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Quadratic Equations Test - 1

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Quadratic Equations Test - 1
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following equations is not quadratic?
    Solution
    Option (1) :
    (x + 1)2 = 2(x - 3)
    x2 + 2x + 1 = 2x - 6
    x2 + 7 = 0, a quadratic equation.

    Option (2):
    x2 - 2x = -2(3 - x)
    x2 - 2x = -6 + 2x
    x2 - 4x + 6 = 0, a quadratic equation.

    Option 3:
    (x - 2)(x + 1) = (x - 1)(x + 3)
    x2 - 2x + x - 2 = x2 + 3x - x - 3
    -x - 2x + 1 = 0
    -3x + 1 = 0, not a quadratic equation, because it is not in the form of ax2 + bx + c = 0
  • Question 2
    1 / -0
    Which of the following quadratic equations is in standard form?
    Solution
    A quadratic equation in the standard form is given in option (2), i.e. 5x2 + 2x + 1 = 0, because the standard form of a quadratic equation is ax2 + bx + c = 0, where a, b, c ∈ R, a ≠ 0 and a is positive.
  • Question 3
    1 / -0
    Which of the following quadratic equations is in standard form?
    Solution
    The standard form of a quadratic equation is ax2 + bx + c = 0, where a, b, c ∈ R, a ≠0.
    So, the standard form of the given equation is x2 + 8x - 2 = 0.
  • Question 4
    1 / -0
    Solve the following equation for x:

    x2 - 7x + 12 = 0
    Solution
    x2 - 7x + 12 = 0
    => x2 - 4x - 3x + 12
    => (x - 3)(x - 4) = 0
    So, x = 3 and 4
  • Question 5
    1 / -0
    Solve for x:

    3x2 + 5x - 8 = 0
    Solution
    x =

    = -
    = 1 or
  • Question 6
    1 / -0
    Find x, if 2x2 - 8x - 24 = 0.
    Solution
    2x2 - 8x - 24 = 0
    x2 - 4x - 12 = 0
    Or x2 - 6x + 2x - 12 = 0
    Or x(x - 6) + 2(x - 6) = 0
    Or (x - 6)(x + 2) = 0

    Thus, x = 6 or x = -2
  • Question 7
    1 / -0
    If the equation x2 – 5x + 6 = 0 has real roots, then what is the sum and product of the roots of this equation?
    Solution
    x2 – 5x + 6 = 0
    x2 – 3x – 2x + 6 = 0
    x(x – 3) – 2(x – 3) = 0
    (x – 3) (x – 2) = 0
    x = 3, 2
    Product of roots = 3 x 2
    = 6
    Sum of roots = 3 + 2
    = 5
  • Question 8
    1 / -0
    Find the real roots of the quadratic equation x2 - 9x + 18 = 0 and for the two roots x and x1, find a and b such that Log10 a = x and Log10 b = x1.
    Solution
    x2 - 9x + 18 = 0
    x2 - 6x - 3x + 18 = 0
    x (x - 6) - 3 (x - 6) = 0
    (x - 6) (x - 3) = 0
    x = 6, 3
    x = 6, x1 = 3
    Log10 a = x Log10 a = 6 a = (10)6
    Log10 b = x1 Log10 b = 3 b = (10)3
  • Question 9
    1 / -0
    Which of the following equations has no real roots?
    Solution
    In x2 + x + 1 = 0, D < 0 (As D < 0, it has no real roots)
  • Question 10
    1 / -0
    Find the common root between quadratic equations x2 – 5x + 6 = 0 and x2 – 7x + 10 = 0.
    Solution
    x2 – 5x + 6 = 0 x2 – 7x + 10 = 0
    X2 – 3x – 2x + 6 = 0 x2 – 5x – 2x + 10 = 0
    X (x – 3) – 2 (x – 3) = 0 x (x – 5) – 2 (x – 5) = 0
    (x – 3) (x – 2) = 0 (x – 5) (x – 2) = 0
    X = 3, (2) x = 5, (2)
  • Question 11
    1 / -0
    Find the product of the roots of the following equation:

    – 9x2 – 8x = 15
    Solution
    – 9 x2 – 8 x = 15

    First subtract 15 from both sides.

    – 9 x2 – 8 x – 15 = 0

    Or 9 x2 + 8 x + 15 = 0

    Comparing the equation with the standard quadratic equation

    a x2 + b x + c = 0
    a = 9
    b = 8
    c = 15

    Product of roots= c/a = 15/9 = 5/3

    Hence, option (4) is correct.
  • Question 12
    1 / -0
    What would be the value of p for which the equation 4x2 - 5x + p = 0 gives two real equal roots?
    Solution
    Discriminant = b2 - 4ac
    = (- 5)2 - 4 4 p
    = 25 - 16p

    For equal roots, D = 0
    25 - 16p = 0
    p =
  • Question 13
    1 / -0
    If x = 2 and x = 3 are roots of the equation 3x2 – 2mx + 2n = 0, find the values of m and n.
    Solution
    Sum of roots = 2 + 3 = 5 = 2m/3
    This gives us m as 15/2.
    Also, product of roots is 2 x 3 = 6 = 2n/3
    This gives us n as 9.
    Thus, option (3) is correct.
  • Question 14
    1 / -0
    Which of the following equations has one of its roots as?
    Solution
  • Question 15
    1 / -0
    Which of the following quadratic polynomials has sum of its zeros as 1/4 and product of its zeros as -1?
    Solution
    Let the quadratic polynomial be ax2 + bx + c and its zeros be and .
    Given:

    Thus, the quadratic polynomial becomes a{x2 - (1/4)x + (-1)}.
    (a/4){4x2 - x - 4}

    Putting a = 4, the quadratic polynomial becomes 4x2 – x – 4.
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