Research Aptitude Test

Result

Research Aptitude Test - 25

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Question 1
2 / -0.5

Direction: The figure given below consists of three interesting circles which represent sets of students who play Tennis, Badminton and Volleyball Each region in the figure is represented by a small letter.

On the basis of the above figure, answer the questions given below.

Which letter represents the set of persons who play Tennis but neither Badminton nor Volleyball?

A
A. a

B
B. b

C
C. c

D
D. d

Solution

The required region is the one which lies inside circle P but is not common to circle Q or circle R or both i.e. a.
Question 2
2 / -0.5

Direction: The figure given below consists of three interesting circles which represent sets of students who play Tennis, Badminton and Volleyball Each region in the figure is represented by a small letter.

On the basis of the above figure, answer the questions given below.
Which letter represents the set of persons who play Tennis and Badminton but not Volleyball?

A
A. b

B
B. d

C
C. c

D
D. f

Solution

The required region is the one which is common to circles P and Q but lies outside circle R i.e. d.
Question 3
2 / -0.5

Direction: Five courses - A, B, C, D and E each of one month duration are to be taught from January to May one after the other though not necessarily in the same order by lectures P, Q, R. S and T. P teaches course 'B' but not in the month of April or May. Q teaches course ‘A’ in the month of March R teaches in the month of January but does not teach course ‘C’ or D'.

Which course is taught by S?

A
A. C

B
B. E

C
C. Either C or D

D
D. D
Solution
We can be solved these questions with the help of tabular chart.

We will start reading each condition and mark ‘✓’ sign or ‘×’ sign according

P teaches course B but not in the month of April or May

Q teaches course A in the month of March

R teaches in the month of January but does not teach course C or D

Now, we can easily answer given questions with the help of above table.

Note: After drawing first table further modifications can be done according to conditions given, There is no need to draw further table. Further table drawn is just to explain the steps in elaborate manner.

Final table can be referred as.
Question 4
2 / -0.5

Direction: Five courses - A, B, C, D and E each of one month duration are to be taught from January to May one after the other though not necessarily in the same order by lectures P, Q, R. S and T. P teaches course 'B' but not in the month of April or May. Q teaches course ‘A’ in the month of March R teaches in the month of January but does not teach course ‘C’ or D'.

Which lecture's course immediately follows after course B?

A
A. Q

B
B. P

C
C. S

D
D. T
Solution
We can be solved these questions with the help of tabular chart.

We will start reading each condition and mark ‘✓’ sign or ‘×’ sign according

P teaches course B but not in the month of April or May

Q teaches course A in the month of March

R teaches in the month of January but does not teach course C or D

Now, we can easily answer given questions with the help of above table.

Note: After drawing first table further modifications can be done according to conditions given, There is no need to draw further table. Further table drawn is just to explain the steps in elaborate manner.

Final table can be referred as.
Question 5
2 / -0.5

Direction: Five courses - A, B, C, D and E each of one month duration are to be taught from January to May one after the other though not necessarily in the same order by lectures P, Q, R. S and T. P teaches course 'B' but not in the month of April or May. Q teaches course ‘A’ in the month of March R teaches in the month of January but does not teach course ‘C’ or D'.

Which course is taught in the month of January?

A
A. C

B
B. D

C
C. E

D
D. Data inadequate
Solution
We can be solved these questions with the help of tabular chart.

We will start reading each condition and mark ‘✓’ sign or ‘×’ sign according

P teaches course B but not in the month of April or May

Q teaches course A in the month of March

R teaches in the month of January but does not teach course C or D

Now, we can easily answer given questions with the help of above table.

Note: After drawing first table further modifications can be done according to conditions given, There is no need to draw further table. Further table drawn is just to explain the steps in elaborate manner.
Question 6
2 / -0.5

Direction: Each question below is followed by two Statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose between the possible answers.

The ages of P and G are in the ratio of 7:5. What is the age of P?

