NTSE - MAT-2015

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NTSE - MAT-2015

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Weekly Quiz Competition

Question 1

1 / -0

Directions For Questions

Directions: Read the following information carefully and answer the question that follows:

A, B, C, E, F, G and H are seven employees in an organization working in the departments of Administration, Accounts and Operations. There are at least two employees in each department. Each of seven employees earns different amount. The only bearded employee F works in Administration and his only other colleague G earns the maximum. C, the last earner, works in Accounts. B and E are brothers and do not work in the same department. A, the husband of H, works in Accounts and earns more than each of F, B and E. The wife in the couple earns more than the husband.

...view full instructions

Which of the following can be a group of females?

GCE

GEH

GCH

GHB

Solution

Number of employee = 7
Number of department = 3

Use the given information in the following sequence:
1. The only bearded employee F works in Administration and his only other colleague G earns the maximum.

G > A, B, C, E, F, H Earning
G, F :- Administration

2. C, the last earner, works in Accounts. A, the husband of H, works in Accounts and earns more than each of F, B and E. The wife in the couple earns more than the husband.
A > F, B, E > C Earning
The wife in the couple earns more than the husband.
H is the wife of A, So, H earns more than A.
H > A > F, B, E > C
C, A :- Accounts

3. B and E are brothers and do not work in the same department. There are at least two employees in each department.
From 1 it is clear that there are only 2 employees in Administration, i.e. G, F
Between B and E if B works in Accounts, then E work in Operations vice versa.
B : Operation, E : Accounts
OR
B : Accounts , E : Operation
Till now only 1 person works in Operation. So, H must be working in Operations.

After combining 1 and 2 we get,
G > H > A > F, B, E > C

Employee	Department	Earning	Earning Rank
A(Male)	Accounts	Less than G and H	3
B(Male)	Operation/Accounts	-	4 or 5 or 6
C	Accounts	Minimum	7
E(Male)	Operation/Accounts	-	4 or 5 or 6
F	Administration	-	4 or 5 or 6
G	Administration	Maximum	1
H(Female)	Operation	Less than G	2

From the given options only option 3 is the correct answer. Because B and E are brothers.

Question 2

1 / -0

Directions For Questions

Directions: Read the following information carefully and answer the question that follows:

...view full instructions

In which of the following departments do three employees work?

Operations

Accounts

Operations or Accounts

Data inadequate

Solution

Number of employee = 7
Number of department = 3

Use the given information in the following sequence:
1. The only bearded employee F works in Administration and his only other colleague G earns the maximum.

G > A, B, C, E, F, H Earning
G, F:- Administration

2. C, the last earner, works in Accounts. A, the husband of H, works in Accounts and earns more than F, B and E. The wife in the couple earns more than the husband.
A > F, B, E > C Earning
The wife in the couple earns more than the husband.
H is the wife of A, So, H earns more than A.
H > A > F, B, E > C
C, A:- Accounts

3. B and E are brothers and do not work in the same department. There are at least two employees in each department.
From 1 it is clear that there are only 2 employees in Administration, i.e. G, F
Between B and E if B work in Accounts, then E work in Operations vice versa.
B : Operation, E : Accounts
OR
B : Accounts, E : Operation
Till now only 1 person works in Operations. So, H must be working in Operations.

After combining 1 and 2, we get
G > H > A > F, B, E > C

Employee	Department	Earning	Earning Rank
A(Male)	Accounts	Less than G and H	3
B(Male)	Operation/Accounts	-	4 or 5 or 6
C	Accounts	Minimum	7
E(Male)	Operation/Accounts	-	4 or 5 or 6
F	Administration	-	4 or 5 or 6
G	Administration	Maximum	1
H(Female)	Operation	Less than G	2

From the table, it is clear that A, C, B or E are the three employees working in the Accounts department.

Question 3

1 / -0

Directions For Questions

Directions: Read the following information carefully and answer the question that follows:

...view full instructions

What will be the position of A from the top when they are arranged in descending order of their incomes?

Second

Third

Fourth

Fifth

Solution

Number of employee = 7
Number of department = 3

Use the given information in the following sequence:
1. The only bearded employee F works in Administration and his only other colleague G earns the maximum.

