Self Studies
Self Studies
Self Studies
Self Studies

KVPY Class-XI (SA) - 2011

Result Self Studies

KVPY Class-XI (SA) - 2011
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    The number of distinct prime divisors of the number 5123 - 2533 - 2593 is

    Solution

    (512)3 – 2533 – 2593

    = (512)3 – [(253)3 + (259)3]

    = (512)3 – (253 + 259) (2532 + 2592 – (253 × 259)

    = (512)3 – (512) [(253 + 259)2 – 2(253) (259) – (253) (259)]

    = 512 [(512)2 – {(512)2 – 3 (253) (259)}]

    = (512) [3 (253) (259)] = 29 × 3 × (253) (259)

    = 29(3) (11) (23) (7) (37)

     

  • Question 2
    1 / -0

    The following three objects (1) a metal tray, (2) a block of wood, and (3) a woollen cap are left in a closed room overnight. Next day the temperature of each is recorded as T1, T2 and T3 respectively. The likely situation is

    Solution

    All three objects (1) a metal tray, (2) a block of wood, and (3) a woollen cap will be in thermal equilibrium with the air of room. So, temperatures of the three will be same.

     

  • Question 3
    1 / -0

    We sit in the room with windows open. Then,

    Solution

    We sit in the room with windows open. The air pressure is nearly the same on the floor, the walls and the ceiling because the height of the room is very small as compared to the height of the atmosphere.

     

  • Question 4
    1 / -0

    A convex lens is used to form an image of an object on a screen. If the upper half of the lens is blackened so that it becomes opaque, then

    Solution

    A convex lens is used to form an image of an object on a screen. If the upper half of the lens is blackened so that it becomes opaque, then the image will be formed with reduced brightness as light reaching from each and every part of the object through lens, with blackened part, will be less as the aperture of the lens is reduced.

     

  • Question 5
    1 / -0

    Two balloons, A and B, containing 0.2 moles and 0.1 moles, respectively, of helium at room temperature and 2.0 atm are connected. When equilibrium is established, the final pressure of He in the system is

    Solution

    Since pressures of the gases are the same in both the containers, therefore, the final pressure will not change.

     

  • Question 6
    1 / -0

    The set of principal (n), azimuthal (l) and magnetic (ml) quantum numbers not allowed for the electron in H-atom is

    Solution

    'n' is always greater than 'l'.
    And m = -l…….. 0 ……..+l
    If n = 2, then l = 0, 1
    and ml = 0, {-1, 0, +1}.

     

  • Question 7
    1 / -0

    When chlorine gas is passed through an aqueous solution of KBr, the solution turns brown due to the formation of

    Solution

    When chlorine gas is passed through an aqueous solution of KBr, the solution turns brown due to the formation of bromine.

    2KBr + Cl2 → 2KCl + Br2 (brown)

     

  • Question 8
    1 / -0

    If parents have free earlobes and the offspring has attached earlobes, then the parents must be

    Solution

    If parents with free earlobes give birth to a baby with attached earlobes, it is certain that both of them had both a copy of the dominant and recessive alleles.

     

  • Question 9
    1 / -0

    During meiosis, there is

    Solution

    In meiosis, DNA replication occurs only once in the S phase of interphase. Homologous pairs separate during the first round of cell division, called meiosis I. Sister chromatids separate during the second round, called meiosis II.

     

  • Question 10
    1 / -0

    Blood clotting involves the conversion of

    Solution

    Fibrinogen is converted into fibrin. The fibrin threads form a mesh that traps platelets, blood cells and plasma. This is the stage of clot formation.

     

  • Question 11
    1 / -0

    The gallbladder is involved in

    Solution

    Bile is synthesised in the liver. It is stored in the gallbladder and secreted when required for the emulsification of fats.

     

  • Question 12
    1 / -0

    Which of the following colours is LEAST useful for plant life?

    Solution

    Green light is not absorbed but reflected, making the plant appear green. The most important colours/wavelengths of light are red and blue, which are absorbed during photosynthesis.

     

  • Question 13
    1 / -0

    At rest, the volume of air that moves in and out per breath is called

    Solution

    Tidal volume (symbol VT or TV) is the lung volume representing the normal volume of air displaced between normal inhalation and exhalation when extra effort is not applied.

     

  • Question 14
    1 / -0

    Scurvy is a result of the deficiency of

    Solution

     

    Scurvy is a disease resulting from the lack of vitamin C. Early symptoms include weakness, fatigue, curly hair, and sore arms and legs.

     

  • Question 15
    1 / -0

    How many sex chromosomes does a normal human inherit from the father?

    Solution

    In humans, there are a total of 23 pairs of chromosomes. Out of these, 22 pairs are autosomes and one pair is of sex chromosomes. One chromosome in this pair is inherited from the father and the other one is inherited from the mother.

     

  • Question 16
    1 / -0

    Which of the the following structures is NOT found in plant cells?

    Solution

    The main function of the centriole is to help with cell division in animal cells. Centrioles help in the formation of the spindle fibres that separate the chromosomes during cell division. Centrioles are not found in plant cells.

