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Research Aptitude Test - 18

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Research Aptitude Test - 18
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Weekly Quiz Competition
  • Question 1
    2 / -0.5

    There are 5 letters and 5 directed envelopes. Find 'the number of ways in which the tetters can be pul into the envelopes so that all are not put in directed envelopes?

    Solution

    Since out of the 120 ways, there is only one way for putting each letter in the correct envelope.

    Hence, the number of ways of putting letters all are not in directed envelopes = 120 - 1 = 119 ways.

    Here, the first letter can be put in any one of the 5 envelopes in 5 ways. Second letter can be put in any one of the 4 remaining envelopes In 4 ways. Continuing in this way, we get the total number of ways in which 5 letters can be put into 5 envelopes

    = 5 x 4 x 3 x 2 x 1 = 120.

  • Question 2
    2 / -0.5

    How many words, with or without meaning, can be formed using all letters of the word EQUATION, using each letter exactly once?

    Solution

    The word EQUATION has exactly 8 letters which are all different.

    ∴ Number of words that can be formed = number of permutations of 8 letters taken all at a time.

    = P(8, 8) = 8!

    = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

    = 40320

  • Question 3
    2 / -0.5

    It is required to seat 5 men and 4 women in a row so that the women occupy the even places. How many such arrangements are possible?

    Solution

    Total number of candidates = 5 + 2 = 9

    In the row of 9 positions, the even places are 2nd , 6th and 8th . Now, number of even places = 4.

    Number of women to occupy the even places = 4.

    ∴ Even places can be filled = P(4, 4) ways

    Number of men = 5

    ∴ The remaining 5 places can be tilted by 5 men = P(5, 5) ways

    ∴ By the fundamental principle of counting.

    ∴ The required number of seating arrangements = P(4, 4) x P(5, 5) = 4! x 5!

    = 24 x 120 = 2880.

  • Question 4
    2 / -0.5

    Four books, one each in chemistry, Physics, Biology and Mathematics are to be arranged in a shelf. In how many ways can this be done?

    Solution

    4 different books can be arranged among themselves, in a shelf, in P (4,4)

    = 4 x 3 x 2 x 1 = 24 ways.

  • Question 5
    2 / -0.5

    The Probability of raining on day 1 is 0.2 and on day 2 is 0.3. What is the probat of raining on both the days?

    Solution

    0.2 x 0.3 = 0.06

  • Question 6
    2 / -0.5

    A bag contains 5 red balls and 8 blue bans. It also contains 4 green and 7 black balls. If a ball is drawn at random, then find the probability that it is not green.

    Solution

    The probability that the ball drawn is ol green colour = 4/24 = ⅙

    Probability that the ball drawn is not of green colour

  • Question 7
    2 / -0.5

    From a pack of 52 playing cards, two cards are drawn together at random. Calculate the probability of both the cards being Kings.

    Solution

    Two cards can be drawn from a pack of 52 playing cards in52 C2 ways.

    The event that two kings appear in a single draw can appear in 4 C2 ways, i.e. 6 ways.

    ∴ The probability that the two cards drawn from a pack of 52 cards are kings = 6/1326 = 1/221

  • Question 8
    2 / -0.5

    Rahul's mother is the only daughter of Monika’s father, how is Monika's husband related to Rahul

  • Question 9
    2 / -0.5

    A is B’s sister, C is B’s mother, D is C’s father, E is D's mother. Then, how is A related to D

  • Question 10
    2 / -0.5

    Given that (i) A is brother of B (ii) C is father of A (iii) D is brother of E (iv) E is daughter of B, then uncle of D is

    Solution

    Uncle of D is A

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