MAT (Stage-2) Mock Test

Result

MAT (Stage-2) Mock Test - 56

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Weekly Quiz Competition

Question 1
1 / -0

A series of figures is given below. Checking the pattern in the first two figures, you have to find the missing number in the third.

A
5.5

B
10.5

C
8.5

D
3.5

Solution

Half of the sum of the number outside the circle gives the number inside the circle.

Missing number = (4 + 3 + 1 + 3) ÷ 2 = 11 ÷ 2 = 5.5
Question 2
1 / -0

A series of figures is given below. Checking the pattern in the first two figures, you have to find the missing number in the third.

A
24

B
125

C
216

D
64

Solution
Question 3
1 / -0

A series of figures is given below. Checking the pattern in the first two figures, you have to find the missing number in the third.

A
24

B
36

C
42

D
15

Solution

'Sum of numbers around the circle × 2' gives the number inside the circle.
Missing number = (4 + 5 + 6 + 3) × 2 = 18 × 2 = 36
Question 4
1 / -0

Which of the following options should replace the question mark in the final figure of the series given below?

A
400

B
41

C
9

D
3

Solution
Question 5
1 / -0

A series of figures is given below. Checking the pattern in the first two figures, you have to find the missing number in the third.

A
21

B
15

C
17

D
14

Solution
Question 6
1 / -0

Instead of dividing Rs. 117 among A, B and C in the ratio , I divided the sum in the ratio 2 : 3 : 4. Who gained the most and by what amount?

A
A; Rs. 28

B
B; Rs. 3

C
C; Rs. 20

D
C; Rs. 25

Solution

But the amount is divided in the ratio 2 : 3 : 4.
A gets 2x.
B gets 3x.
C gets 4x.
According to the question,
2x + 3x + 4x = 117
9x = 117
x = 13,
A gets: 2x = 2 × 13 = Rs. 26
B gets: 3x = 3 × 13 = Rs. 39
C gets: 4x = 4 × 13 = Rs. 52
C gained the most amount by (52 - 27) = Rs. 25.
Answer: (4)
Question 7
1 / -0

A bag contains 25 paise, 10 paise and 5 paise coins in the ratio 1 : 2 : 3. If the total value of the coins in the bag is Rs. 36, the number of 25 paise coins is

A
120

B
63

C
70

D
60

Solution

Let the number of 25 paise coins be x.
∴ Number of 10 paise coins = 2x
∴ Number of 5 paise coins = 3x
Total value of coins = 25x + 10 × 2x + 5 × 3x = 3600 paise … (1)
⇒ 25x + 20x + 15x = 3600
⇒ x = 3600/60 = 60
∴ Number of coins of 25 paise = 60
Question 8
1 / -0

If the average age of mother and her daughter is 34.5 years while the age of the daughter is half that of the mother, what is mother's age?

A
48 years

B
69 years

C
56 years

D
46 years

Solution

Let the ages of the mother and her daughter be "X" and "Y" years, respectively.
Thus, [(X + Y) ÷ 2] = 34.5
⇒ (X + Y) = 69 --- (i)
Total age of mother and daughter = 69
Further, Daughter's age = Mother's age/2
Y = X ÷ 2
⇒ X = 2Y --- (ii)
Put the value of X from eq. (ii) in eq. (i).
⇒ 3Y = 69
⇒ Daughter's age = Y = 23 years
Thus, Mother's age = X = 46 years
Answer: (4)
Question 9
1 / -0

The maximum marks in a test were 1000. A scored 10% less than B, B scored 25% more than C, and C scored 20% less than D. If A scored 720 marks, then what percentage marks did D score?

A
90%

B
85%

C
80%

D
78%

Solution

A scored 720 marks.
Suppose, B scored x marks.
Then, 0.9x = 720
⇒ x = 800
Suppose, C scored y marks.
Then, 1.25y = 800
⇒ y = 640
Suppose, D scored z marks.
Then, 0.8z = 640
⇒ z = 800
So, A scored 720 marks, B scored 800 marks, while C scored 640 marks and D scored 800 marks.
So, % marks scored by D = 800/1000× 100 = 80%
Question 10
1 / -0

A mixture contains milk and water in the ratio 5 : 1. On adding 5 litres of water, the ratio of milk to water becomes 5 : 2. Find the quantity of milk in the original mixture.

A
20 litres

B
25 litres

C
30 litres

D
28 litres

Solution

Let the quantity of milk be 5X litres and that of water be X litres.
Then,
After adding 5 litres of water, ratio becomes 5 : 2.
5X/(X + 5) = 5/2
Or X = 5
⇒ Quantity of milk in the original mixture = 5X litres = 25 litres
Question 11
1 / -0

When the price of a radio was reduced by 20%, its sale increased by 80%. What was the net effect on the sale?

A
44% increase

B
44% decrease

C
66% increase

D
66% increase

Solution
Question 12
1 / -0

A and B can do a piece of work in 30 days, B and C can do the same work in 24 days and C and A can do the same in 20 days. They all work for 10 days before B and C leave. How many more days will A take to finish the work?

A
26 days

B
22 days

C
18 days

D
14 days

Solution

Suppose A, B and C take x, y and z days, respectively.
Question 13
1 / -0

Mona has two taps near her swimming pool. Tap X can fill the pool in 36 minutes, Tap Y can fill the same pool in 48 minutes. If they are opened simultaneously, at what time tap Y (keep tap X running) can be stopped so that the tank can be filled completely in 27 minutes?

A
After 27 minutes

B
After 39 minutes

C
After 12 minutes

D
After 25 minutes

Solution

Tap X can fill the pool in 36 minutes which means that 1/36^th of the pool will be filled up in a minute.
Tap Y can fill the pool in 48 minutes which means that 1/48^th of the pool will be filled up in a minute.
Given that tap X is open for 27 minutes,
So, (27/36) or (3/4) of the pool will be filled and tap Y has to fill the remaining (1/4)^th of the pool.
Y will fill the entire pool in 48 minutes and for it to fill (1/4)^th of the pool it will take (48/4) = 12 minutes
Question 14
1 / -0

Simple interest on a certain sum for 3 years at 4% p.a. is Rs. 303.60. If the amount was kept at compound interest compounded annually, the difference between compound interest and simple interest would be

A
Rs. 12.31

B
Rs. 12.91

C
Rs. 13.91

D
Rs. 14.11

Solution

Time = T = 3 years
Rate = R = 4%
Simple interest = SI = Rs. 303.60
P = Principal

= Rs. 315.91
Difference between CI and SI = Rs. 315.91 - Rs. 303.60 = Rs. 12.31
Question 15
1 / -0

A train, 280 metres long, is moving at 60 km per hour. The time taken by the train to cross a 220-metre long platform is

A
20 seconds

B
25 seconds

C
30 seconds

D
35 seconds

Solution