Mix Test

Result

Mix Test - 5

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Weekly Quiz Competition

Question 1
1 / -0

The compound above does not show aldol condensation because

A
carbon is bounded by 3 heavy methyl groups

B
of the absence of -hydrogen

C
it is a neutral molecule

D
of the hindrance created by methyl group for carbon ion

Solution
Question 2
1 / -0

Which of the following is a path function?

A
Internal energy

B
Enthalpy

C
Work

D
Entropy

Solution

Internal energy, enthalpy and entropy are state functions, whereas work and heat are path functions.
Question 3
1 / -0

Which of the following Fischer's projection formula is identical to D-glyceraldehyde?

A

B

C

D

Solution

Following is the Fischer's projection formula of D-glyceraldehyde:

D-glyceraldehyde has the -OH group on the right and -H on the left. Hold the -CHO group, rotation of the other three groups in such a way that -OH group will come towards right side. Configuraton of D-glyceraldehyde will obtain.
Question 4
1 / -0

The de Broglie wavelength of a tennis ball of mass 60 g moving with a velocity of 10 meters per second is approximately

A
10^-31 meters

B
10^-16 meters

C
10^-25 meters

D
10^-33 meters

Solution
Question 5
1 / -0

In the compound, CH₂=CH-CH₃,what is the hybridisation of 1^st and 2^nd carbon atoms?

A
sp³ - sp

B
sp² - sp³

C
sp² - sp

D
sp² - sp²

Solution

Every double bonded carbon atom is sp² hybidized.
In the compound CH₂CHCH₃,the first and second carbon atoms are sp² hybridised.
Question 6
1 / -0

Which of the following sets represents molecules with see-saw geometry only?

A
SF₄, TeCl₄, CH₄

B
XeF₄, TeCl₄, XeO₂F₂

C
SF₄, TeCl₄, XeO₂F₂

D
CH₄, XeF₄, TeCl₄

Solution

SF₄, TeCl₄, XeO₂F₂: All have see-saw geometry.
Question 7
1 / -0

A dry gas occupies 136.5 cm³ at STP. If the same mass of gas is collected over water at 27°C at a total pressure of 725 Torr, what volume will it occupy? The vapour pressure of water at 27°C is 25 Torr.

A
157.3 cm³

B
162.9 cm³

C
159.2 cm³

D
160.9 cm³

Solution
Question 8
1 / -0

The amount of heat evolved when 500 cm³ of 0.1 M HCl is mixed with 200 ml of 0.2 M NaOH is

A
1.292 kJ

B
2.292 kJ

C
3.35 kJ

D
0.092 kJ

Solution

500 cm³ of 0.1 M HCl = = 0.05 mol

200 cm³ of 0.2 M NaOH = = 0.04 mol
Limiting reagent is 0.04 mol NaOH.
Heat released = 0.04 x 57.3 = 2.292 kJ
Question 9
1 / -0

The ratio of rate constant of the forward to the backward reaction in an equilibrium is

A
equilibrium constant

B
rate constant

C
equilibrium coefficient

D
reaction quotient

Solution

The ratio of rate constant of the forward to the backward reaction in an equilibrium is called equilibrium constant.
Question 10
1 / -0

Which of the following statements is not correct about uses of hydrogen?

A
It is used as a fuel in the form of coal gas.

B
It is used for welding alloys containing different metals.

C
It is used in the preparation of ethanol.

D
It reduces metallic oxides to metal.

Solution

Hydrogen is used in the manufacture of methanol as shown below:
CO + 2H₂ CH₃OH
Question 11
1 / -0

Which of the following gases is present in the highest amount in the air?

A
Carbon dioxide

B
Hydrogen

C
Nitrogen

D
Oxygen

Solution

Nitrogen is present in the highest amount in the air.
Nitrogen (N₂): 78.09%
Oxygen (O₂): 20.95%
Argon (Ar): 0.93%
Carbon dioxide (CO₂): 0.038%
Question 12
1 / -0

Directions: In the following question, two statements are given. One is Assertion, and the other is Reason. Examine the statements carefully and mark the correct answer according to the instructions given below.

Assertion: BF₃ is a weaker Lewis acid than BBr₃.
Reason: BF₃ has planar geometry and is stabilised to a greater extent than BBr₃ by pπ-back bonding.

A
Both A and R are true and R is the correct explanation of A.

B
Both A and R are true, but R is not the correct explanation of A.

C
A is true but R is false.

D
A is false but R is true.

Solution

BF₃ is a weaker Lewis acid than BCl₃ because of the greater pπ-pπ back bonding effect in BBr₃.BF₃ and BBr₃ both have sp² hybridisation with trigonal planar geometry.
Question 13
1 / -0

A reaction: A Product, follows half-order kinetics with respect to A.

A linear plot is observed between

A
[A]^1/2 versus t, with slope equal to –k

B
[A]^1/2 versus t, with slope equal to –k/2

C
[A]^1/2 versus t, with slope equal to –2k

D
[A]^3/2 versus t, with slope equal to –k

Solution

^{On integration:}
Hence, the graph between and 't' is a straight line passing through the origin and the slope will be .
Question 14
1 / -0

The half cell reaction with their standard electrode potentials are

Pb²⁺ (aq) + 2e^- Pb(s) : E^o = - 0.13 V
Ag⁺ (aq) + e^- Ag(s); E^o = + 0.80 V

What is the emf of the cell?

A
- 0.93 V

B
+ 0.93 V

C
+ 0.67 V

D
- 0.67 V

Solution
Question 15
1 / -0

What amount (in g) of bromine will be required to convert 2 g of phenol into 2, 4, 6-tribromophenol?

A
4.00

B
6.00

C
10.22

D
20.44

Solution

1 mole of phenol (mol. mass = 94) requires 3 moles of Br₂ (mol. mass = 160)
Write equation for chemical change, find molecular masses of reactants and products and solve it.

Molecular weight of phenol = 12 × 6 + 1 × 6 + 16 = 94
Molecular wt. of Br₂ = 3 × 160 = 480
∵ 94 g of phenol requires = 480 g of Br₂
∴ 2 g of phenol requires = × 2 = 10.22 g