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Mix Test - 10

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Mix Test - 10
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The compound benzophenone (C6H5COC6H5) does not react with
    Solution
    All aldehydes react with NaHSO3 to form a white crystalline solid, bisulphite addition compound.
    But ketones except for acetone and cyclohexanone do not react with NaHSO3 due to stearic hindrance.
  • Question 2
    1 / -0
    If an allotropic form changes slowly to a stable form, it is called
    Solution
  • Question 3
    1 / -0
    The number of optical isomers of CH3CH(OH)CH(OH)CHO is
    Solution
  • Question 4
    1 / -0
    Which of the following can act both as a Lewis acid and a Lewis base?
    Solution
  • Question 5
    1 / -0
    The enthalpies of combustion at 25°C of H2, cyclohexane (C6H12) and cyclohexene (C6H10) are -241 kJ/mole, -3920 kJ/mole and -3800 kJ/mole, respectively. The heat of hydrogenation of cyclohexene is
    Solution
    Given data:
    (i) H2 (g) + O2 (g) H2O (l) = -241 kJ/mole
    (ii) C6H10 (g) + O2 (g) 6CO2 (g) + 5H2O (l) = -3800 kJ/mole
    (iii) C6H12 (g) + 9O2 (g) 6CO2 (g) + 6H2O (l) = -3920 kJ/mole

    We have to calculate the enthalpy change for the reaction C6H10 (g) + H2 (g) C6H12 (g).
    This equation can be obtained by:
    Equation (ii) + Equation (i) - Equation (iii)

    Carrying out the corresponding manipulations for s, we get
    = (-3800 - 241 + 3920 kJ/mole) = -121 kJ/mole
  • Question 6
    1 / -0
    Which of the following statements is TRUE?
    Solution
    B-F bond is larger in BF4- than in BF3. This is due to the fact that in BF4-, boron atom is sp3 hybridised, while in BF3, boron atom is sp2 hybridised and bond length decreases with increase in s-character, since s-orbital is smaller than p-orbital.
  • Question 7
    1 / -0
    If 3 g of helium diffuses from a container in 15 minutes, then the mass of sulphur dioxide diffusing from the same container under identical conditions over the same time interval will be
    Solution
    According to Graham's law of diffusion,




    On solving we get,
    w = 12 g
  • Question 8
    1 / -0
    A reversible chemical reaction (g) ⇌ 2NO (g) + (g) is carried at 400 K with
    = 77.2 kJ/mol
    = 122 J/K/mol

    Which of the following is the correct value (x) for of the reaction?
    Solution
    = = 77.2 – = 28.4 kJ/mol
  • Question 9
    1 / -0
    What is the relation between Kp and Kc in the following reaction?

    N2(g) + 3H2(g) 2NH3(g)
    Solution
    The relation between Kp and Kc is given as:
    Kp = Kc(RT)Δn
    Kp = equilibrium constant in terms of partial pressure
    (Its unit is 'atm'.)
    Kc = equilibrium constant in terms of concentration (molarity)
    R = ideal gas constant (0.082 atm.L/K.mol)
    T = absolute temperature (570 K)
    Δn = Σn products - Σn reactants
    Δn = (2) - (3 + 1) = -2
    Thus, for the formation of NH3, the correct relation between Kp and Kc is:
    Kp = Kc(RT)-2 or Kp = Kc/(RT)2
  • Question 10
    1 / -0
    Why is the method of hydrogen preparation by action of cold water on potassium not preferred?
    Solution
    It is not preferred because the reaction is very violent and exothermic. The heat liberated ignites the hydrogen.
  • Question 11
    1 / -0
    In Antarctica, ozone depletion takes place due to the formation of which of the following compounds?
    Solution
    In Antarctica, ozone depletion takes place due to the formation of chlorine nitrate (ClONO2).
    Chlorine nitrate, with chemical formula ClNO3 is an important atmospheric gas present in the stratosphere. It is an important sink of chlorine that contributes to the depletion of ozone.
  • Question 12
    1 / -0
    The oxidation state of central metal atom in 'lunar caustic' is
    Solution
    Silver nitrate (AgNO3) is known as lunar caustic. The central metal in silver nitrate is nitrogen atom.
    + 1 + x + 3(-2) = 0
    x - 5 = 0
    x = +5
    Hence, the oxidation state of N atom in silver nitrate is +5.
  • Question 13
    1 / -0
    For a first order reaction, the time taken to reduce the initial concentration by a factor of 1/4 is 10 min. The time required to reduce the initial concentration by a factor of 1/16 will be
    Solution
    For a first order reaction, time required to reduce the concentration by the same factor is constant.
  • Question 14
    1 / -0
    If k1 and k2 are the respective equilibrium constants for the reactions (I) and (II), where (I) is 2NO and (II) is NO, then
    Solution

    On squaring k2, we get

    The right side of (k2)2 is equal to k1.
    So, (k2)2 = (k1)
    Or k2 =
  • Question 15
    1 / -0
    Which of the following aldehydes gives a red precipitate on reaction with Fehling solution?
    Solution
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