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MAT (Stage-1) Mock Test - 36

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MAT (Stage-1) Mock Test - 36
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  • Question 1
    1 / -0

    In the following problem, a question is followed by statements I, II and III. Read all the statements carefully and find which of them is/are sufficient to answer the given question. Choose your answer accordingly.

    What is the code of 'in' in the given code language?

    Statements:
    I. 'huh an ho' means 'ball in bag'.
    II. 'ho lue gei' means 'water in glass'.
    III. 'yo mei li ho an gei' means 'how are you in water bag'.

    Solution

    From I and II, it is clear that 'in' is coded as 'ho'.
    So, only statements I and II are required to answer the question.

     

  • Question 2
    1 / -0

    In the following problem, a question is followed by statements I, II and III. Read all the statements carefully and find which of them is/are sufficient to answer the given question.'

    In a certain code, PYC means 'we are friends'. Which of the following letters stands for 'we'?

    Statements:
    I. XYZ means 'they are classmates'.
    II. CMS means 'we love them'.
    III. PR means 'hello friends'.

    Solution

    Given question statement: PYC means we are friends.
    Statement I: XYZ means 'they are classmates'.
    Statement II: CMS means 'we love them'.
    Statement III: PR means 'hello friends'.
    From II and question statement, C means 'we'.
    Or
    From I, III and question statement, Y means 'are' and P means 'friends', which implies that C means 'we'.

     

  • Question 3
    1 / -0

    If `white` is called `blue`, `blue` is called `red`, `red` is called `yellow`, `yellow` is called `green`, `green` is called `black`, `black` is called `violet` and `violet` is called `orange`, then what would be the colour of human blood?

    Solution

    Human blood is red in colour. But, red is called yellow. So, the colour of human blood is called yellow.

     

  • Question 4
    1 / -0

    In a certain code language, 39574 is written as XPLMD and 0826 is written as TBNQ. How will DBMTX be written in the same language?

    Solution

    Here, 39574 is written as XPLMD and 0826 is written as TBNQ.
    According to the given data,
    X >> 3
    P >> 9
    L >> 5
    M >> 7
    D >> 4
    T >> 0
    B >> 8
    N >> 2
    Q >> 6
    Hence, DBMTX will be written as 48703.

     

  • Question 5
    1 / -0

    In a certain code language,

    (i) '786' means 'study very hard'
    (ii) '958' means 'hard work pays'
    (iii) '645' means 'study and work'

    Which of the following is the code for 'very'?

    Solution

    In the first and second statements, the common digit is '8' and the common word is 'hard'. So, '8' means 'hard'. In the first and third statements, the common digit is '6' and the common word is 'study'. So, '6' means 'study'.
    Thus, in the first statement, '7' stands for 'very'.

     

  • Question 6
    1 / -0

    Find the missing term.

    3 7 6
    4 ? 8
    5 25 10
    Solution

    The pattern is followed columnwise.
    In every column, all numbers form triplets.
    3, 4, 5 and 6, 8, 10 form triplets.
    So, ? = 24 to form the triplet 7, 24, 25.

     

  • Question 7
    1 / -0

    Find the missing term.

    40 18 72
    20 3 ?
    2 6 4
    Solution

    The sequence is
    40/2 = 20
    18/6 = 3
    Similarly,
    72/4 = 18

     

  • Question 8
    1 / -0

    A man has 7 friends. The 1st one visits him every night, the 2nd every 2nd night, the 3rd every 3rd night, the 4th every 4th night and so on. After how many days will all the friends meet together?

    Solution

    They will meet together after that number of days which is the minimum common multiple of frequencies of meeting of all the seven friends (i.e. LCM of 1, 2, 3, 4, 5, 6, 7) = 420

     

  • Question 9
    1 / -0

    What is the least number by which 825 must be multiplied in order to get a multiple of 715?

    Solution

    825 = 3 × 5 × 5 × 11
    715 = 5 × 11 × 13
    In 825, 13 is missing. All the rest of the factors of 715 are present in 825.

     

  • Question 10
    1 / -0

    Find the greatest number which when divides 166, 199 and 298, leaves the same remainder in each case.

    Solution

    Let the remainder in each case be r.
    A = 166 - r, B = 199 - r and C = 298 - r
    A, B, and C should be divisible by the common highest divisor.
    Hence, it must be the HCF of the above numbers.
    If A, B and C are divisible by this number, then B - A and C - B must also be divisible by this number.
    B - A = 199 - r - 166 + r = 33
    C - B = 298 - r - 199 + r = 99
    33 and 99 must be divisible by this number.
    ∴The required number is 33.
    (Cross-check: 166, 199 and 298, when divided by 33, leave remainder = 1)

    Alternative method:
    Greatest number = HCF of (199-166, 298 -166, 298-199) = HCF of (33, 132, 99) = 33

     

  • Question 11
    1 / -0

    A given work can be completed by A in 20 days and by B in 30 days, working separately. In how many days can they complete the work together?

    Solution

    One day work of A = 1/20
    One day work of B = 1/30
    (A + B)' s 1 day work = (1/20) + (1/30) = 5/60 = 1/12
    They can complete the work in 12 days.

     

  • Question 12
    1 / -0

    A alone can do a piece of work in 6 days and B alone can do it in 8 days. How many days will it take for A and B together to finish the work?

    Solution

    A can do 1/6th of the given work in one day and B can do 1/8th of the same work in one day.
    Together they can do 1/6 + 1/8 = 7/24th work in one day.
    ∴ They can complete the work in 24/7 days.

     

  • Question 13
    1 / -0

    Two cyclists left Agra for Aligarh simultaneously. The first cyclist stopped after 42 min, when he was 1 km short of Aligarh and the other one stopped after 52 min, when he was 2 km short of Aligarh. If the first cycled as many kilometres as the second, the first one would need 17 min less than the second. Find the distance between Agra and Aligarh.

    Solution

    Let distance between Agra and Aligarh be x km.
    First cyclist covered (x - 1) km in 42 min.
    Second cyclist covered (x - 2) km in 52 min.
    First cyclist will take (52 - 17)
    i.e. 35 min to cover (x - 2) distance.
    ∴ This means first cyclist covers 1 km in 7 min.
    ∴ In 42 min, he will cover 6 km.
    ∴ x - 1 = 6
    x = 7

     

  • Question 14
    1 / -0

    Two trains are running at 72 km/h and 48 km/h in the same direction. The faster train completely passes a man, sitting in the slower train, in 15 sec. Find the length of the faster train.

    Solution

    Relative speed in the same direction = 72 – 48 = 24 km/h
    Therefore, length of the train = Speed × Time = 24 km/h × 15 sec
    = 24(5/18) m/s × 15 sec
    = 24(5/18) × 15 = 100
     

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