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NTSE - MAT-2016

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NTSE - MAT-2016
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  • Question 1
    1 / -0

    Complete the series.

    D3Y104, G9U91, J27Q78, M81M65, ______

    Solution

    In each term the first element moves 3 steps forward to obtain corresponding element of next term, second element is multiplied by 3 to obtain the corresponding element of next term, third element moves 4 step backward to obtain corresponding element of next term and fourth element is decreased by 13 to obtain corresponding element of next term. Thus term obtained is P243I52.

     

  • Question 2
    1 / -0

    Which of the following can replace the question mark (?) in the following table?

    0.8 0.512
    0.04 ?
    Solution

    Cube of 0.8 is 0.512
    Therefore cube of 0.04 is 0.000064

     

  • Question 3
    1 / -0

    Directions For Questions

    Directions: Study the given information carefully and answer the question that follows.

    Five lectures of Hindi, English, Science, Mathematics and Sanskrit are to be taken by five different teachers A, B, C, D and E in five different periods 1, 2, 3, 4 and 5. Each teacher will teach only one subject and take only one period.
    Science is not the 3rd period. The 5th period is taken by D, who does not teach Hindi or Sanskrit. A takes the 3rd period. The one who teaches Sanskrit takes the 4th period. There are two periods after and two periods before the lecture of Mathematics. The lecture of Hindi is between the lectures of Science and Mathematics. B teaches Science. E takes the period just before D's period.

    ...view full instructions

    Who teaches Hindi and in which period?

    Solution
    Period Number Teacher Subject
    1    
    2    
    3    
    4    
    5    

    A takes the 3rd period.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4    
    5    

    The one who teaches Sanskrit takes the 4th period.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4   Sanskrit
    5    

    The 5th period is taken by D, who does not teach Hindi or Sanskrit.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4   Sanskrit
    5 D  

    There are two periods after and two periods before the lecture of Mathematics.

    Period Number Teacher Subject
    1    
    2    
    3 A Mathematics
    4   Sanskrit
    5 D English/Science

    The lecture of Hindi is between the lectures of Science and Mathematics.

    Period Number Teacher Subject
    1   Science
    2   Hindi
    3 A Mathematics
    4   Sanskrit
    5 D English

    B teaches Science.

    Period Number Teacher Subject
    1 B Science
    2   Hindi
    3 A Mathematics
    4   Sanskrit
    5 D English

    E takes the period just before D's period.

    Period Number Teacher Subject
    1 B Science
    2   Hindi
    3 A Mathematics
    4 E Sanskrit
    5 D English

    So, the final arrangement is as given below:

    Period Number Teacher Subject
    1 B Science
    2 C Hindi
    3 A Mathematics
    4 E Sanskrit
    5 D English

     

  • Question 4
    1 / -0

    Directions For Questions

    Directions: Study the given information carefully and answer the question that follows.

    Five lectures of Hindi, English, Science, Mathematics and Sanskrit are to be taken by five different teachers A, B, C, D and E in five different periods 1, 2, 3, 4 and 5. Each teacher will teach only one subject and take only one period.
    Science is not the 3rd period. The 5th period is taken by D, who does not teach Hindi or Sanskrit. A takes the 3rd period. The one who teaches Sanskrit takes the 4th period. There are two periods after and two periods before the lecture of Mathematics. The lecture of Hindi is between the lectures of Science and Mathematics. B teaches Science. E takes the period just before D's period.

    ...view full instructions

    Which of the following is the correct sequence of 'Subject - Period - Teacher'?

    Solution
    Period Number Teacher Subject
    1    
    2    
    3    
    4    
    5    

    A takes the 3rd period.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4    
    5    

    The one who teaches Sanskrit takes the 4th period.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4   Sanskrit
    5    

    The 5th period is taken by D, who does not teach Hindi or Sanskrit.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4   Sanskrit
    5 D  

    There are two periods after and two periods before the lecture of Mathematics.

    Period Number Teacher Subject
    1    
    2    
    3 A Mathematics
    4   Sanskrit
    5 D English/Science

    The lecture of Hindi is between the lectures of Science and Mathematics.

    Period Number Teacher Subject
    1   Science
    2   Hindi
    3 A Mathematics
    4   Sanskrit
    5 D English

    B teaches Science.

    Period Number Teacher Subject
    1 B Science
    2   Hindi
    3 A Mathematics
    4   Sanskrit
    5 D English

    E takes the period just before D's period.

    Period Number Teacher Subject
    1 B Science
    2   Hindi
    3 A Mathematics
    4 E Sanskrit
    5 D English

    So, the final arrangement is as given below:

    Period Number Teacher Subject
    1 B Science
    2 C Hindi
    3 A Mathematics
    4 E Sanskrit
    5 D English

     

  • Question 5
    1 / -0

    Directions For Questions

    Directions: Study the given information carefully and answer the question that follows.