G > A, B, C, E, F, H Earning
G, F:- Administration

2. C, the last earner, works in Accounts. A, the husband of H, works in Accounts and earns more than F, B and E. The wife in the couple earns more than the husband.
A > F, B, E > C Earning
The wife in the couple earns more than the husband.
H is the wife of A, So, H earns more than A.
H > A > F, B, E > C
C, A:- Accounts

3. B and E are brothers and do not work in the same department. There are at least two employees in each department.
From 1 it is clear that there are only 2 employees in Administration, i.e. G, F
Between B and E if B work in Accounts, then E work in Operations vice versa.
B : Operation, E : Accounts
OR
B : Accounts, E : Operation
Till now only 1 person works in Operations. So, H must be working in Operations.

After combining 1 and 2, we get
G > H > A > F, B, E > C

Employee	Department	Earning	Earning Rank
A(Male)	Accounts	Less than G and H	3
B(Male)	Operation/Accounts	-	4 or 5 or 6
C	Accounts	Minimum	7
E(Male)	Operation/Accounts	-	4 or 5 or 6
F	Administration	-	4 or 5 or 6
G	Administration	Maximum	1
H(Female)	Operation	Less than G	2

From the tables, A is the third.

Question 4

1 / -0

Directions For Questions

Directions: Read the following information carefully and answer the question that follows:

...view full instructions

In which of the following departments does B work?

Operations

Accounts

Administration

Data inadequate

Solution

Number of employee = 7
Number of department = 3

Use the given information in the following sequence:
1. The only bearded employee F works in Administration and his only other colleague G earns the maximum.

G > A, B, C, E, F, H Earning
G, F:- Administration

2. C, the last earner, works in Accounts. A, the husband of H, works in Accounts and earns more than F, B and E. The wife in the couple earns more than the husband.
A > F, B, E > C Earning
The wife in the couple earns more than the husband.
H is the wife of A, So, H earns more than A.
H > A > F, B, E > C
C, A :- Accounts

3. B and E are brothers and do not work in the same department. There are at least two employees in each department.
From 1 it is clear that there is only 2 employee in Administration, i.e. G, F
Between B and E if B work in account then E work in Operations vice versa.
B : Operation, E : Accounts
OR
B : Accounts, E : Operation
Till now only 1 person works in Operation. So, H must be working in Operations.

After combining 1 and 2, we get
G > H > A > F, B, E > C

Employee	Department	Earning	Earning Rank
A(Male)	Accounts	Less than G and H	3
B(Male)	Operation/Accounts	-	4 or 5 or 6
C	Accounts	Minimum	7
E(Male)	Operation/Accounts	-	4 or 5 or 6
F	Administration	-	4 or 5 or 6
G	Administration	Maximum	1
H(Female)	Operation	Less than G	2

From the given data we cannot find the exact Department of B.

Question 5

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Directions For Questions

Directions: Read the following information carefully and answer the question that follows:

...view full instructions

Which of the following statements is definitely true?

B earns less than F and H.

F earns more than B and E.

B earns more than E and C.

B earns less than A and H.

Solution

Number of employee = 7
Number of department = 3

Use the given information in the following sequence:
1. The only bearded employee F works in Administration and his only other colleague G earns the maximum.

G > A, B, C, E, F, H Earning
G, F:- Administration

2. C, the last earner, works in Accounts. A, the husband of H, works in Accounts and earns more than F, B and E. The wife in the couple earns more than the husband.
A > F,B,E > C Earning
The wife in the couple earns more than the husband.
H is the wife of A, So, H earns more than A.
H > A > F, B, E > C
C, A:- Accounts

3. B and E are brothers and do not work in the same department. There are at least two employees in each department.
From 1 it is clear that there are only 2 employees in Administration, i.e. G, F
Between B and E if B work in Accounts, then E work in Operations vice versa.
B : Operation, E : Accounts
OR
B : Accounts, E : Operation
Till now only 1 person works in Operations. So, H must be working in Operations.

