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SAT (Stage-1) Mock Test - 62

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SAT (Stage-1) Mock Test - 62
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following statements is/are false?

    a. The process of diffusion is a slow process.
    b. Xylem and phloem are present in all parts of the plant body.
    c. Movement of minerals and water takes place from the leaves to the other parts of plants.

    Solution

    This is the correct option as this statement is false. Movement of minerals and water does not take place from the leaves to the other parts of plants.

     

  • Question 2
    1 / -0

    How many meiotic divisions are required to produce 10024 pollen grains?

    Solution

    As one microspore mother cell produces four pollen grains after undergoing one meiotic division, 2506 MMC will produce 2506 x 4 = 10024 pollen grains after undergoing 2506 meiotic divisions.

     

  • Question 3
    1 / -0

    In the network shown below, the ring has zero resistance. The equivalent resistance between the points A and B is

    Solution

    The given circuit can be redrawn as

    The 3 resistances of 3R are connected in parallel and their equivalent resistance in parallel is

    This equivalent resistance is in series with another resistance of value R. Hence, equivalent resistance across A and B is RAB = R + R = 2R

     

  • Question 4
    1 / -0

    Two bulbs rated 200 W, 220 V and 100 W, 220 V are connected in series. Combination is connected to a 220 V supply. Power consumed by the circuit is

    Solution

    In series, power consumed is given by

     

  • Question 5
    1 / -0

    In the circuit show below, the voltmeter is of large resistance. The emf of the cell is E. The reading of the voltmeter is

    Solution

    The given circuit can be redrawn as

    The two resistances in upper limb are in series and the two resistances in lower limb are in series.

    Equivalent resistance in upper limb is 10Ω and in lower limb, the equivalent resistance is also equal to 10Ω.

    Total resistance across AB is 5Ω (Parallel combination of two 10Ω and 10Ω resistances)

    Current in the circuit will be I = E/5 A, which will be equally divided into two limbs i.e. I = E/10 A in each limb.

    We can consider point B = 0 V

    Using Ohm's law, we get

     

  • Question 6
    1 / -0

    The current in a simple series circuit is 5.0 A. When an additional resistance of 2.0 Ω is inserted, the current drops to 4.0 A. The original resistance of the circuit in ohms was

    Solution

     

  • Question 7
    1 / -0

    In the network shown below, each resistance is equal to R. The equivalent resistance between diagonally opposite corners is

    Solution

    As all the resistances are the same, this circuit can be considered as the balanced wheat stone bridge. No current will flow from B to D diagonally.

    The two resistances in each limb are connected in series. Hence, equivalent resistance in each limb is 2R.

    Equivalent resistance across A and C

     

  • Question 8
    1 / -0

    If the density of a small planet is the same as that of Earth, while the radius of the planet is 0.2 times that of Earth, then the gravitational acceleration near the surface of that planet is

    Solution

    The acceleration due to gravity at the surface of the planet having mass M and radius R is given by

     

  • Question 9
    1 / -0

    An underwater fish views obliquely a fisherman standing on the bank of a lake. To the fish, the man looks

    Solution

    When a ray from man O in air (rarer medium) goes to water (denser medium), then it bends towards the normal. Extend MN backwards meet at point O'. Therefore, it appears to the fish as if the man is taller than what he actually is.

     

  • Question 10
    1 / -0

    Two thin equiconvex lenses, each of focal length 0.2 m, are placed coaxially with their optic centres 0.5 m apart. What is the focal length of the combination?

    Solution

    Equivalent focal length (F) of two lens separated by distance d is given by

     

  • Question 11
    1 / -0

    A plane glass slab is kept over various colour letters. The letter which appears least raised is

    Solution

    So, we can say that the lesser the refractive index, the greater the apparent depth. Hence, the colour letters which have more apparent depth will be least raised.

    Secondly, refractive index depends upon the wavelength. The greater the wavelength, the lesser the refractive index.

    Hence, the glass slab has the least refractive index for the red colour because it has the largest wavelength among the given and red colour letters will be least raised.

     

  • Question 12
    1 / -0

    Which of the following statements is incorrect?

    Solution

    Power is defined as the ability to converge the parallel beam of light. For a converging lens (convex lens), power is positive. Power of the diverging lens (concave lens) is taken as negative.

     

  • Question 13
    1 / -0

    An object is placed at the centre of curvature of a concave mirror of focal length 16 cm. If the object is shifted by 8 cm towards the focus, then the nature of the image would be

    Solution

    An object is placed at the centre of curvature of a concave mirror of focal length 16 cm, i.e. at 32 cm from the pole. If the object is shifted by 8 cm towards the focus, then the object will be at 24 cm from the pole, i.e. between centre of curvature and focus. So, real, inverted and magnified image is produced.

     

  • Question 14
    1 / -0

    If two parallel conductors A and B of equal lengths carry currents I and 10I, respectively in the same direction, then

    Solution

    Force between two straight current carry conductors in same direction is attractive in nature and force between two straight current carry conductors in opposite directions is repulsive in nature. Each conductor exerts equal and opposite force on each other.

     

  • Question 15
    1 / -0

    A charged particle moves along the line AB, which lies in the same plane of a circular loop of conducting wires as shown in the figure. Then,

    Solution

    As the charge particle moves from A to B, the flux linked with the loop will first increase and current will be induced in such a way that it will try to decrease the increasing magnetic flux (in accordance with Lenz's law). As the charge passes away, the magnetic flux will decrease and current will induce in such a way that it will try to increase the decreasing magnetic flux. Hence, current will change the direction as the charge passes away.

     

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