MAT (Stage-1) Mock Test

Result

MAT (Stage-1) Mock Test - 63

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Question 1
1 / -0

Choose the option that will replace the question mark (?) in the figure given below.

A
20

B
32

C
24

D
96

Solution

(7 + 8 + 9) = 24

(6 + 8 + 10) = 24

So, the missing number is (12 + 4 + 8) = 24.
Question 2
1 / -0

Choose the option that will replace the question mark (?) in the figure given below.

A
12

B
120

C
40

D
17

Solution

(3 × 4 × 5) = 60
(5 × 7 × 2) = 70
Missing number = 10 × 4 × 3 = 120
Question 3
1 / -0

The average mark of 9 students in a group is 63. Three of them scored 78, 69 and 48 marks, respectively. What is the average mark of remaining 6 students?

A
63.5

B
62.5

C
63

D
62

Solution
Question 4
1 / -0

Which of the following is the smallest number, which when divided by 20, 30, 40 and 50, leaves remainders 8, 18, 28 and 38, respectively?

A
488

B
588

C
688

D
788

Solution

As difference between (20 - 8) = (30 - 18) = (40 - 28) = (50 - 38) = 12

So, required number = LCM (20, 30, 40, 50) - 12 = 600 - 12 = 588
Question 5
1 / -0

A train travelling from A to B meets with an accident after 1 hour. After the accident, it moves at four-fifths of the former speed and arrives 2 hours late. If the train had covered 80 km more before the accident, then it would have been just 1.5 hours late. Find the original speed of the train.

A
60 kmph

B
40 kmph

C
80 kmph

D
None of these

Solution

Let the speed of the train be 'x' kmph and the distance covered after the accident be 'y'.
According to the question,

y = 8x
y - 8x = 0 ... (1)
Now, if the train had covered 80 km more before the accident,

y - 80 = 6x
y - 6x = 80 ... (2)
From (1) and (2), x = 40
Therefore, speed of the train = 40 kmph
Question 6
1 / -0

Find the profit gained in the two transactions if a person sells 2/3 of a product with a profit of 20% and rest of the product at the cost price.

A
10%

B
13.33%

C
15%

D
12.50%

Solution

Let the product quantity be 3i.
Let the cost price of this quantity of product be 3c.
As, 2i of product is sold at a profit of 20%, the cost of which is 2c, sales revenue for 2i of product = 1.2 × 2c = 2.4c.
Now, i of the product is sold at c.
Thus, total sales revenue of the product = 2.4c + c = 3.4c.
So, profit % = (3.4c - 3c)/3c × 100% = (0.4/3) × 100% = 13.333%
Question 7
1 / -0

A book, if sold at Rs. 38.5, gives a profit of 10%. If it was sold at Rs. 40, what would be the profit %?

A
14.28%

B
14.56%

C
15.26%

D
13.46%

Solution

According to the question,
Selling price of book = Rs. 38.5
Profit = 10%

When the selling price is Rs. 40, then
Profit = selling price - cost price = 40 - 35 = Rs. 5
Therefore,
Profit% = 5/35 × 100 = 100/7 = 14.28%
Hence, this is the required result.
Question 8
1 / -0

The price of a necklace is Rs. 2,00,000. After two successive discounts, it is sold for Rs. 1,39,400. If the first discount is 15%, what is the rate of the second discount?

A
17%

B
18%

C
19%

D
20%

Solution

Marked price = Rs. 2,00,000

Reduced price after the first discount = Rs. 2,00,000 - Rs. 30,000 = Rs. 1,70,000
Second discount = Rs. 1,70,000 - Rs. 1,39,400 = Rs. 30,600
Question 9
1 / -0

In a simultaneous roll of two dice, the probability of getting a total of 7 is

A
1/7

B
7/36

C
1/4

D
1/6

Solution

Total number of possible outcomes = (6)² = 36

Favourable cases = (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6

Required probability = 6/36 = 1/6.
Question 10
1 / -0

A man buys a horse and a sheep for $4500. He sells the horse at a profit of 20% and the sheep at a profit of 5%. Find the cost price of the horse if his overall profit is 17.5%.

A
$3000

B
$3250

C
$3750

D
$900

Solution

Applying the rule of alligation:
Question 11
1 / -0

Find the principal if the interest on that principal, at the end of 5 years at 6% p.a., is the same as the interest on Rs. 1120 at the end of 18 months at 10% p.a.

A
Rs. 500

B
Rs. 560

C
Rs. 1120

D
None of these

Solution
Question 12
1 / -0

If the amount is times the sum after 2 years at compound interest, then the rate of interest per annum is

A
25%

B
30%

C
40%

D
50%

Solution
Question 13
1 / -0

A train, 150 metres long, passes through a tunnel at a rate of 72 kmph in 20 seconds. What is the length of the tunnel?

A
200 m

B
225 m

C
230 m

D
250 m

Solution

Speed of the train = 72 kmph = 72 × 5/18 = 20 m/s

Let L be the length of the tunnel in metres.

Then, 20 = (150 + L)/20 or L = 250 metres

Hence, length of tunnel = 250 metres
Question 14
1 / -0

A train, 350 m long, travelling at a speed of 120 kmph crosses a platform in 24 sec. A man going at a certain speed crosses the platform in 3 min. What is the speed of the man?

A
6 kmph

B
7 kmph

C
8 kmph

D
9 kmph

Solution

Let the length of the platform be x m.
Given, length of the train = 350 m
Distance travelled = (x + 350) m
Time taken = 24 s
Speed in mps = 120 × 5/18 mps = 100/3 mps
Distance = Speed × Time
x + 350 = 24 × 100/3
x + 350 = 800
x = 450
Speed of the man = Distance/Time
Distance = 450 m
Time = 3 × 60 s = 180 s
Question 15
1 / -0

A contractor employs 200 men to build a dam. They finish 5/6 part of the work in 10 weeks. Due to rain, the work remains suspended for 4 weeks and also half of the work already done is washed away. When the work is resumed, only 140 men turn up. The total time in which the contractor is able to complete the work is (Assuming there are no further disruptions)

A
25 weeks

B
26 weeks

C
24 weeks

D
22 weeks

Solution

The work remains suspended for 4 weeks and 1/2 of 5/6 work done is washed away.

Therefore, they have to do 1 – 5/12 = 7/12 of work

x = 10 weeks

Therefore, required time = 10 + 4 + 10 = 24 weeks