Coordination Compounds Test

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Coordination Compounds Test - 48

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Weekly Quiz Competition

Question 1
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In an octahedral complex, if ligands on one axis are displaced little away from their ideal positions, the crystal field splitting of d-orbitals for this complex is as given below
$$d_{x^2-y^2} d_{z^2} d_{xy} d_{yz} d_{xz}$$
The ligands are displaced on which axis/ axes :

A
x- and y

B
y-only

C
x-only

D
z-only

Solution

$$d_{x^2-y^2}$$ and $$d_{z^2}$$ lies on the x and y axis so if the energy increases of $$d_{x^2-y^2}$$ and $$d_{z^2}$$ it means the ligands are displaced on which x and y axis.
Question 2
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Which of the following statement(s) is/are not correct?

A
Hybridization is the separation of atomic orbitals.

B
$$sp^{2}-$$ hybrid orbitals are formed form two p- atomic orbitals and one s- atomic orbitals.

C
$$dsp^{2}-$$ hybrid orbitals are at $$\displaystyle\:90^{\circ}$$ to one another.

D
$$d^{2}sp^{3}-$$ hybrid orbitals are directed towards the corners of a regular octahedron.

Solution

Hybridization is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory. Hybrid orbitals are very useful in the explanation of molecular geometry and atomic bonding properties.
Also,
$$dsp^{2}-$$ hybrid orbitals are at $$\displaystyle\:90^{\circ}$$ to one another.
$$sp^{2}-$$ hybrid orbitals are formed form two p- atomic orbitals and one s- atomic orbitals.
$$d^{2}sp^{3}-$$ hybrid orbitals are directed towards the corners of a regular octahedron.
Question 3
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The magnitude of crystal field stabilization energy in octahedral field depends on
I : the nature of the ligand
II : the charge on the metal ion
III : whether the metal is in the first, second or third row of the transition elements.

A
I, II, III all are correct.

B
I, II are correct

C
II, III are correct

D
III only correct

Solution

The magnitude of crystal field stabilization energy in octahedral field depends on the nature of ligands, the charge on the metal ions and whether the metal is in the first, second or third row of the transition elements.
Strong ligands cause high value of CFSE and weak ligands cause low value of CFSE.
Question 4
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Coordination compounds have great importance in biological systems. In this context which of the following statement(s) is/are incorrect?

A
Chlorophyll is a green pigment in plants and contains calcium

B
Haemoglobin is the red pigment of blood and contains iron

C
Cyanocobalamin is $$\displaystyle B_{12}$$ and contains cobalt

D
Carboxypeptidase A is an enzyme and contains zinc

Solution

Chlorophyll is a green pigment in plants and contains Mg.
Question 5
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Which of the following statements are true regarding Werner's theory are true?
$$( 1 )$$ Ligands are connected to the metal ions by covalent bonds
$$( 2 )$$ Secondary valencies have directional properties
$$( 3 )$$ Secondary valencies are non- ionizable

A
1, 2 and 3 are correct

B
2 and 3 are correct

C
1 and 3 are correct

D
1 and 2 are correct

Solution

According Werner's theory Ligands are connected to the metal ions by coordinate bonds.
The primary valencies are non-directional whereas secondary valencies have directional properties.
The primary valencies are ionizable whereas secondary valencies are non-ionisable.
Thus, statements 2 and 3 are correct.

Hence, the correct option is $$\text{B}$$
Question 6
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The IUPAC name for the complex $$\displaystyle \left [ Co\left ( NH_{3} \right )_{5}\left ( NO_{2} \right ) \right ]Cl_{2}$$ is:

A
Nitrito $$\displaystyle -$$ N $$\displaystyle -$$ pentaammine cobalt ( III ) chloride.

B
Nitrito $$\displaystyle -$$ N $$\displaystyle -$$ pentaammine cobalt ( II ) chloride.

C
Pentaammine nitrito $$\displaystyle -$$ N $$\displaystyle -$$ cobalt ( II ) chloride.

D
Pentaammine nitrito $$\displaystyle -$$ N $$\displaystyle -$$ cobalt ( III ) chloride.

Solution

Oxidation number of $$Co$$,

$$x-1=2 \rightarrow x=3$$.