    Five lectures of Hindi, English, Science, Mathematics and Sanskrit are to be taken by five different teachers A, B, C, D and E in five different periods 1, 2, 3, 4 and 5. Each teacher will teach only one subject and take only one period.
    Science is not the 3rd period. The 5th period is taken by D, who does not teach Hindi or Sanskrit. A takes the 3rd period. The one who teaches Sanskrit takes the 4th period. There are two periods after and two periods before the lecture of Mathematics. The lecture of Hindi is between the lectures of Science and Mathematics. B teaches Science. E takes the period just before D's period.

    ...view full instructions

    The subject taught by teachers A, B, C, D and E respectively are

    Solution
    Period Number Teacher Subject
    1    
    2    
    3    
    4    
    5    

    A takes the 3rd period.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4    
    5    

    The one who teaches Sanskrit takes the 4th period.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4   Sanskrit
    5    

    The 5th period is taken by D, who does not teach Hindi or Sanskrit.

    Period Number Teacher Subject
    1    
    2    
    3 A  
    4   Sanskrit
    5 D  

    There are two periods after and two periods before the lecture of Mathematics.

    Period Number Teacher Subject
    1    
    2    
    3 A Mathematics
    4   Sanskrit
    5 D English/Science

    The lecture of Hindi is between the lectures of Science and Mathematics.

    Period Number Teacher Subject
    1   Science
    2   Hindi
    3 A Mathematics
    4   Sanskrit
    5 D English

    B teaches Science.

    Period Number Teacher Subject
    1 B Science
    2   Hindi
    3 A Mathematics
    4   Sanskrit
    5 D English

    E takes the period just before D's period.

    Period Number Teacher Subject
    1 B Science
    2   Hindi
    3 A Mathematics
    4 E Sanskrit
    5 D English

    So, the final arrangement is as given below:

    Period Number Teacher Subject
    1 B Science
    2 C Hindi
    3 A Mathematics
    4 E Sanskrit
    5 D English

     

  • Question 6
    1 / -0

    If × stants for +, ÷ stands for -, + stands for ÷ and - stands for ×, then what is the value of the following expression?

    ÷ 33 × 11 ÷ 9 x 28 + 4 - 5

    Solution

    After interchanging the symbols the expression will be:
    - 33 + 11 - 9 + 28 ÷ 4 × 5
    = - 22 - 9 + 35 = - 31 + 35 = 4

     

  • Question 7
    1 / -0

    If REASON is coded as PGYUMP, then DIRECT will be coded as

    Solution

    R (-2) = P, E (+2) = G, A (-2) = Y, S (+2) = U, O (-2) = M, N (+2) = P
    Similarly, DIRECT is coded as BKPGAV.

     

  • Question 8
    1 / -0

    Pritam, Zeba, Joy and Anu were assigned duties in the alphabetical order of their names. Only one of them is assigned a duty on a day. This assignment is repeated in the same sequence. Working week starts from Monday and ends on Friday.

    Who worked for the least number of days and for how many days if the duties are assigned for 3 weeks?

    Solution
    Anu Joy Pritam Zeba
    Mon (1) Tues (1) Wed (1) Thurs (1)
    Fri (1) Mon (2) Tues (2) Wed (2)
    Thurs (2) Fri (2) Mon (3) Tues (3)
    Wed (3) Thurs (3) Fri (3)  -

    Least number of days = Zeba, 3 days

     

  • Question 9
    1 / -0

    Pritam, Zeba, Joy and Anu were assigned duties in the alphabetical order of their names. Only one of them is assigned a duty on a day. This assignment is repeated in the same sequence. Working week starts from Monday and ends on Friday.

    Who were assigned duties on Wednesday in 1st, 2nd and 3rd weeks, respectively?

    Solution
    Anu Joy Pritam Zeba
    Mon (1) Tues (1) Wed (1) Thurs (1)
    Fri (1) Mon (2) Tues (2) Wed (2)
    Thurs (2) Fri (2) Mon (3) Tues (3)
    Wed (3) Thurs (3) Fri (3)  -

    Pritam, Zeba and Anu is the required order.

     

  • Question 10
    1 / -0

    In a showroom, 60 percent discount is given to everybody on all the articles. A successive discount of 40 percent is offered to female students. If printed price of an article is Rs. 1000 and it is bought by a female student, how much will she have to pay for that article?

    Solution

    Required price = (0.6) (0.4) (1000) = Rs. 240.