After combining 1 and 2, we get
G > H > A > F, B, E > C

Employee	Department	Earning	Earning Rank
A(Male)	Accounts	Less than G and H	3
B(Male)	Operation/Accounts	-	4 or 5 or 6
C	Accounts	Minimum	7
E(Male)	Operation/Accounts	-	4 or 5 or 6
F	Administration	-	4 or 5 or 6
G	Administration	Maximum	1
H(Female)	Operation	Less than G	2

Using G > H > A > F, B, E > C
It is clear that B earn less than A and H.

Question 6
1 / -0

Directions For Questions

Directions: Given an input, a machine generates pass codes for six batches each day as follows:

Input: these icons were taken out from the sea

Pass codes

Batch I: from sea the out taken were icons these
Batch II: from icons these were taken out the sea
Batch III: from icons out sea the taken were these
Batch IV: from icons out sea these were taken the

...view full instructions

What will be the pass code for the batch V on a day, if the input is 'four of the following five form a group'?

A
a five following form four group the of

B
a five following form group the of four

C
a five following form four of the group

D
a five following form four group of the

Solution

Logic: One word is arranged in an alphabetical order in each batch and the rest of the words being written in a reverse order.
i.e. Pass code: "these icons were taken out from the sea"
The word 'from' comes first in alphabetical order, and the remaining "these icons were taken out the sea" should be written in reverse order. So, the output is
'from sea the out taken were icons these'
Similar code is applied for all batches.

Input: four of the following five form a group
Batch I: a group form five following the of four
Batch II: a five four of the following form group
Batch III: a five following group form the of four
Batch IV: a five following form four of the group
Batch V: a five following form four group the of
Question 7
1 / -0

Directions For Questions

Directions: Given an input, a machine generates pass codes for six batches each day as follows:

Input: these icons were taken out from the sea

Pass codes

Batch I: from sea the out taken were icons these
Batch II: from icons these were taken out the sea
Batch III: from icons out sea the taken were these
Batch IV: from icons out sea these were taken the

...view full instructions

If the pass code for the batch IV on a day was 'back go here people who settle want to', what was the pass code for the batch V on that day?

A
back go here people settle who want to

B
back go here people to want settle who

C
back go here people settle to want who

D
Cannot be determined

Solution

Logic: One word is arranged in an alphabetical order in each batch and the rest of the words being written in a reverse order.
i.e. Pass code: "these icons were taken out from the sea"
The word 'from' comes first in alphabetical order, and the remaining "these icons were taken out the sea" should be written in reverse order. So, the output is
'from sea the out taken were icons these'
Similar code is applied for all batches.

Pass code for Batch IV is 'back go here people who settle want to'
In the above pass code four words (back go here people) are arranged in previous batches, so we need to check the reaming words (who settle want to). In this arrangement 'settle' should come first and the remaining words come in reverse order.
So, the Batch V is: 'back go here people settle to want who'
Question 8
1 / -0

Directions For Questions

Directions: Given an input, a machine generates pass codes for six batches each day as follows:

Input: these icons were taken out from the sea

Pass codes

Batch I: from sea the out taken were icons these
Batch II: from icons these were taken out the sea
Batch III: from icons out sea the taken were these
Batch IV: from icons out sea these were taken the

...view full instructions

The pass code for the batch I on a day was 'he so used to sell the surplus items'. What was the input on that day?

A
items surplus the sell to used so he

B
he items surplus the sell to used so

C
so used to sell the surplus items he

D
Cannot be determined

Solution

The input may be obtained by writing all words, except 'he', in the given pass code in the reverse order and then placing 'he' at any of the seven positions.
So, there are seven possible inputs.
Thus, it is not possible to determine the exact input.
Question 9
1 / -0

In a certain code language, 'po ki top ma' means 'Usha is playing cards', 'Kop ja ki ma' means 'Asha is playing tennis', 'ki pop sop ho' means 'They are playing football' and 'po sur kop' means 'Cards and tennis'. What is the code for 'Asha'?

