Mix Test

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Mix Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

The element 'X' which forms a stable product of the type XCl₄ is

A
Al

B
Na

C
Ca

D
Si

Solution

Silicon has a valency of 4. So, it will form a stable SiCl₄ (general formula: XCl₄) molecule to acquire stable noble gas configuration.
Aluminium is trivalent and forms AlCl₃ (general formula: XCl₃).
Sodium being monovalent forms NaCl (general formula: XCl).
Calcium being divalent forms CaCl₂ (general formula: XCl₂).
Question 2
1 / -0

A mixture of NH₄Cl and NaCl can be separated by

A
filtration

B
distillation

C
sublimation

D
decantation

Solution

A mixture of NH₄Cl and NaCl can be separated by sublimation. This is due to the fact that ammonium chloride changes directly from solid state to gaseous state on heating. So, to separate such mixtures that contain a sublimable volatile component (NH₄Cl) from a non-sublimable impurity (NaCl, in this case), sublimation method can be used.
Question 3
1 / -0

Among the following, the pair in which the first compound is ionic and the second compound is covalent is

A
Fe(OH)₂and CH₃OH

B
CH₃OH and CH₃CH₂OH

C
Fe(OH)₂ and Cu(OH)₂

D
Ca(OH)₂ and Cu(OH)₂

Solution

Among the given options, Fe(OH)₂, Cu(OH)₂and Ca(OH)₂ are ionic, while CH₃OH and CH₃CH₂OH are covalent.
Hence, option (1) is the correct answer.
Question 4
1 / -0

In the reaction SO₂ + 2H₂S 3S + 2H₂O, the substance that is oxidised is

A
SO₂

B
H₂O

C
S

D
H₂S

Solution

It is clear from the above equation that H₂S is getting oxidised to H₂O, while SO₂ is getting reduced to S.
Question 5
1 / -0

Sodium oxide dissolves in water to give sodium hydroxide, which indicates its

A
acidic character

B
basic character

C
amphoteric character

D
ionic character

Solution

We know that the metallic oxides are basic in nature, and on dissolving in water, they give their hydroxides, which are also basic in nature.
Question 6
1 / -0

For an ideal gas, Boyle's law is demonstrated by

A

B

C

D

Solution

As per Boyle's law, at constant temperature:
PV = constant
and .Since the graph is plotted at constant temperature, it is called an isotherm.

Question 7

1 / -0

Arrange the pH values of the following solutions in the correct increasing order:

(i) 0.1 M HCl, (ii) 0.1 M KOH, (iii) Tomato juice, and (iv) Pure water

(i) < (iii) < (iv) < (ii)

(iii) < (i) < (iv) < (ii)

(i) < (ii) < (iii) < (iv)

(iv) < (iii) < (ii) < (i)

Solution

According to pH scale,
pH < 7 - acidic solution (lower the pH value, greater the acidic nature)
pH = 7 - neutral solution
pH > 7 - basic solution (higher the pH value, greater the basic nature)
The pH value can be calculated as:
pH = - log [H₃O⁺]
The pH values of the given solutions are:

Substance	pH
0.1 M HCl	1
0.1 M KOH	13
Tomato juice	4.1 to 4.6
Water	7

From the above table, it is clear that the correct increasing order of pH values is:
(i) < (iii) < (iv) < (ii)

Question 8
1 / -0

When calcium carbide is added to water, the gas evolved is

A
carbon dioxide

B
hydrogen

C
acetylene

D
methane

Solution

On hydrolysis, calcium carbide gives acetylene. The complete reaction is shown below:
Question 9
1 / -0

The atomic radii of the alkali metals follow the order

A
Li > Na > K > Cs

B
K > Cs > Li > Na

C
Na > K > Cs > Li

D
Cs > K > Na > Li

Solution

As we move from top to bottom in a group, the atomic radii increase due to an increase in the number of shells and a decrease in the effective nuclear charge.
Therefore, the correct order of atomic radii of alkali metals is:
Cs > K > Na > Li
Question 10
1 / -0

The number of possible structural isomers of C₃H₄ is

A
1

B
3

C
2

D
4

Solution

There are three possible structural isomers of C₃H₄.
Propadiene, Propyne and Cyclopropene.
CH₂=C=CH₂,
Question 11
1 / -0

Which two of the following four compounds are isomeric?

(i) acetone, (ii) Propanol, (iii) Methyl acetate, and (iv) Propionic acid

A
Methyl acetate and Acetone

B
Methyl acetate and Propanol

C
Propionic acid and Methyl acetate

D
Propionic acid and Acetone

Solution

Propionic acid and methyl acetate both are functional isomers as both have the same chemical formula with different functional groups.
Question 12
1 / -0

One mole of nitrogen gas, on reaction with 3.01 10²³ molecules of hydrogen gas, produces

A
one mole of ammonia

B
2.0 10²³ molecules of ammonia

C
2 moles of ammonia

D
3.01 10²³ molecules of ammonia

Solution

The chemical reaction for the preparation of ammonia is:

N₂ + 3H₂ 2NH₃

It is clear from the above equation that 3 moles of hydrogen combine with 1 mole of N₂ to give 2 moles of NH₃.
(1/2) moles of hydrogen combines with 1/6 moles of N₂ to give moles of NH₃.

