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S- And p-Block Elements Test - 1

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S- And p-Block Elements Test - 1
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  • Question 1
    1 / -0

    Which of the following statements are FALSE?

    P. All the bonds that are present in PCl5 are similar.
    Q. ICl is more reactive than I2.
    R. Chlorine is a stronger oxidising agent than fluorine.
    S. Pentahalides are more covalent than trihalides.

    Solution

    PCl5 has a trigonal bipyramidal structure. All the bonds that are present in PCl5 are not similar. The bond length of the P-Cl bonds in the equatorial plane is different from the bond length of the P-Cl bonds in the axial plane. Hence, the statement 'P' is false.

    F2 is a stronger oxidising agent than Cl2. Hence, the statement 'R' is false.

    The I-I bond is stronger than the I-Cl bond, consequently ICl is more reactive than I2. Hence, the statement 'Q' is true.

    Pentahalides are more covalent than trihalides as the polarizing power of the central ion is greater in the higher oxidation state. This imparts a greater covalent character to the molecule. Hence, the statement 'S' is true.

     

  • Question 2
    1 / -0

    What is the correct order of thermal stability of hydrides of group 16 elements?

    Solution

    The bond dissociation enthalpy (H−E) of hydrides decreases on moving down the group and consequently the thermal stability decreases.
    The decreasing order of thermal stability of the group 16 hydrides is:
    H2O > H2S > H2Se > H2Te > H2Po

     

  • Question 3
    1 / -0

    Which of the following represents the correct order of reducing character of hydrides of group 15 elements?

    Solution

    As we move down a group, the atomic size increases and the stability of the hydrides of group 15 elements decreases. Since the stability of hydrides decreases on moving from NH3 to BiH3, the reducing character of the hydrides increases on moving from NH3 to BiH3. Hence, the correct order of reducing character is NH< PH< AsH< SbH< BiH3.

     

  • Question 4
    1 / -0

    Which of the following statements are FALSE?

    P. The boiling point of PH3 is lower than that of NH3.
    Q. Red phosphorus is more reactive than white phosphorus.
    R. Phosphorus is sp3 hybridised in PCl3.
    S. In the solid state, PCl5 exists as a covalent solid.

    Solution

    White phosphorus has a tetrahedral basic unit where four phosphorus atoms arranged at the four corners of a tetrahedron are joined together by a total of six single bonds.
    The molecule is under tremendous strain, hence white phosphorous is highly reactive.
    However, the strain is much less in case of red phosphorous on account of its polymeric structure.
    Therefore, chemically, red phosphorus is much less reactive than white phosphorus and statement is incorrect.
    In the solid state, PClexists as an ionic solid [PCl4]+[PCl6], in which the cation [PCl4]+ is tetrahedral and the anion [PCl6] is octahedral.
    Hence, statement S is incorrect.

     

  • Question 5
    1 / -0

    Directions For Questions

    In the following question, there are two statements, Assertion A and Reason R. Consider both the statements independently and mark your answer.

    ...view full instructions

    Assertion A: Elements of Group 16 generally show lower value of first ionization enthalpy as compared to the corresponding periods of Group 15.

    Reason R: Due to extra stable half-filled p orbital electronic configurations of Group 15 elements, larger amount of energy is required to remove electrons as compared to Group 16 elements.

    Solution

    A and R both are correct and R is the correct explanation of A.

    Elements of Group 16 generally show lower value of first ionization enthalpy as compared to the corresponding periods of group 15. Due to extra stable half-filled p orbitals electronic configurations of Group 15 elements, larger amount of energy is required to remove electrons as compared to Group 16 elements.

     

  • Question 6
    1 / -0

    Which of the following statements are TRUE?

    1. H2S is more acidic than H2Te.
    2. Ozone is thermodynamically more stable than oxygen.
    3. The two oxygen-oxygen bond lengths in the ozone molecule are identical.
    4. Rhombic sulphur is the stable form of sulphur at room temperature.

    Solution

    The two oxygen-oxygen bond lengths in the ozone molecule are identical (128 pm) and the molecule is angular as expected with a bond angle of about 117o.
    Sulphur forms numerous allotropes, of which the yellow rhombic and monoclinic forms are the most important. The stable form at room temperature is rhombic sulphur, which transforms to monoclinic sulphur when heated above 369 K.

     

  • Question 7
    1 / -0

    Directions For Questions

    In the following question, there are two statements, Assertion (A) and Reason (R). Consider both the statements independently and mark your answer.

    ...view full instructions

    Assertion (A): Halogens have the maximum negative electron gain enthalpy in their respective periods in the periodic table.

    Reason (R): Halogens have the largest size in their respective periods and therefore, the highest effective nuclear charge.

    Solution

    Halogens have the maximum negative electron gain enthalpy in their respective periods in the periodic table. They have the smallest size in their respective periods and therefore, the highest effective nuclear charge. As a consequence, they readily accept one electron to acquire noble gas electronic configuration.

     

  • Question 8
    1 / -0

    Match the following:
     

    Column – I (Compound) Column – II (Use)
    A. O2F2 1. Estimation of carbon monoxide
    B. ClO2 2. Bleaching agent for paper pulp and textiles
    C. I2O5 3. Removal of plutonium from spent nuclear fuel
    Solution

    O2F2 oxidises plutonium to PuF6 and the reaction is used in removing plutonium as PuF6 from spent nuclear fuel.

    ClO2 is used as a bleaching agent for paper pulp and textiles and in water treatment.

    I2O5 is a very good oxidising agent and is used in the estimation of carbon monoxide.

     

  • Question 9
    1 / -0

    The correct order of hydration enthalpies of alkali metal ions is

    Solution

    Correct order of hydration enthalpies is Li+ > Na+ > K+ > Rb+ > Cs+, because as we move from Li to Cs, the size increases and charge to radius ratio decreases, and it is difficult for the metal to be surrounded by water molecules. Hence, less energy is released when the size increases. Therefore, Li is the most heavily hydrated ion among alkali metal cations and Cs+ is the least hydrated ion.

     

  • Question 10
    1 / -0

    The alkali metals and their salts impart characteristic colour to an oxidising flame. Which of the following matchings of alkali metals and characteristic colour imparted to an oxidising flame by them is correct?

    Solution

    Potassium imparts violet colour to an oxidising flame.

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