     

  • Question 11
    1 / -0

    Select the related word from the given alternatives.

    Guitar : Music : : Book : ?

    Solution

    Guitar produces music and knowledge comes from book.

     

  • Question 12
    1 / -0

    Reena, Rita and Zoha are three friends. Reena is the eldest, followed by Rita and Zoha. Reena is 2 years elder to Rita and 5 years elder to Zoha. The sum of the present ages of Reena and Zoha is 3 times the age of Rita 5 years ago. What is the current age of Rita?

    Solution

    Let Zoha's age be x years.
    Rita's age = (x + 3) years
    Reena's age = (x + 5) years
    According to the question: 2x +5 = 3(x – 2)
    2x + 5 = 3x - 6
    x = 11 years
    After solving, we get Rita's age = 14 years.

     

  • Question 13
    1 / -0

    A person needs to find the fastest two horses from among 16 horses. A race of 4 horses only can be conducted at a time. What is the minimum number of races to be conducted to determine the fastest two?

    Solution

    First we conduct 4 races of 4 sets of horses taking 4 horses in each set.
    Let F1, F2 , F3 and F4 and S1, S2 , S3 and S4 be the first 4 and second 4 horses, respectively.
    Then the 5th race will be conducted with all top 4 (F1, F2 , F3 , F4). So, we get the 2 top rankers. For example, take F1 and F2.
    So, the final 6th race will be conducted with F1 and F2 and second rankers of their groups S1 and S2. So, the total number of races conducted is 6.

     

  • Question 14
    1 / -0

    Which term will replace the question mark (?) in the given series?

    b, c, e, g, k, ?, q, s

    Solution

    If we assign number to the alphabets according to their sequence then it will be as 2, 3, 5, 7, 11, ?, 17, 19
    We observe that it is series of prime number therefore in place of question mark 13 will come.

     

  • Question 15
    1 / -0

    A + B means A is the daughter of B, A × B means A is the son of the son of B and A – B means A is the wife of B. If T – S × B – M, then which of the following is NOT true?

    Solution

    We have,
    T – S means T is the wife of S
    S x B means S is the son of B
    B – M means B is the wife of M
    S is son of B not daughter of B.

     

  • Question 16
    1 / -0

    In the following sequence, one number is wrong. Find the wrong number.

    9, 23, 51, 106, 219, 443

    Solution

    9 + 14 = 23, 23 + 28 = 51, 51 + 56 = 107, 107 + 112 = 219, 219 + 224 = 443
    Hence, 107 has to be there in the place of 106.

     

  • Question 17
    1 / -0

    Ronald is elder to Veena, while Amilia and Shree are elder to Parul, whose age lies between those of Ronald and Amilia. If Amilia is elder to Veena, then which of the following statements is necessarily true?

    Solution

    From first line Ronald is elder to Veena
    Ronald > Veena .....(1)
    From line: Amilia and Shree are elder to Parul, whose age lies between those of Ronald and Amilia and if Amilia is elder to Veena
    Shree > Amila > Parul > Ronald > Veena ...(2)

     

  • Question 18
    1 / -0

    A matrix of certain numbers is given. These numbers follow a certain trend, either row-wise or column-wise. Find this trend and choose the missing number from the given alternatives.

    1 5 7 75
    8 3 4 ?
    9 7 8 194
    Solution

    12 + 52 + 72 = 75
    92 + 72 + 82 = 194
    Similarly, 82 + 32 + 42 = 89

     

  • Question 19
    1 / -0

    A wall clock is placed in a room. It chimes 8 times at 8 o'clock. A person "X" present outside the room listens the 8 beats of chimes in 8 seconds. Assume that each chime of the wall clock takes equal time. To listen 11 chimes at 11 o'clock, how much time will be required by person "X"?

    Solution

    For 8 beats it takes 7 intervals
    7 intervals = 8 seconds
    1 interval = 8/7 seconds
    10 intervals = 8/7 × 10 seconds = 11.43 seconds

     

  • Question 20
    1 / -0

    Directions For Questions

    Directions: Study the following information and answer the question given below it.

    Six boys Prem, Kamal, Ramesh, Shyam, Tarun and Umesh go to University Sports Centre and each plays a different sport.
    A. Tarun is taller than Prem and Shyam.
    B. The tallest among them plays kabaddi.
    C. The shortest one plays volley ball.
    D. Kamal and Shyam neither play volley ball nor kabaddi.
    E. Ramesh plays volley ball.
    F. If all six boys stand in order of their height, then Tarun is in between Kamal and Prem; and Tarun plays football.

    ...view full instructions

    Who among them plays kabaddi?

