution:
    (i) Since the unit digit of 62 = 36 is 6, the unit digit of the square of 146 is 6.
    (ii) Since the unit digit of 12 = 1 is 1, the unit digit of the square of 321 is 1.

    Statement II: The square of a number n is equal to the sum of first n odd natural numbers.
    12 = 1
    22 = 1 + 3
    33 = 1 + 3 + 5
    42 = 1 + 3 + 5 + 7, and so on.
    So, both statements are true.
  • Question 25
    1 / -0
    State true (T) or false (F) for the following statements.

    i) If a number has 3 or 7 at the ones place, then its square ends in 9.
    ii) 33.52 lies between 500 and 1000.
    iii) If a number has 5 at the ones place, then its square ends in 5.
    iv) The area of a square, whose side is 8 cm, is 64 cm2.
    Solution
    i) If a number has 3 or 7 at the ones place, then its square ends in 9.
    E.g. 332 = 1089, 172 = 289, 132 = 169
    So, statement (i) is true.
    ii) 33.52 = 1122.25; it does not lie between 500 and 1000. So, statement (ii) is false.
    iii) If a number has 5 in the ones place, then its square ends in 5.
    E.g. 52 = 25, 152 = 225, 252 = 625
    So, statement (iii) is true.
    iv) The area of a square, whose side is 8 cm, is 64 cm2.
    8 × 8 =
    So, statement (iv) is true.
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