     

  • Question 17
    1 / -0

    The cell that transfers information about pain to the brain is called a

    Solution

    A neuron is an electrically excitable cell that processes and transmits information through electrical and chemical signals.

     

  • Question 18
    1 / -0

    The presence of nutrients in the food can be tested. Benedict's Test is used to detect

    Solution

    Benedict's Test is used to test for simple carbohydrates. Benedict's Test identifies reducing sugars (monosaccharides and some disaccharides), which have free ketone or aldehyde functional groups. Benedict's solution can be used to test for the presence of glucose in urine.

     

  • Question 19
    1 / -0

    Several minerals such as iron, iodine, calcium and phosphorus are important nutrients. Iodine is found in

    Solution

    Iodine is essential for the formation of thyroid hormones like thyroxine.

     

  • Question 20
    1 / -0

    The principle upon which a lactometer works is

    Solution

    A lactometer is a little glass instrument that tests the purity of milk based on density/buoyancy. If the milk sample is pure, then the lactometer floats on it; and if it is adulterated or impure, then the lactometer sinks.

     

  • Question 21
    1 / -0

    Mammalian liver cells will swell when kept in

    Solution

    Mammalian liver cells are animal cells. If kept in hypotonic solution, the animal cells swell up due to intake of water.

     

  • Question 22
    1 / -0

    The form of cancer called 'carcinoma' is associated with

    Solution

    Carcinoma is a cancer arising in the epithelial tissue of the skin or of the lining of the internal organs.

     

  • Question 23
    1 / -0

    Three taps A, B, C fill up a tank independently in 10 hr, 20 hr, 30 hr, respectively. Initially the tank is empty and exactly one pair of taps is open during each hour and every pair of taps is open at least for one hour. What is the minimum number of hours required to fill the tank?

    Solution

    Let the tank volume be 60V litres
    Let the tap A fill it in 10 hours and the volumetric flow rate through tap A be A litres per hour
    So, 10A = 60V or A = 6V ....(i)
    Let the tap B fill it in 20 hours and the volumetric flow rate through it be B litres per hour.
    So, 20B = 60V or B = 3V ... (ii)
    Let the tap C fill the tank in 30 hours and the volumetric flow rate through it be C litres per hour.
    So, 30C = 60V or, C = 2V ... (iii)
    As the tank has to be filed in the minimum possible time and as exactly one pair of taps is open every hour and a pair of tanks is open for at least an hour, and as the volumetric flow rate through tap C is the least, taps A and C are opened for 1 hour only and the pair B and C is opened for the other hour.
    Thus, in all, tap C is opened for 2 hours only and in those 2 hours, taps A and B run for 1 hour each.
    Thus, fluid filed in those 2 hours = (2C + A + B) litres ...(iv)
    Plugging in the values of C, A and B in terms of V, we get volume of fluid filled = (2 x 2V + 6V + 3V) litres = 13V litres
    Volume of fluid left to be filled = (60V - 13V) litres = 47V litres
    Now, taps A and B only are opened to fill this volume of fluid.
    Let them do so in t hours.
    So, t(A + B) = 47V ... (v)
    Now plugging in the values of A and B in terms of V in equation (v), we have the following equation:
    t(6V + 3V) = 47V
    Or, t x 9V = 47V
    Or, t = 47/9 = 5 2/9
    Thus total time taken to fill the tank = (2 +5 2/9) hours = 7 2/9 hours

     

  • Question 24
    1 / -0

    You remove four fresh tobacco leaves of similar size and age. Leave leaf 1 as it is, smear leaf 2 with Vaseline on the upper surface, leaf 3 on the lower surface and leaf 4 on both the surfaces. Hang the leaves for a few hours and you observe that leaf 1 wilts the most, leaf 2 has wilted, leaf 3 has wilted less than leaf 2 and leaf 4 remains fresh. Which of the following conclusions is most logical?

    Solution

    All surfaces of plants that are in the air have some stomata, but leaf surfaces have the most because this is where photosynthesis is occurring. From the experiment, it can be concluded that the underside of the tobacco leaf has more stomata than the upper surface as leaf 3 has wilted less than leaf 2.

     

  • Question 25
    1 / -0

    Vestigial organs such as the appendix exist because

    Solution

    Vestigial organs such as the appendix exist because these vestigial organs were functional in certain ancestors.

     

  • Question 26
    1 / -0

    Mendel showed that unit factors, now called alleles, exhibit a dominant/recessive relationship. In a monohybrid cross, the __________ trait disappears in the first filial generation.

    Solution

    In Mendel's experiment, in the first filial generation, all plants show the dominant character. The recessive character is shielded, which appears in the second filial generation.

     

  • Question 27
    1 / -0

    If a man with an X-linked dominant disease has six sons from a woman having a normal complement of genes, then

    Solution

    Males inherit only the Y chromosome from their father. The X chromosome is inherited from the mother. So none of the sons will show symptoms of the disease.

     

  • Question 28
    1 / -0

    In evolutionary terms, an Indian school boy is more closely related to

    Solution

    Modern humans evolved in East Africa and then began to disperse throughout the world roughly 50,000 to 1,00,000 years ago. So, as a fact, Indians also evolved in Africa.

     

Self Studies
User
Question Analysis

  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now