Nitrogen is donating its lone pairs in the given compound.

The IUPAC name is pentaamminenitrito-N-cobalt(III) chloride.

Hence,option D is correct.
Question 7
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Directions For Questions

The crystal field theory (C.F.T.) is now much more widely accepted than the valence bond theory. It assume that the attraction between the central metal and the ligands in a complex is purely electrostatic. According to C.F.T. ligands are treated as a point charge and crystal field splitting energy (CFSE) increases the thermodynamic stability of the complexes. Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally. For tetrahedral complexes, $$\Delta$$ is about 4/9 times to $$\Delta _{0}$$ (CFSE for octahedral complexes.) This energy lies in visible region and i.e. why electronic transition are responsible for colour.

...view full instructions

Which of the following statement is not correct about C.F.T.?

A
Diamagnetic metal ions cannot have an odd number of electrons.

B
In an octahedral crystal field, the $$d-$$electrons of a metal ion occupy the $$\displaystyle e_{g}$$ set of orbitals before they occupy the $$\displaystyle t_{2g}$$ set of orbitals.

C
Low spin complex may be paramagnetic.

D
In high spin octahedral complex, $$\displaystyle \Delta _{0}$$ is less than the electron pairing energy and is relatively very small.

Solution

Diamagnetic metal ions cannot have an odd number of electrons as their magnetic moment is zero.
Low spin complex may be paramagnetic if they have unpaired electron.
In high spin octahedral complex, $$_0$$ is less than the electron pairing energy and is relatively very small,
This is the reason why electron dont pair & move to upper d-orbitals.
In an octahedral crystal field, the d electrons of a metal ion occupy the $$t_{2g}$$ set of orbitals before they occupy the $$e_g$$ set of orbitals.
Question 8
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Which one of the following pairs of isomers and types of isomerism are correctly matched?
(i) $$[Co(NH_{3})_{5}(NO_{2})]Cl_{2}$$ and $$[Co(NH_{3})_{5}(ONO)Cl_{2} ... (Linkage)$$
(ii) $$[Cu(NH_{3})_{4}][PtCl_{4}]$$ and $$[Pt(NH_{3})_{4}][CuCl_{4}] ... (Coordination)$$
(iii) $$[PtCl_{2}(NH_{3})_{4}]Br_{2}$$ and $$[PtBr_{2}(NH_{3})_{4}]Cl_{2} ... (Ionization)$$
Select the correct answer using the codes given below:

A
(ii) and (iii)

B
(i), (ii) and (iii)

C
(i) and (iii)

D
(i) and (ii)

Solution

(i) The complexes $$[Co(NH_3)_5(NO_2)]Cl_2$$ and $$[Co(NH_3)_5(ONO)]Cl_2$$ exhibit linkage isomerism.
This is because the nitro group is ambidentate ligand and has two donor atoms N and O.

(ii) The complexes $$[Cu(NH_3)_4][PtCl_4]$$ and $$ [Pt(NH_3)_4][CuCl_4]$$ exhibit coordination isomerism in which the ligands in the complex cation and the complex anion are interchanged.

(iii) The complexes $$[PtCl_2(NH_3)_4]Br_2$$ and $$ [PtBr_2(NH_3)_4]Cl_2$$ are examples of ionization isomers as there is exchange of ions inside and outside the coordination sphere.
Question 9
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The degeneracy of $$d-orbitals$$ is lost under:
(I) Strong field ligand (II) Weak field ligand (III) Mixed field ligand (IV) Chelated ligand field
Choose the correct code.

A
I, II and IV

B
I and II

C
I, II, III and IV

D
I, II and III

Solution

When the ligands approach the metal ions, the degeneracy of d-orbitals is lost . This is irrespective of the strength of the strength of the ligand field.
Thus ligand field created by strong, weak, mixed or chelating ligands cause the loss of the degeneracy of d-orbitals.

