Reasoning Test - 12

Answer: Option C

The first letters are in alphabetical order with a letter skipped in between each segment: C, E, G, I, K. The second and third letters are repeated; they are also in order with a skipped letter: M, O, Q, S, U.

\(E \omega F \Rightarrow E \geq F\)

\(F \in G \Rightarrow F>G\)

G \(\theta \mathrm{H} \Rightarrow \mathrm{G} \leq \mathrm{H}\)

Combined statement: \(\mathrm{E} \geq \mathrm{F}>\mathrm{G} \leq \mathrm{H}\)

Conclusions:

I. \(H \in F=H>F\) not true

II. \(G @ E=G

III. \(G \in E=G>E\) not true

Therefore, only conclusion II is true

\(\mathrm{K}_{\infty} \mathrm{L} \Rightarrow \mathrm{K} \geq \mathrm{L}\)

\(\mathrm{L} \in \mathrm{M} \Rightarrow \mathrm{L}>\mathrm{M}\)

\(M \% N \Rightarrow M=N\)

Combined Statement: \(\mathrm{K} \geq \mathrm{L}>\mathrm{M}=\mathrm{N}\)

Conclusions:

I. \(N @ L=N\)

II. M \(@ \mathrm{K}=\mathrm{M}\)

III. \(\mathrm{K} \in \mathrm{N}=\mathrm{K}>\mathrm{N}\) true

Therefore, all the conclusions are true.

\(P @ Q \Rightarrow P

\(Q \% R \Rightarrow Q=R\)

\(R \propto S \Rightarrow R \geq S\)

Combined Statement: \(\mathrm{P}<\mathrm{Q}=\mathrm{R} \geq \mathrm{S}\)

Conclusions:

\(\mathrm{I} \cdot \mathrm{R}^{\infty} \mathrm{P}=\mathrm{R} \geq \mathrm{P}\) not true

\(\mathrm{II} . \mathrm{S} \cdot \mathrm{Q}=\mathrm{S}<\mathrm{Q}\)

In. \(S\% =S=Q\)

Therefore, either conclusion II or III is true.

\(A \in B \Rightarrow A>B\)

\(B \infty C \Rightarrow B \geq C\)

\(C @ D \Rightarrow c

Combined Statement: \(A>B \geq C

Conclusions:

I. \(\quad C @ A=C

II. \(D \in B=D>B\) not true

III. \(D \in A=D>A\) not true

Therefore, only conclusion I is true.

\(\mathrm{M} \theta \mathrm{N} \Rightarrow \mathrm{M} \leq \mathrm{N}\)

\(\mathrm{N} @ \mathrm{O} \Rightarrow \mathrm{N}<\mathrm{O}\)

\(O \% P \Rightarrow O=P\)

Combined Statement: \(\mathrm{M} \leq \mathrm{N}<\mathrm{O}=\mathrm{P}\)

Conclusions:

I. \(P \in N=P>N\) true

II. \(\mathrm{O} \in \mathrm{N}=\mathrm{O}>\mathrm{N}\) true

III. \(\mathrm{M} @ \mathrm{P}=\mathrm{M}<\mathrm{P}\) true

Therefore, all the conclusions are true.

A is in the North-East corner.

Hapl means cloud; lesh means burst; srench means pin; och means ball; and resbo means nine. Leshsrench (choice a) doesn't contain any of the words needed for cloud nine. We know that och means ball, so that rules out choices b and c. When you combine hapl (cloud) with resbo (nine), you get the correct answer. Hence, option B is correct.

Consider the figure:

The distance between DA will be equal to CB because CB is parallel to DA.

So, the shortest distance travelled \(=50+100=150 \mathrm{km}\)

According to the information, the diagram will be:

Therefore, the west will become South-East.

Hence, the correct answer is (C).