A
ja

B
ma

C
kop

D
top

Solution

In the first and second statements, the common code words are 'ki' and 'ma' and the common words are 'is' and 'playing'.
So, 'ki' and 'ma' can be the codes for 'is' and 'playing'.
In the second and fourth statements, the common code word is 'kop' and the common word is 'tennis'.
So, 'kop' stands for 'tennis'.
Thus, in the second statement, 'ja' stands for 'Asha'.
Question 10
1 / -0

Find the missing numbers in the following sequence:

3, 6, 24, 30, 63, 72, ?, ?, 195, 210

A
117, 123

B
120, 132

C
123, 135

D
135, 144

Solution

There are 2 series hidden in the given question.
The first series is:
3, 24, 63, V1, 195
Looking at this series,
1 x 3 = 3
Now, 1 + 3 = 4 and 3 + 3 = 6
4 x 6 = 24
Now, 4 + 3 = 7 and 6 + 3 = 9
7 x 9 = 63
Now, 7 + 3 = 10 and 9 + 3 = 12
V1 = 10 x 12 = 120
Now, 10 + 3 = 13 and 12 + 3 = 15
13 x 15 = 195
The second series is:
6, 30, 72, V2, 210
6 = 2 x 3
2 + 3 = 5 and 3 + 3 = 6
5 x 6 = 30
5 + 3 = 8 and 6 + 3 = 9
8 x 9 = 72
8 + 3 =11 and 9 + 3 = 12
11 x 12 = 132 = V2
11 + 3 = 14 and 12 + 3 = 15
14 x 15 = 210
Thus, the missing numbers are 120 and 132.
Question 11
1 / -0

Find the number that does not belong to the group.

111, 331, 482, 551, 263, 383, 362, 284

A
263

B
331

C
383

D
551

Solution

First digit x Third digit = Second digit
111: 1 x 1 = 1
331: 3 x 1 = 3
482: 4 x 2 = 8
551: 5 x 1 = 5
263: 2 x 3 = 6
383: 3 x 3 = 9 ≠ 8
362: 3 x 2 = 6
284: 2 x 4 = 8
Question 12
1 / -0

Certain blank spaces are left in the following sequence. Which of the following groups of letters will complete the sequence?

c_bba_cab_ac_ab_ac

A
acbcb

B
bcacb

C
babec

D
abebe

Solution

The sequence is 'cabbac'.

cabbaccabbaccabbac
Question 13
1 / -0

A sum of Rs. 1000 is given to A, B and C in some ratio. A is wrongly given double and C is wrongly given half, i.e. Rs. 500 and Rs. 250, respectively. How much is given to B?

A
Rs. 500

B
Rs. 250

C
Rs. 750

D
None of the above

Solution

Let the money given to A, B and C be 'A', 'B' and 'C', respectively.
A + B + C = Rs. 1000
A = Rs. 500; C = Rs. 250
So, B = Rs. 1000 – Rs. (500 + 250) = Rs. 250
B is given Rs. 250.
Question 14
1 / -0

Given that the total cost of 5 erasers, 7 sharpeners and 9 pencils is Rs. 100 and the total cost of 2 erasers, 6 sharpeners and 10 pencils is Rs. 80. What is the total cost (in Rs.) of one eraser, one sharpener and one pencil?

A
10

B
15

C
20

D
Data insufficient

Solution

According to the question,
5e + 7s + 9p = 100 … (i)
2e + 6s + 10p = 80 … (ii)
Subtracting (ii) from (i),
3e + s – p = 20 … (iii)
Adding (i) and (iii),
8e + 8s + 8p = 120
So, e + s + p = 15
Question 15
1 / -0

Stimulant : Activity : : ?

A
Symptom : Disease

B
Food : Hunger

C
Fertilizer : Growth

D
Diagnosis : Treatment

Solution

Stimulant enhances activity.
Similarly, fertilizer enhances growth.
Question 16
1 / -0

A piece of work can be completed by 40 workers in 40 days. If 5 workers leave after every 10 days, in how many days will the work be completed?

