Chemistry Test

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Chemistry Test - 6

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Weekly Quiz Competition

Question 1
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Which of the following is not the mineral of iron?

A
A. Limonite

B
B. Magnetite

C
C. Corundum

D
D. Haematite

Solution

Corundum is not a mineral of iron. It is a crystalline form of aluminium oxide typically captaining traces of Fe, Ti, V and Cr. On the other hand, limonite, magnetite and haematite are minerals of iron. The name and a molecular formula of given minerals is given below.
Question 2
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How many primary amines are possible for the molecular formula C₃H₉N?

A
A. 4

B
B. 1

C
C. 2

D
D. 3

Solution

Amine with molecular formula C₃ H₉ N have two primary structures. These are as follows

(a)

(b)

Other isomers are not primary amines.
Question 3
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A polymer which becomes soft on heating and hard on cooling, belongs to class of

A
A. fibers

B
B. thermosetting polymer

C
C. elastomer

D
D. thermoplastic polymer

Solution

A polymer which becomes soft on heating and hard on cooling belongs to the class of thermoplastics. When these polymers are heated, the polymer becomes soft enough to be moulded into various shapes, e.g., polyethylene, polystyrene, etc.
Question 4
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Which bond in a molecule of ethyl magnesium bromide is ionic in nature?

A
A. C — C bond

B
B. C — Mg bond

C
C. Mg — Br bond

D
D. C — H bond

Solution

Mg — Br Bond in a molecule of ethyl magnesium bromide is ionic in nature because the difference in electronegativity is large. As a result, it possesses a high magnitude of lattice energy and hence maximum ionic character.
Question 5
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IUPAC name of the complex Ba[CuCl₄] is

A
A. barium tetrachlorocuprate (ll)

B
B. tetrachloro barium cuprate (III)

C
C. barium tetracHLorocuprate (III)

D
D. tetracLoro barium copper (II)

Solution

IUPAC name of the complex Ba [CuCl₄ ] is barium tetrachlorocuprate (II). While naming a complex, the cation is named first and ligands are named in an alphabetical order before the name of the central atom or ion.
Question 6
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Which among the following polymer does not show cross linking in it?

A
A. Nylon-6

B
B. Bakelite

C
C. Melamine

D
D. Vulcanised Rubber

Solution

Nylon - 6 polymer does not show cross linking in it. It is a linear polymer. It is obtained by heating caprolactam with water at a high temperature. The structural formula and name of given polymers are shown below
Question 7
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Which of the following is not present in DNA?

A
A. Thymine

B
B. Guanine

C
C. Adenine

D
D. Uracil

Solution

Uracil is not present in DNA. It is present in RNA. DNA contains four bases, i.e . adenine (A), guanine (G), cytosine (C), and thymine (T). In RNA, thymine (T) is replaced by uracil (U).
Question 8
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The correct order of boiling points of alkyl halides is

A
Rl >RBr >RF >RCI

B
RI >RCI >RBr >RF

C
Rl >RBr >RCl >RF

D
RF >RBr >R >Rl

Solution

The correct order of boiling point of alkyl halides is Rl >RBr >RCl >RF. This is because with the increase in size and mass of the halogen atom, the magnitude of van der Waals 'forces increases.
Question 9
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The conversion of 2-methylpropan-1-ol to 2-methylpropan-2-ol is

A
A. addition reaction

B
B. rearrangement reaction

C
C. substitution reason

D
D. elimination reaction

Solution

The conversion of 2-methylpropan-1-ol to 2-methylpropan-2-ol is a rearrangement reaction. In these reactions, the carbon skeleton of a molocuto is rearranged to give a structural isomer of the original molecule. Here, the alcohol group of 2-methylpropan-1 -ol moves from one atom to another atom in the same molecule to give 2 -methyl propan -2 -ol.
Question 10
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The effective atomic number of Iron (Z = 26) in [Fe{CN)₆)^-3is

A
A. 36

B
B. 33

C
C. 35

D
D. 34

Solution

Key Idea The total number of electrons which the central metal Ion appears to possess in the complex including those gained by it in bonding is called effective atomic number of central metal ions.

