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Principle of Mathematical Induction Test - 2

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Principle of Mathematical Induction Test - 2
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  • Question 1
    1 / -0

    Let P(n) be a statement and let P(n) ⇒ P( n + 1 ) for all natural numbers n , then what will the nature of  P(n) ?

    Solution

    Since the statement is conditional statement ( if....then).

  • Question 2
    1 / -0

    Let P(n) b e a statement 2n < n! , where n is a natural number , then P(n)is true for

    Solution

    Since for example n = 4 will give LHS as 16 and RHS as 4! = 1.2.3.4= 24

  • Question 3
    1 / -0

    If x > -1 , then the statement ( 1 + x ) n > 1 + nx is true for

    Solution

    For example , if x = 0 and n > 1 , say n = 2 then the given inequality will become 12 > 1 , which is not true. Hence both the conditions on x and n are needed.

  • Question 4
    1 / -0

    If P ( n ) = 2+4+6+………………..+2n , n ∈ N , then P ( k ) = k ( k + 1 ) + 2 ⇒ P ( k + 1 ) = ( k + 1 ) ( k +2 ) + 2 for all k ∈ N . So we can conclude that P ( n ) = n ( n + 1 ) +2 for

    Solution

    Because the statement is incomplete without the conclusion/ RHS

  • Question 5
    1 / -0

    (xn − yn) is divisible by ( x - y ) for 

    Solution

    Replacing n by 1,2,3... we get the expression with  the factor ( x - y ).Hence it is divisible by ( x - y ).

  • Question 6
    1 / -0

    The greatest positive integer , which divides n ( n + 1 ) ( n + 2 ) ( n + 3 ) for all n ∈ N , is

    Solution

    If n = 1 then the statement becomes 1x2x3x4= 24 : the consecutive natural numbers when substituted will be multiples of 24.

  • Question 7
    1 / -0

    Let P ( n ) denote the statement n2 + n is odd , It is seen that P(n) ⇒ P( n + 1 ) , therefore P ( n ) is true for all

    Solution

    Since if n = 1 the answer is 2 which is even . also p ( 1 ) = p ( 2 ) is also not true since p(2 ) is 6 which is even.

  • Question 8
    1 / -0

    The greatest positive integer, which divides (n + 1) (n + 2) (n + 3)..................(n + r)∀n ∈ W , is

    Solution

    If n = 0 the given expression becomes 1.2.3.4........r = r! Also when n = 1 one more extra term will be there in the product  2.3.4........(r+1)which is also divisible by r!.

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