I. The ages of P and N are in the ratio of 3:1.

II. After 7 yr, the ratio of ages of P and A will be 4 : 3.

A
A. if the Statement 1 alone is sufficient to answer the question but the Statement II alone is not sufficient

B
B. if the Statement II alone is sufficient to answer the question but the Statement I alone is not sufficient

C
C. if both Statements I and II together are needed to answer the question

D
D. if either the Statement I alone or Statement II alone is sufficient to answer the question

E
E. if cannot get the answer from the Statements I and II together but need even more data

Solution

Age of P can not be found as in the given question, ratio of ages of the P and G is given, while in Statements I and II, the ratio ot ages of P and N and P and A, respectively are given. When we make three equations in two variables using given three ratios, no two variables are same in any of the two equations.
Question 7
2 / -0.5

Direction: In these questions, questions are given followed by information in three statements. You have to consider the information in all the three statements and decide the information in which of the statements is not necessarily required to answer the question and therefore can be dispensed with. Indicate vo'iransw accordingly.

How many students passed in first class?

I. 85% of the students who appeared in examination have passed either in first class or in second class or in pass class.

II. 750 students have passed in second class.

III. The number of students who passed in pass class is 28% of those passed in second class.

A
A. Only I

B
B. I and III

C
C. II and III

D
D. Question cannot be answered even with information in ail three statements

E
E. None of the above

Solution

Using Statements II and III. we can find the number of students in second class and pass class only, as there is no link given between the firs: class and the other classes, we cannot find the number of students in first class.
Question 8
2 / -0.5

Direction: In this question, a question is given followed by information in three statements. You have to consider the information in all the three statements and decide which information in the statement(s) is not necessarily required to answer the question and therefore can 't be dispensed with. Indicate your answer accordingly.

Q. What is Suchitra 's present age?

Statements:

I. Suchitra 's present age is double the age of her son.

II. Ratio between present ages of Suchitra and her mother is 2:3 respectively.

III. Four years hence the ratio between Suchitra 's age and her son 's age will be 24:13.

A
None of these

B
Only III

C
Either I or II only

D
Either II or III only

E
Only II

Solution

According to the statement (I),
Let present age of Suchitra = X and her son = Y
then,
X = 2 ×Y
X/Y = 2/1 .....(a)
It is not sufficient data for further calculation so, we need to consider statement (III).
According to the statement (III),
Four year hence ratio of Suchitra and her son 's age

Using equation (a) Put X = 2Y in above expression we have,

This is Suchitra 's son present age so, Suchitra present age is,

So,only statement (I) and (III) is sufficient to solve the problem.
Question 9
2 / -0.5

Direction: In these questions, questions are given followed by information in three statements. You have to consider the information in all the three statements and decide the information in which of the statements is not necessarily required to answer the question and therefore can be dispensed with. Indicate vo 'iransw accordingly.

What is the amount invested in Scheme B?

I. The amounts invested in Schemes A and B are in the ratio of 2 : 3.

II. The amount invested in Scheme A is 40% of the total amount invested.

III. The amount invested in Scheme A is ₹45000.

A
I and II

B
I and III

C
II and III

D
Only II

E
Either I or II

Solution

Using Statement

Using Statement II, A is 40% of total. So, B is 60% of total amount invested.

A/B = 40/60 = 2/3

Using Statement III, A = ₹45000

Putting the value of Statement III in any of the Statements I or II we can find the amount invested in scheme B.

Thus, either I or II can be dispensed with.Answer: E: Either I or II

Explanation:

To find the amount invested in Scheme B, we need to consider the information in both statements I and II.

Statement I tells us that the amounts invested in Schemes A and B are in the ratio of 2:3. This means that if the amount invested in Scheme A is known, we can calculate the amount invested in Scheme B by multiplying the amount invested in Scheme A by 3/2.

Statement II tells us that the amount invested in Scheme A is 40% of the total amount invested. If the total amount invested is known, we can calculate the amount invested in Scheme A by multiplying the total amount invested by 40%. Once we know the amount invested in Scheme A, we can use statement I to calculate the amount invested in Scheme B.

Statement III provides additional information that the amount invested in Scheme A is ₹45000. This information is not necessary to answer the question because we can calculate the amount invested in Scheme B using either statement I or statement II.

Therefore, the information in statement III is not necessarily required and can be dispensed with. Hence, the answer is E: Either I or II.
Question 10
2 / -0.5

'a' and 'b' are two number whose AM is 25 and GM is 7. Which of the following may be value of ‘a'?

A
A. 10

B
B. 20

C
C. 49

D
D. 25

Solution

(a+b)/2 = 25

a + b = 50

ab = 49 here a = 1 and b = 49 or vice versa