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Number Analogy Test - 5

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Number Analogy Test - 5
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  • Question 1
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language-
    '3$f 8#d 7@s 5!a' means 'class are always late'.
    '2%g 3$f 0&j 1^h' means 'teacher were always punished'.
    '8#d 1^h 4*k 9?c' means 'teacher stopped all class'.
    '6%m 7@s 2%g 4*k' means 'all students were late'.

    ...view full instructions

    What will be the code for 'punished'?

    Solution

    In the given second and third statements, the common code-word is "1^h" and the common word is "teacher". So, "1^h" means "teacher".
    In the given first and second statements, the common code-word is "3$f" and the common word is "always". So, "3$f" means "always".

    In the given second and fourth statements, the common code-word is "2%g" and the common word is "were". So, "2%g" means "were".
    In the second statement, the remaining code-word is "0&j" and the remaining word is "punished". So, "punished" will be coded as "0&j".

     

  • Question 2
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language-
    '3$f 8#d 7@s 5!a' means 'class are always late'.
    '2%g 3$f 0&j 1^h' means 'teacher were always punished'.
    '8#d 1^h 4*k 9?c' means 'teacher stopped all class'.
    '6%m 7@s 2%g 4*k' means 'all students were late'.

    ...view full instructions

    How will 'students are late' be coded?

    Solution

    In the given first and fourth statements, the common code-word is "7@s" and the common word is "late". So, "7@s" means "late".
    In the given third and fourth statements, the common code-word is "4*k" and the common word is "all". So, "4*k" means "all".

    In the given first and second statements, the common code-word is "3$f" and the common word is "always". So, "3$f" means "always".
    In the given first and third statements, the common code-word is "8#d" and the common word is "class". So, "8#d" means "class".

    In the given second and fourth statements, the common code-word is "2%g" and the common word is "were". So, "2%g" means "were".
    In the first statement, the remaining code-word is "5!a" and the remaining word is "are". So, "are" will be coded as "5!a".

    In the fourth statement, the remaining code-word is "6%m" and the remaining word is "students". So, "students" will be coded as "6%m".

    Thus, the required code will be the combination of 6%m, 5!a and 7@s.

     

  • Question 3
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language-
    '3$f 8#d 7@s 5!a' means 'class are always late'.
    '2%g 3$f 0&j 1^h' means 'teacher were always punished'.
    '8#d 1^h 4*k 9?c' means 'teacher stopped all class'.
    '6%m 7@s 2%g 4*k' means 'all students were late'.

    ...view full instructions

    What will be the code for 'stopped'?

    Solution

    In the given second and third statements, the common code-word is "1^h" and the common word is "teacher". So, "1^h" means "teacher".
    In the given third and fourth statements, the common code-word is "4*k" and the common word is "all". So, "4*k" means "all".

    In the given first and third statements, the common code-word is "8#d" and the common word is "class". So, "8#d" means "class".
    In the third statement, the remaining code-word is "9?c" and the remaining word is "stopped". So, "stopped" will be coded as "9?c".

     

  • Question 4
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language-
    '3$f 8#d 7@s 5!a' means 'class are always late'.
    '2%g 3$f 0&j 1^h' means 'teacher were always punished'.
    '8#d 1^h 4*k 9?c' means 'teacher stopped all class'.
    '6%m 7@s 2%g 4*k' means 'all students were late'.

    ...view full instructions

    What will be the code for 'always good'?

    Solution

    In the given first and second statements, the common code-word is "3$f" and the common word is "always". So, "3$f" means "always".
    From the given option, "3$f" is the code-word for "always", then "6~s" will be the code-word for "good".

    So, the code for "always good" will be "3$f 6~s".

     

  • Question 5
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language-
    '2%k 5*i 8&h 8%a 7^n' means 'women's place in the home'.
    '0&j 1$c 6@j i*2 8%a' means 'women's work is never done'.
    'w!9 9&f 5*i 4&g 1$c' means 'his work place was nearer'.
    '0&j 9&f r@3 7^n 3?t' means 'his home art never break'.

    ...view full instructions

    What is the code for 'nearer'?

    Solution

    In the given third and fourth statements, the common code-word is 9&f and the common word is his. So, 9&f means his.
    In the given second and third statements, the common code-word is 1$c and the common word is work. So, 1$c means work.