In the given complex ion [Fe(CN)₆ ]^3- , the Fe is in +3 oxidation state. As we know that atomic number of iron is 26. The number of electron in Fe³⁺ is 23. Each of the six cyanide molecules donates a pair of elections so that EAN becomes 23 + 2 x 6 ⇒ 35.
Question 11
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Based on first Jaw of thermodynamics which of the following is correct

A
A. for an isobaric process, q_p = ΔU + w

B
B. for an adiabatic process, ΔU = -w

C
C. for an isochoric process, ΔU = -q_v

D
D. for an isothermal process, q = + w

Solution

In the isobaric process, pressure is constant, and volume increases from V₁ to V₂ due to heat absorption. According to the first law of thermodynamics, ΔU = q + W

At constant pressure, q_p = ΔU -W.

q_p = ΔU - pΔV

q_p = U₂ - U₁ - (-p(V₂ - V₁ ))

q_p = (U₂ + pV₂ ) - (U₁ + pV₁ )

q_p = H₂ - H₁

q_p = ΔH

As we know, ΔH = ΔU + pΔV

ΔH = ΔU + W

Putting the value of ΔH in (1)

q_p = ΔU + W

Other corrected options are as follows:

For adiabatic process ΔU = W

For an isochoric process ΔU = q_v

For an isothermal process q = -W
Question 12
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Hinsberg's reagent is

A
A. benzene sulphonyl chloride

B
B. benzene sulphonic add

C
C. sodium benzene sulphonate

D
D. Igonzone sulfonamide

Solution

Hinsberg’s reagent is benzene sulphonyl chloride. Its molecular formula is C₆ H₅ SO₂ Cl. This reagent is used to distinguish primary (1⁰ ), secondary (2⁰ ), and tertiary (3⁰ ) amines.
Question 13
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The vitamin that belongs to the aromatic series is

A
A. B complex

B
B. K

C
C. C

D
D. A

Solution

The vitamin that belongs to the aromatic series is vitamin K . It has an aromatic structure. The structure of vitamin K is given below
Question 14
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The SI unit of electrochemical equivalent is

A
A. Js^-1

B
B. kg C^-1

C
C. kg ms^-2

D
D. kg m^-1 s^-2

Solution

(b) The electrochemical equivalent of a substance is the mass Liberated in electrolysis by 1 coulomb, it can be calculated by assuming Faraday's second law and using the experimental fad that the equivalent weight in grams of all substances is liberated by 96500 C.

Electrochemical equivalent = Equivalent weight/96500

gm per coulomb. Its unit is kgC^-1 .
Question 15
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The molar conductivities at infinite dilution for sodium acetate, NaAc, HCI and NaCI are 91 S cm²mol^-1, 425.9 S cm²mol^-1and 126.4 S cm²mol^-1respectively. The molar conductivity of acetic acid at infinite dilution is

A
A. 390.5 S cm² mol^-1

B
B. 530.9 S cm² mol^-1

C
C. 300.5 S cm² mol^-1

D
D. 930.5 S cm² mol^-1

Solution

Key idea Kohlrausch law of independent migration of ions can be used to calculate ∧*_m for weak electrolytes such as acetic acid.

Given

Using Kohlrausch law, to find molar conductivity of acetic acid.
Question 16
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A flavouring agent found in oil of whether green is

A
A. methyl salicylate

B
B. acetophenone

C
C. vanillin

D
D. menthol

Solution

A flavouring agent found in the oil of wintergreen is methyl salicylate. It is an organic compound with the formula C₆ H₄ (OH) (CO₂ CH₃ ). It is the methyl ester of salicylic acid. It is a colourless, viscous liquid. The structure of methyl salicylate is as follows
Question 17
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Which of the following metal halides is more covalent?

A
A. SnCl₂

B
B. PbCl₂

C
C. SbCl₃

D
D. SbCl₅

Solution

Key idea Fajans rules help in predicting the covalent character in a bond.

SbCl₅ metal halide is more covalent than other given options. It can be explained on the basis of Fajan’s rule. The higher the charge on the cation, the ,,greater is its polarising power. In SbCt_6, Antimony (Sb) is in +5 oxidation state, it has maximum polarising power. Hence, possess a the higher covalent character.