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Perimeter And Area - 2D Test - 3

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Perimeter And Area - 2D Test - 3
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  • Question 1
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    The sides of a rectangular park are in the ratio 3 : 2 and its area is 3,750 m2. The cost of fencing it at 50 paisa per metre is:

    Solution

    Let the length and the breadth of the rectangular park be 3a and 2a, respectively.
    Therefore, (3a) x (2a) = 3750
    ⇒ 6a2 = 3750
    ⇒ a2 = 625
    ⇒ a = 25 m
    Hence, length = 3 x 25 = 75 m and breadth = 2 x 25 = 50 m
    Now, perimeter of the rectangular park = 2(Length + Breadth) = 2(75 + 50) = 250 m
    Cost of fencing it at the rate of 0.50 per m = 250 x 0.50 = Rs. 125

     

  • Question 2
    1 / -0

    From a circular sheet of paper with radius 20 cm, four circles of radius 5 cm each are cut out. What is the ratio of the uncut to the cut portion?

  • Question 3
    1 / -0

    In a triangle ABC, the lengths of the sides AB and AC are 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD is perpendicular to BC. If AD = 3 cm, then what is the radius (in cm) of the circle circumscribing the triangle ABC?

  • Question 4
    1 / -0

    The sides of a square are increased by 20% and 40%, respectively. The area of the resulting rectangle exceeds the area of the square by:

  • Question 5
    1 / -0

    A jogging park has two identical circular tracks touching each other and a rectangular track enclosing the two circles. The edges of the rectangles are tangential to the circles. Two friends, A and B, start jogging simultaneously from the point where one of the circular tracks touches the smaller side of the rectangular track. A jogs along the rectangular track, while B jogs along the two circular tracks in a figure of eight. Approximately, how much faster than A does B have to run, so that they take the same time to return to their starting point?

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