SAT (Stage-1) Mock Test - 54

For the convex lens focal length is f₁ = 80 cm or 0.8 m and for concave lens focal length is f₂ = -50 cm or -0.5 m

Let the focal length of the combination is f, then

Magnetic field around the straight current carrying wire is given by:

According to Fleming's left hand rule, if we stretch the thumb, first finger and second finger such that they are perpendicular to each other, the first finger gives the direction of the magnetic field, second finger gives the direction of the motion of the positive charge particle then the thumb will give the direction of the force exerted by the magnetic field on the positive charge particle. So when a proton is projected vertically downward in a uniform magnetic field which is horizontal and north ward in direction. the proton will be deflected eastwards.

A bar magnet slowly approaches a coil with the North Pole facing it. The nearer end of the coil behaves like North pole. When a magnet approaches the coil the number of the magnetic field lines linked with the coil increases hence magnetic flux linked with it increases, according to Lenz's law, current will be in induced in such a way that it will try oppose the increasing magnetic flux or we say it will oppose the motion of the approaching North pole so the near end of the coil behaves as north pole.

When the bar magnet is slowly withdrawn, the nearer end of the coil behaves like South pole. When a magnet is receding away from the coil the number of the magnetic field lines linked with the coil decreases hence magnetic flux linked with it decreases. According to Lenz's law, current will be in induced in such a way that it will try oppose the decreasing magnetic flux or we say it will oppose the motion of the receding North pole so the near end of the coil behaves as south pole.

As the water drops are falling at regular intervals for the three succesive drops,

The time interval for the 1^st drop (Near to the roof) in air is one second.

The time interval for the 2^nd drop in air is two seconds.

The time interval for the 3^rd drop in air is three seconds.

Initial velocities of the all the drops is zero, u = 0 and a = g (Taking downward direction to be positive)

Hence, s₁ : s₂ : s₃ :: 1: 3 : 5

It is given that the distance travelled by the object in the 5th and 6th seconds are the same.
It means that the object will reach the highest point in 5 seconds.
Using v = u + at
v = 0, a = -9.8 m/s² and t = 5 sec
0 = u - 9.8 × 5
⇒ u = 49 m/s

Taking upward direction as positive, let the displacement of the balloon after 8 seconds is H and its velocity after 8 seconds will be v, then

Using

When the stone is released from the balloon after 8 sec, the velocity of the stone w.r.t earth will be same as that of balloon. When it reaches the ground the displacement of the stone = -40 m and as it is moving under the action acceleration due to gravity,

Using

Neglecting the negative value, time taken to reach the ground is 4 seconds.

Up thrust acting on the ball = weight of the water displaced (W)

Weight of the water displaced, W = ρVg; ρ is the density of the water, V is the volume of the ball.

W = 1 × 50 × g = 50 g

Hence up thrust acting on the ball = 50 g. An equal amount of force will be acting on the fluid in downward direction.

Reading of the weighing balance = 600 g + 50 g = 650 g

When the temperature of 1 kg of water is raised from 30°C to 140°C then there will be a change in the physical state of water.

During the phase conversion, some of the heat supplied is used up to overcome the intermolecular forces of attraction, in order to bring about the phase conversion. This heat remains latent and is not visible in the form of temperature rise.

The boiling point of water depends on the atomspheric pressure. It is 373 K at the sea level and decreases with the decrease in the atmospheric pressure. Thus the boiling point of water decreases with the increase in the altitudes.

Hence, the options I, III and IV are correct.

However, the option II is incorrect as there is no chemical change involved when water is heated.

Cl (Z = 17)

Electronic configuration: 1s², 2s², 2p⁶, 3s², 3p⁵

Total number of electrons in the s orbitals is 6.

Na₂CO₃ is a salt of a strong base, NaOH and a weak acid, H₂CO₃; thus it is a basic salt.

Its aqueous solution will hydrolize as follows and will yield a strong base and a weak acid.

Na₂CO₃ + 2H₂O → 2NaOH + H₂CO₃

The aqueous solution of Na₂CO₃ will turn the red litmus blue.

The percentage of carbon can be calculated as 

Moreover, the compounds having the same empirical formula will have the same percentage composition.

The empirical formula of both the compounds, acetic acid and glucose is the same, i.e. CH₂O. So the percentage of C in both will also be the same.

The colour of the hydrangea flower depends on the nature of the soil.
It is pink in basic soil and blue in acidic soil.
Pink colour of the flower indicates basic soil, hence pH > 7.
Hence, the statement I is correct.
On adding organic manure, the soil becomes acidic due to the acid produced by the bacteria that decompose the organic matter. Therefore the colour of the soil changes to blue.
Hence, the statement II is correct.

When Silver Bromide is exposed to sunlight, it decomposes to form Silver Metal and Bromine vapours.

Since the decomposition is carried out using light energy, it is called photolysis.