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Heron`s Formula Test - 1

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Heron`s Formula Test - 1
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  • Question 1
    1 / -0
    In a quadrilateral ABCD, AB = 10 cm, BC = 12 cm, CD = 7 cm, AD = 9 cm and diagonal AC = 14 cm. The area of ABC is
    Solution


    According to Heron's formula,

    A =

    P = Semi-perimeter
    a, b and c are the sides of the triangle.

    P of ABC =

    Area = cm2

    = cm2

    =

    = cm2

    = 2 2 2 3 cm2

    =
  • Question 2
    1 / -0


    What is the area of the given triangle?
    Solution
    Let P be the semi-perimeter of the triangle.

    P = cm

    Area = unit2

    Area = cm2

    Area = cm2

    = 2 x 2 x 3 cm2 = 12 cm2
  • Question 3
    1 / -0
    ABC is an isosceles triangle with AB = AC = a cm. If BC = b cm, then use Heron's formula to find the area of the triangle.
    Solution
    s =

    Area of triangle =
    By solving, we get
    Area of triangle =
  • Question 4
    1 / -0
    In a triangle ABC, AB = 6 cm, BC = 7 cm and AC = 9 cm. The area of ABC is
    Solution
    Let P be the semi-perimeter of the triangle.

    P = cm

    Area = unit2

    Area = cm2

    Area = cm2

    = 2 cm2
  • Question 5
    1 / -0
    ABCD is a rhombus with AB = 6 cm and AC = 8 cm. What is the area of the rhombus?
    Solution


    ABCD is a rhombus.
    AB = BC = CD = DA = 6 cm
    AC = 8 cm
    Area of rhombus = 2 x area of ABC
    Now, area of ABC =
    S =
    Area of ABC =
    = cm2
    Area of rhombus = 2( Area of triangle ABC) = 16cm2
  • Question 6
    1 / -0
    XYZ has sides XY = 20 cm, YZ = 30 cm and XZ = 40 cm. What is the length of the altitude from vertex X?
    Solution


    S = cm
    Area = cm2

    =
    Also,
    Area =

    Or height =
  • Question 7
    1 / -0
    What is the area of the given figure?

    Solution
    Area of triangle with sides 8 cm, 15 cm and 17 cm:

    Semi perimeter = ( a + b + c) / 2 = ( 8 + 15 + 17) / 2 = 20 cm

    Area by Heron's formula = =

    = 3 4 5 = 60 cm2
    Area of triangle with sides 9 cm, 15 cm and 12 cm:

    S =







    = 54 cm2



    = 114 cm2
  • Question 8
    1 / -0
    An irregular octagon is formed by joining 8 triangles, each having dimensions 8 cm, 7 cm and 9 cm. What is the total area of the octagon?
    Solution
    Total area of the octagon = 8 times the area of triangle with sides 8 cm, 7 cm and 9 cm.
    Area of triangle:
    a = 8 cm, b = 7 cm, c = 9 cm =
    Therefore, area =
    Therefore, area of octagon =
    = 96 cm2
  • Question 9
    1 / -0
    A showpiece is made up of three triangles measuring 4 cm, 5 cm and 7 cm. What is the total area of the showpiece?

    Solution
    Area of one triangle =
    S =
    Area of one triangle =
    =
    =
    Total area of showpiece = 3
    = 12cm2
  • Question 10
    1 / -0
    What is the area of an isosceles triangle whose sides measure a cm, a cm and b cm?
    Solution
    S = cm
    S – a = cm
    s – a = cm
    s – b = cm
    Area = sq. cm
    = sq. cm
  • Question 11
    1 / -0
    In a triangle, the three sides a, b and c measure 9 cm, 6 cm and 5 cm, respectively. What is the length of the altitude to the side 'b' from the opposite vertex?
    Solution
    S = semi-perimeter =
    Now,


    Or height =
  • Question 12
    1 / -0
    ABC is a scalene triangle. If AB = 3 cm, BC = 6 cm and AC = 5 cm, what is the area of the triangle?
    Solution
    Let a = 3 cm
    b = 5 cm
    c = 6 cm

    S =
    S =
    S =
    Now, area of ABC =
    =
    =
    =
  • Question 13
    1 / -0
    If the lengths of the sides of a triangle are doubled, then which of the following shows the correct relationship between the new area (A2) and the old area (A1)?
    Solution
  • Question 14
    1 / -0
    What is the area of the given triangle?


    Solution
    Let a = 11 cm
    b = 7 cm
    c = 10 cm
    Then, S = cm
    = cm
    Area by Heron's formula =
    =
    =
    =
  • Question 15
    1 / -0
    What is the area of a parallelogram with adjacent sides measuring 12 cm and 5 cm and the diagonal corresponding to the given two sides measuring 13 cm?
    Solution


    ABCD is a parallelogram.
    AB = CD = 12 cm
    and BC = AD = 5 cm
    Area of parallelogram ABCD = 2 area of ABC
    Now, S = cm
    Area of ABC =
    = cm2
    = 30 cm2
    Now, Area of parallelogram = 2 30 cm2
    = 60 cm2
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