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Theory of Equations Test - 4

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Theory of Equations Test - 4
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  • Question 1
    1 / -0

    The number of real roots of the equation (x – 1)2 + (x – 2)2 + (x – 3)2 = 0 is

    Solution

    The equation has no real root because its LHS is always positive, while its RHS is zero.

     

  • Question 2
    1 / -0

    For what value of m will the equation

    (m + 1) x2 + 2 (m + 3) x + m + 8 = 0 have equal roots?

    Solution

    For equal roots D = 0 or b2 - 4ac = 0
    4 (m + 3)2 - 4 (m + 1) (m + 8) = 0
    Solving we get m = 1/3

     

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