    In the given first and third statements, the common code-word is 5*i and the common word is place. So, 5*i means place.
    The remaining code-words are w!9 and 4&g and the remaining words are was and nearer.

    So, the word nearer is coded as w!9 or 4&g.

     

  • Question 6
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language—
    '2%k 5*i 8&h 8%a 7^n' means 'women's place in the home'.
    '0&j 1$c 6@j i*2 8%a' means 'women's work is never done'.
    'w!9 9&f 5*i 4&g 1$c' means 'his work place was nearer'.
    '0&j 9&f r@3 7^n 3?t' means 'his home art never break'.
     

    ...view full instructions

    What is the code for 'done'?

    Solution

    In the given first and second statements, the common code-word is "8%a" and the common word is "women's". So, "8%a" means "women's".
    In the given second and third statements, the common code-word is "1$c" and the common word is "work". So, "1$c" means "work".

    In the given second and fourth statements, the common code-word is "0&j" and the common word is "never". So, "0&j" means "never".
    The remaining code-words are "6@j" and "i*2" and the remaining words are "is" and "done".

    So, the word "done" is coded as "6@j" or "i*2".

     

  • Question 7
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language—
    '2%k 5*i 8&h 8%a 7^n' means 'women's place in the home'.
    '0&j 1$c 6@j i*2 8%a' means 'women's work is never done'.
    'w!9 9&f 5*i 4&g 1$c' means 'his work place was nearer'.
    '0&j 9&f r@3 7^n 3?t' means 'his home art never break'.

    ...view full instructions

    Which of the following will be the code for 'home work'?

    Solution

    In the given second and third statements, the common code-word is "1$c" and the common word is "work". So, "1$c" means "work".
    In the given first and fourth statements, the common code-word is "7^n" and the common word is "home". So, "7^n" means "home".

    So,"home work" will be coded as "7^n 1$c".

     

  • Question 8
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language—
    '2%k 5*i 8&h 8%a 7^n' means 'women's place in the home'.
    '0&j 1$c 6@j i*2 8%a' means 'women's work is never done'.
    'w!9 9&f 5*i 4&g 1$c' means 'his work place was nearer'.
    '0&j 9&f r@3 7^n 3?t' means 'his home art never break'.

    ...view full instructions

    What will be the code for "women's never break"?

    Solution

    In the given first and second statements, the common code-word is "8%a" and the common word is "women's". So, "8%a" means "women's".
    In the given second and fourth statements, the common code-word is "0&j" and the common word is "never". So, "0&j" means "never".

    In the given third and fourth statements, the common code-word is "9&f" and the common word is "his". So, "9&f" means "his".
    In the given first and fourth statements, the common code-word is "7^n" and the common word is "home". So, "7^n" means "home".

    The remaining code-words are "r@3" and "3?t" and the remaining words are "art" and "break".
    So, the word "break" will be coded as "r@3" or "3?t".

    From the above conclusion, "women's never break" will be coded as "8%a 0&j r@3".

     

  • Question 9
    1 / -0

    Directions For Questions

    Study the information and answer the following question.

    In a certain code language—
    '2%k 5*i 8&h 8%a 7^n' means 'women's place in the home'.
    '0&j 1$c 6@j i*2 8%a' means 'women's work is never done'.
    'w!9 9&f 5*i 4&g 1$c' means 'his work place was nearer'.
    '0&j 9&f r@3 7^n 3?t' means 'his home art never break'.

    ...view full instructions

    What will be the code for 'home is sweet place'?

    Solution

    In the given first and fourth statements, the common code-word is "7^n " and the common word is "home". So, "7^n" means "home".
    In the given first and third statements, the common code-word is "5*i" and the common word is "place". So, "5*i" means "place".

    In the given first and second statements, the common code-word is "8%a" and the common word is "women's". So, "8%a" means "women's".
    In the given second and third statements, the common code-word is "1$c" and the common word is "work". So, "1$c" means "work".

    In the given second and fourth statements, the common code-word is "0&j" and the common word is "never". So, "0&j" means "never".
    The remaining code-words are "6@j" and "i*2" and the remaining words are "is" and "done".

    So, the word "is" will be coded as "6@j" or "i*2".

    From the above conclusion. "home is sweet place" will be coded as "1#z 6@j 5*i 7^n".

     

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