A
55.66

B
56.44

C
56.66

D
58.66

Solution

Let the work done by 1 worker in 1 day be 'w'.
Let the total work be 'W'.
Now, 40 x 40 x w = W
Or w = W/1600
Now, 40 workers work for 10 days, then 35 and so on and so forth.
Thus, (40 x 10 x W/1600) + (35 x 10 x W/1600) + ... = W
Or (1/160)(40 + 35 + ...) = 1
Or 40 + 35 + ... = 160
This is an AP with 1^st term as 40 and common difference as -5.
Let there be n such terms.
So, 160 = (n/2)(2 x 40 + (n - 1)(-5))
320 = n(80 - 5n + 5)
320 = n(85 - 5n)
Or n² - 17n + 64 = 0
n = 11.3725 or n = 5.6275
Now, taking integral values, we have
n = 11 or n = 5
Now, n = 11 is not possible as this implies that 10 x 5 = 50 workers must have left, which is greater than the total number of workers to start with, i.e. 40.
Thus, we take n = 5, which implies a total of 20 workers must have left till the end, which is possible.
Now, work done in these 50 days (5 x 10) = (W/160)(5/2(2 x 40 + (5 - 1)(-5)) = 15W/16
Now, this work was completed by having 20 workers at the end of the 50 day period.
So, workers left = 20 - 5 = 15
Let 15 workers take 'd' days to do the job.
Work left to do = W/16
So, (15 x d x W)/1600 = W/16
Or d = 6.66
Thus, total days taken = 50 + 6.66 = 56.66 days

Question 17

1 / -0

Directions For Questions

Study the following information and answer the question given below it:

Rohit, Kunal, Ashish and Ramesh are students of a school. Three of them stay far from the school and one stays near to it. Two study in class IV, one studies in class V and one in class VI. They study Hindi, Mathematics, Social Sciences and Science. One is good in all four subjects, while another is weak in all of those. Rohit stays far from the school and is good in Mathematics only, while Kunal is weak in Mathematics only and stays near to the school. Neither of those two nor Ashish studies in class VI. The one who is good in all the subjects studies in class V.

...view full instructions

Who among the following is good in all the subjects?

Rohit

Ramesh

Kunal

Ashish

Solution

-	Rohit	Kunal	Ashish	Ramesh
Class	IV	IV	V	VI
Far/Near	Far	Near	Far	Far
Subject	Good in Maths	Weak in Maths only	Good in all	Weak in all

The table given above illustrates the information given in the question and the information that can be deduced. From the table given above, it is obvious that it is Ashish who is good in all the subjects. Hence, answer option 4 is correct.

Question 18
1 / -0

Study the following information and answer the question that follows:

Half of the villagers of a certain village have their own houses. One-fifth of the villagers cultivate paddy. One-third of the villagers are literate. Four-fifth of the villagers are below twenty-five.

Which one of the following is certainly true?

A
At least 10 percent villagers who have their own houses are literate.

B
At least 25 percent of the villagers who have their own houses cultivate paddy.

C
At least 50 percent of the villagers who cultivate paddy are below twenty-five.

D
At least 13.33 percent of the total population of the village must be literate and below twenty-five.

Solution

Let the total population of the village be 30P.
Thus, 15P villagers have their own houses and 15P do not.
6P villagers cultivate paddy and 24P do not.
10P villagers are literate and 20P are illiterate.
24P villagers are below 25 and 6P are above 25.
Now, let us evaluate the statements in the answer options 1 by 1.
The answer option 1 states that at least 10% villagers who have their houses are literate.
Now, 10P villagers are literate and 15P do not have their own houses.
For argument sake, let us assume that 10P villagers who are literate are all out of those 15P villagers who do not have a house of their own.
Thus, the statement in answer option 1 needs not to be true.
Now, answer option 2 states that at least 25 percent of the villagers who have their own houses cultivate paddy.
Now, 6P villagers cultivate paddy, 15P have their own houses and 15P do not.
Again, for argument sake, let us assume that the 6P villagers who cultivate pady are all out of those 15P villagers who do not have a house of their own.
Thus, the statement in answer option 2 needs not to be true.
Now, the statement in answer option 3 states that at least 50 percent of the villagers who cultivate paddy are below 25.
Now, 6P villagers cultivate paddy, 24P are below 25 and 6P are above 25.
Again, for argument sake, let us assume that all the 6P villagers who cultivate paddy are those 6P villagers who are above 25.
Thus, the statement in answer option 3 needs not to be true.
Now, answer option 4 states that 13.33 percent of the total population of the village must be literate and above 25.
10P of the villagers are literate and 20P are illiterate.
6P are above 25 and 24P are below 25.
Now, let us assume that all those 6P villagers who are above 25 are literate.
This implies that 4P of the villagers who are literate must be below 25.
Let this be 'p' percent of the total population of the village.
Thus, 4P = p/100 x 30P
Or p = 13.33
Thus, the statement given in the answer option 4 must be true.
Question 19
1 / -0

