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Structure of Atom Test - 2

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Structure of Atom Test - 2
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  • Question 1
    1 / -0

    Which of the following sets of quantum numbers is correct for an electron in a 4f orbital?

    Solution

    The following set of quantum numbers is possible for an electron in a 4f orbital:
    n = 4
    l = 3
    m = -3, -2, -1, 0, 1, 2, 3
    s = +1/2 or -1/2

     

  • Question 2
    1 / -0

    The addition of a neutron to the nucleus of an atom results in the

    Solution

    Atoms of the same element can have different numbers of neutrons; the different possible versions of each element are called isotopes. For example, the most common isotope of hydrogen has no neutrons at all; there's also a hydrogen isotope called deuterium, with one neutron, and another, tritium, with two neutrons. The addition of a neutron to the nucleus of an atom results in the formation of an isotope.

     

  • Question 3
    1 / -0

    Which of the following isoelectronic species has more electrons than neutron?

    Solution

    Each ion has 10 electrons

    For F-, Z = 9 A = 19 n = 10

    For Na+, Z = 11, A = 23, n = 12

    For Mg2+, Z = 12 A = 24 n = 12

    For O2-, Z = 8 A = 16 n = 8

     

  • Question 4
    1 / -0

    The maximum number of 4f electrons, having spin quantum number 1/2 is

    Solution

    The maximum number of 4f electrons, having spin quantum number 1/2 is 7.

     

  • Question 5
    1 / -0

    The statement 'An s orbital is spherical in shape', means that

    Solution

    The statement 'An s orbital is spherical in shape', means that the probability of finding an electron, at a given distance from the nucleus in this orbital, is same in all directions.

     

  • Question 6
    1 / -0

    Electronic configuration of niobium (Nb = 41) is

    Solution

    Electronic configuration of niobium (Nb = 41) is (Kr) 4d4, 5s1

     

  • Question 7
    1 / -0

    How many electrons have their spins paired in an atom of oxygen (Atomic Number 8)?

    Solution

    Electronic configuration of oxygen is 1s2, 2s2, 2p4. So six electrons have their spins paired in an atom of oxygen.

     

  • Question 8
    1 / -0

    The atomic weight of an element is 52 and the atomic number is 24. The number of electrons, protons and neutrons in an atom of this element will be, respectively,

    Solution

    Atomic number = Number of electrons = Number of protons
    Atomic weight = Number of protons + Number of neutrons
    The number of electrons, protons and neutrons in an atom of this element will be, respectively, 24, 24 and 28

     

  • Question 9
    1 / -0

    When electrons revolve in stationary orbits,

    Solution

    When electrons revolve in stationary orbits, there is no change in energy level.

     

  • Question 10
    1 / -0

    Neutrons are present in the nuclei of all elements, except

    Solution

    Neurons are present in the nuclei of all elements, except the most common form of hydrogen.

     

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