    Solution

    From C and E
    Ramesh is shortest and plays volleyball.
    From B and D
    Neither Kamal nor Shyam is tallest and do not play Kabaddi
    From A and F
    Kamal > Tarun > Prem
    From above information it is clear that Shyam cannot be tallest and shortest and Tarun is taller than Shyam.
    Therefore, Shyam is taller than Ramesh.
    Combining all statements we get information given below:
    Boys are according to the decreasing order of their height.
    Umesh > Kamal > Tarun > Prem > Shyam > Ramesh

    Person Game
    Tarun Football
    Ramesh Volleyball
    Umesh Kabaddi
    Kamal Data insufficient
    Shyam Data insufficient
    Prem Data insufficient

     

  • Question 21
    1 / -0

    Directions For Questions

    Directions: Study the following information and answer the question given below it.

    Six boys Prem, Kamal, Ramesh, Shyam, Tarun and Umesh go to University Sports Centre and each plays a different sport.
    A. Tarun is taller than Prem and Shyam.
    B. The tallest among them plays kabaddi.
    C. The shortest one plays volley ball.
    D. Kamal and Shyam neither play volley ball nor kabaddi.
    E. Ramesh plays volley ball.
    F. If all six boys stand in order of their height, then Tarun is in between Kamal and Prem; and Tarun plays football.

    ...view full instructions

    Who will be at fourth place if they are arranged in descending order of their heights?

    Solution

    From C and E
    Ramesh is shortest and plays volleyball.
    From B and D
    Neither Kamal nor Shyam is tallest and do not play Kabaddi
    From A and F
    Kamal > Tarun > Prem
    From above information it is clear that Shyam cannot be tallest and shortest and Tarun is taller than Shyam.
    Therefore, Shyam is taller than Ramesh.
    Combining all statements we get information given below:
    Boys are according to the decreasing order of their height.
    Umesh > Kamal > Tarun > Prem > Shyam > Ramesh
     

    Person Game
    Tarun Football
    Ramesh Volleyball
    Umesh Kabaddi
    Kamal Data insufficient
    Shyam Data insufficient
    Prem Data insufficient

     

  • Question 22
    1 / -0

    Directions For Questions

    Directions: Study the following information and answer the question given below it.

    Six boys Prem, Kamal, Ramesh, Shyam, Tarun and Umesh go to University Sports Centre and each plays a different sport.
    A. Tarun is taller than Prem and Shyam.
    B. The tallest among them plays kabaddi.
    C. The shortest one plays volley ball.
    D. Kamal and Shyam neither play volley ball nor kabaddi.
    E. Ramesh plays volley ball.
    F. If all six boys stand in order of their height, then Tarun is in between Kamal and Prem; and Tarun plays football.

    ...view full instructions

    Who plays tennis?

    Solution

    From C and E
    Ramesh is shortest and plays volleyball.
    From B and D
    Neither Kamal nor Shyam is tallest and do not play Kabaddi
    From A and F
    Kamal > Tarun > Prem
    From above information it is clear that Shyam cannot be tallest and shortest and Tarun is taller than Shyam.
    Therefore, Shyam is taller than Ramesh.
    Combining all statements we get information given below:
    Boys are according to the decreasing order of their height.
    Umesh > Kamal > Tarun > Prem > Shyam > Ramesh

    Person Game
    Tarun Football
    Ramesh Volleyball
    Umesh Kabaddi
    Kamal Data insufficient
    Shyam Data insufficient
    Prem Data insufficient

     

  • Question 23
    1 / -0

    A coding language writes English words in a coded form as

    STAT θδθγ
    RAT βθδ
    SAY εγδ

    The code does not appear in the same order of the letters in the English alphabet. On this basis, which of the following will be the code of the word TRAY?

    Solution

    As A is present in STAT, RAT and SAY and common code is "δ"
    There are two 'T's' in STAT and common code is "θ"
    S is common in STAT and SAY and common code is "γ"
    Y is common in SAY and common code is "ε"
    R is coded as "β"
    Therefore, TRAY is coded as θβδε.

     

  • Question 24
    1 / -0

    A piece of work is expected to be completed by 20 workers in 25 days. The work is started by 10 workers. Then, after every 5 days, 5 more workers join the work. In how many days will the work be completed?

    Solution

    Let the amount of work done by 1 worker in 1 day is 1 unit
    Total work = 20 x 25 units = 500 units
    In first 5 days work done = 5 x 10 units = 50 units
    In next 5 days work done = 5 x 15 units = 75 units
    In next 5 days work done = 5 x 20 units = 100 units
    In next 5 days work done = 5 x 25 units = 125 units
    In next 5 days work done = 5 x 30 units = 150 units
    So Total 25 days are required to complete the work

     

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