A tank is filled by three pipes with each pipe having a constant flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe to fill the tank is

A
6 hours

B
10 hours

C
15 hours

D
30 hours

Solution

Let the tank's volume be V litres.
Let the fluid flow rate through the first pipe be 'F' litres/hours, for the second pipe be 'S' litres/hours and for the third pipe be 'T' litres/hours.
Let the time taken by the second pipe to fill the tank be 't' hours.
So, St = V...(i)
F(t + 5) = V...(ii)
T(t - 4) = V...(iii)
Also, (F + S)t₁ = Tt₁= V...(iv)
Or F + S = T...(iv)
Putting the value of 'T' from (iv) into (iii), we get
(F + S)(t - 4) = V...(v)
Now, putting the value of 'F' as V/(t + 5) from (ii) into (v), we get
(V/(t + 5) + S)(t - 4) = V
On simplifying, this equation becomes
V - 4S = V(9/(t + 5))..(vi)
Now, t = V/S (from (i)
Putting this value of 't' in (vi), the equation becomes
V - 4S = 9V/(V/S + 5) ..(vi)
Or 20S² + 8SV - V² = 0 ..(vii)
On solving for 'S', we get
S = V/10...(viii)
Putting this value of 'S' in (i), we get
t = 10
Thus, the second pipe fills the tank in 10 hours.
Hence, the first pipe fills the tank in 10 + 5 = 15 hours.
Question 20
1 / -0

One watch is 1 minute slow at 1:00 p.m. on Tuesday and 2 minutes fast at 1:00 a.m. on Friday. When did it show the correct time?

A
5:00 a.m. on Wednesday

B
9:00 a.m. on Wednesday

C
5:00 p.m. on Wednesday

D
9:00 p.m. on Wednesday

Solution

Total time lapsed from 1:00 p.m. on Tuesday to 1:00 a.m. on Friday = 3600 true minutes = 3600 tm
The dysfunctional watch shows a time lapse of 3603 dysfunctional minutes = 3603 dm
So, there are 3603 dm for 3600 tm.
Or 3603/3600 dm for 1 tm
Now, let 't' minutes have passed after 1:00 p.m on Tuesday when the dysfunctional watch shows the correct time.
As the dysfunctional watch has to cover 1 minute more, we have the following equation:
(3603/3600)t = 1 + t
On solving, we get
t = 1200 minutes = 20 hours
Thus, the correct time will be shown at 9:00 a.m. on Wednesday.

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NTSE - MAT-2015

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SHARING IS CARING

Question 1

GCE

GEH

GCH

GHB

Solution

Question 2

Operations

Accounts

Operations or Accounts

Data inadequate

Solution

Question 3

Second

Third

Fourth

Fifth

Solution

Question 4

Operations

Accounts

Administration

Data inadequate

Solution

Question 5

B earns less than F and H.

F earns more than B and E.

B earns more than E and C.

B earns less than A and H.

Solution

Question 6

a five following form four group the of

a five following form group the of four

a five following form four of the group

a five following form four group of the

Solution

Question 7

back go here people settle who want to

back go here people to want settle who

back go here people settle to want who

Cannot be determined

Solution

Question 8

items surplus the sell to used so he

he items surplus the sell to used so

so used to sell the surplus items he

Cannot be determined

Solution

Question 9

ja

ma

kop

top

Solution

Question 10

117, 123

120, 132

123, 135

135, 144

Solution

Question 11

263

331

383

551

Solution

Question 12

acbcb

bcacb

babec

abebe

Solution