Question 10

1 / -0

Match List-I with List-II and select the correct answer using the codes given below:

List I	List II
(I) $$[FeF_{6}]^{3-}$$	(A) $$1.73\ BM$$
(II) $$[Ti(H_{2}O)_{6}]^{3+}$$	(B) $$5.93\ BM$$
(III) $$[Cr(NH_{3})_{6}]^{3+}$$	(C) $$0.00\ BM$$
(IV) $$[Ni(H_{2}O)_{6}]^{2+}$$	(D) $$2.83\ BM$$
(V) $$[Fe(CN)_{6}]^{4-}$$	(E) $$3.88\ BM$$

$$B A C D E$$

$$B A E D C$$

$$B C D E A$$

$$D E A B C$$

Solution

(i) In $$[FeF_6]^{3-}$$, the central metal ion has the oxidation state of +3. It has $$3d^5$$ configuration and undergoes $$sp^3d^2$$ hybridization. It contains 5 unpaired electrons and has magnetic moment value of 5.91 B.M.

(ii) In $$[Ti(H_2O)_6]^{3+}$$, the central metal ion has the oxidation state of +3. It has $$3d^1$$ configuration and undergoes $$d^2sp^3$$ hybridization. It contains 1 unpaired electron and has magnetic moment value of 1.732 B.M.

(iii) In $$[Cr(NH_3)_6]^{3+}$$, the central metal ion has the oxidation state of +3. It has $$3d^3$$ configuration and undergoes $$d^2sp^3$$ hybridization. It contains 3 unpaired electrons and has magnetic moment value of 3.88 B.M.

(iv) In $$[Ni(H_2O)_6]^{2+}$$, the central metal ion has the oxidation state of +2. It has $$3d^8$$ configuration and undergoes $$sp^3d^2$$ hybridization. It contains 2 unpaired electrons and has magnetic moment value of 2.83 B.M.

(v) In $$[Fe(CN)_6]^{4-}$$, the central metal ion has the oxidation state of +2. It has $$3d^6$$ configuration and undergoes $$d^2sp^3$$ hybridization. It contains 0 unpaired electrons and has magnetic moment value of 0 B.M.

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Coordination Compounds Test - 48

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Coordination Compounds Test - 48

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Question 1

x- and y

y-only

x-only

z-only

Solution

Question 2

Hybridization is the separation of atomic orbitals.

$$sp^{2}-$$ hybrid orbitals are formed form two p- atomic orbitals and one s- atomic orbitals.

$$dsp^{2}-$$ hybrid orbitals are at $$\displaystyle\:90^{\circ}$$ to one another.

$$d^{2}sp^{3}-$$ hybrid orbitals are directed towards the corners of a regular octahedron.

Solution

Question 3

I, II, III all are correct.

I, II are correct

II, III are correct

III only correct

Solution

Question 4

Chlorophyll is a green pigment in plants and contains calcium

Haemoglobin is the red pigment of blood and contains iron

Cyanocobalamin is $$\displaystyle B_{12}$$ and contains cobalt

Carboxypeptidase A is an enzyme and contains zinc

Solution

Question 5

1, 2 and 3 are correct

2 and 3 are correct

1 and 3 are correct

1 and 2 are correct

Solution

Question 6

Nitrito $$\displaystyle -$$ N $$\displaystyle -$$ pentaammine cobalt ( III ) chloride.

Nitrito $$\displaystyle -$$ N $$\displaystyle -$$ pentaammine cobalt ( II ) chloride.

Pentaammine nitrito $$\displaystyle -$$ N $$\displaystyle -$$ cobalt ( II ) chloride.

Pentaammine nitrito $$\displaystyle -$$ N $$\displaystyle -$$ cobalt ( III ) chloride.

Solution

Question 7

Diamagnetic metal ions cannot have an odd number of electrons.

In an octahedral crystal field, the $$d-$$electrons of a metal ion occupy the $$\displaystyle e_{g}$$ set of orbitals before they occupy the $$\displaystyle t_{2g}$$ set of orbitals.

Low spin complex may be paramagnetic.

In high spin octahedral complex, $$\displaystyle \Delta _{0}$$ is less than the electron pairing energy and is relatively very small.

Solution

Question 8

(ii) and (iii)

(i), (ii) and (iii)

(i) and (iii)

(i) and (ii)

Solution

Question 9

I, II and IV

I and II

I, II, III and IV

I, II and III

Solution

Question 10

$$B A C D E$$

$$B A E D C$$

$$B C D E A$$

$$D E A B C$$

Solution

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