Therefore, number of molecules of NH₃ formed = × 6.02 × 10²³ = 2.0 × 10²³ molecules
Question 13
1 / -0

Saponification is

A
the hydrolysis of an ester

B
the hydrolysis of an amide

C
the hydrolysis of an ether

D
the hydrolysis of an acid chloride

Solution

The chemical reaction between any fatty acid (ester) and sodium hydroxide is a saponification reaction. For example:
Triglyceride + Sodium hydroxide (or potassium hydroxide) Glycerol + Three soap molecules
Question 14
1 / -0

A concentrated solution of lead nitrate in water can be stored in

A
an iron vessel

B
a copper vessel

C
a zinc vessel

D
a magnesium vessel

Solution

Concentrated PbNO₃ solution can be stored in a copper vessel due to higher reduction potential of copper as compared to that of lead. Therefore, the redox reaction will not take place and it is safe to store PbNO₃ in a copper vessel.
Or
Copper is less electropositive than lead and lies below it in the reactivity series. It cannot displace lead from its salt solution.
Hence, no reaction will occur and it is safe to store a concentrated solution of lead nitrate in a copper vessel.
Question 15
1 / -0

^{^{Given above are the solubility curves of KNO₃ and KCl.

Which of the following statements is not true?}}

A
At room temperature, the solubilities of KNO₃ and KCl are not equal.

B
The solubilities of both KNO₃ and KCl increase with temperature.

C
The solubility of KCl decreases with increasing temperature.

D
The solubility of KNO₃ increases much more than that of KCl with an increase in temperature.

Solution

The solubility of KCl increases with increasing temperature, as is evident from the graph.
Hence, option (3) is incorrect.
Question 16
1 / -0

Reaction of NaCl with conc. H₂SO₄ liberates a gas, X, which turns moist blue litmus paper red. When gas X is passed into a test tube containing eggshell powder suspended in water, another gas Y is generated which when passed through limewater, makes it milky. The gases X and Y, respectively, are

A
HCl and CO₂

B
SO₂ and CO₂

C
Cl₂ and CO₂

D
SO₂ and HCl

Solution

Case I: During the reaction of NaCl with conc. H₂SO₄, white fumes of HCl gas ('X') are produced.
Case II: When white fumes of HCl gas ('X') are passed through a test tube containing eggshell (which is CaCO₃), CO₂ gas ('Y') is liberated which turns limewater (CaOH)₂) milky due to the formation of insoluble CaCO₃.

The chemical reactions involved during these processes are:
Question 17
1 / -0

If 10 ml of an aqueous solution containing 222 mg of calcium chloride (molecular weight = 111) is diluted to 100 ml, then the concentration of chloride ion in the resulting solution will be

A
0.02 mol/L

B
0.01 mol/L

C
0.04 mol/L

D
2.0 mol/L

Solution

The initial concentration of CaCl₂ in mol/L can be calculated as:

M = = 0.2 mol/L

Now, apply molarity equation:
M₁V₁ = M₂V₂
0.2 x 10 x 10^-3 = M₂ x 100 x 10^-3[1 ml = 10^-3 L]
M₂ = 0.02 mol/L
Now, dissolution reaction of CaCl₂ is:
CaCl₂ (s) Ca²⁺ (aq) + 2Cl^- (aq)
It is clear from the above equation that the concentration of Cl^- ions is two times the concentration of CaCl₂ in the given solution.
Therefore, [Cl^-] = 0.02 x 2 = 0.04 mol/L
Question 18
1 / -0

Aluminium reduces manganese dioxide to manganese at high temperatures. The amount of aluminium required to reduce one gram mole of manganese dioxide is

A
^{_{gram mole}}

B
1 gram mole

C
^{_{gram mole}}

D
^{_{gram moles}}

Solution

The chemical equation of reaction of aluminium with manganese dioxide is:
4Al + 3MnO₂ 2Al₂O₃ + 3Mn

Now, it is clear from the above reaction:
To reduce 3 moles of MnO₂ = 4 g moles of Al are required
To reduce 1 mol of MnO₂ = g moles of Al are required
Question 19
1 / -0

Ethanol on reaction with alkaline KMnO₄ gives X, which when reacted with methanol in the presence of an acid, gives a sweet smelling compound, Y. X and Y, respectively, are

A
acetaldehyde and acetone

B
acetic acid and methyl acetate

C
formic acid and methyl formate

D
ethylene and ethyl methyl ether

Solution

As KMnO₄ is a strong oxidising agent, it will oxidise ethanol to acetic acid ('X'), which on reaction with methanol in the presence of acid, gives sweet smelling ester (methyl acetate). The reaction of carboxylic acid (acetic acid) with alcohol (methanol) is known as esterification reaction.
Question 20
1 / -0

The pH of a 10 ml aqueous solution of HCl is 4. The amount of water to be added to this solution in order to change its pH from 4 to 5 is

A
30 ml

B
60 ml

C
90 ml

D
120 ml

Solution

As we know, on dilution, milliequivalent of the solute remains constant.
Initially, pH of HCl = 4
So, normality of HCl = 10^-4 N
After dilution, pH of HCl = 5
So, normality of HCl will be 10^-5 N.
Apply normality equation:
N₁V₁= N₂V₂
10^-4 x 10 = 10^-5x V
V = 100 mL
So, 90 mL of water should be added for this pH change.