Self Studies

Electrostatic Potential and Capacitance Test - 57

Result Self Studies

Electrostatic Potential and Capacitance Test - 57
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    The capacitance of a parallel plate capacitor is $$2.5\mu F$$. When it is half-filled with a dielectric shown in the figure Its capacitance becomes $$5\mu F$$, the dielectric constant of the dielectric is :

    Solution
    Let area of each plate be A and spacing between then be d.
    Then capacitance of parallel plate capacitor, $$C = \dfrac{\epsilon_0A}{d} = 2.5\mu F$$

    When it is half filled with dielectric, capacitance of capacitor filled with air, $$C_1 = \dfrac{\epsilon_0 (A/2)}{d}$$

    capacitance of capacitor filled with medium of dielectric constant $$ k$$ is $$C_2 = \dfrac{k\epsilon_0 (A/2)}{d}$$
     
    Since $$C_1$$ and $$C_2$$ are in parallel, equivalent capacitance will be, $$C' = C_1+C_2 = 5\mu F$$

    $$\dfrac{\epsilon_0A}{2d} +\dfrac{k\epsilon_0}{2d} = 5$$

    $$\dfrac{2.5}{2} +\dfrac{k\times2.5}{2} = 5$$

    $$1+k = 4$$

    $$k =3$$
  • Question 2
    1 / -0
    In the circuit shown in figure $$C=6\mu F$$. The charge stored in the capacitor of capacity $$C$$ is($$Voltage =10V$$):

    Solution

  • Question 3
    1 / -0
    A parallel plate capacitor with air between the plates has a capacitance of 2pF. The capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6 is
    Solution
    We know,

    $$C=\dfrac{Ak\varepsilon_0}{d}$$

    Given,
    For $$k=1,$$
    $$C=\dfrac{A\varepsilon_0}{d}=2$$

    For k=6, and $$d\rightarrow \dfrac{d}{2}$$

    $$C=\dfrac{A\times 6\varepsilon_0}{\dfrac{d}{2}}$$

    $$C=\dfrac{12A\varepsilon_0}{d}=12C=24pF$$

    Option $$\textbf B$$ is the correct answer
  • Question 4
    1 / -0
    A dielectric slab is inserted between the plates of a capacitor is $$Q$$ and the magnitude of the induced charges on each surface of the dielectric is $$Q$$,
  • Question 5
    1 / -0
    Determine the equivalent capacitance between point $$S$$ and $$V$$, as shown in fig.

  • Question 6
    1 / -0
    A parallel plate capacitor consists of two circular disc separated by a small distance it is capacitance of see the radius of discus half and separation between disc is doubled a medium of dielectric constant K is introduced between the desk the new capacitance is found to be same as that of the original capacitance C the dielectric constant of medium is
  • Question 7
    1 / -0
    Six identical square metallic plates are arranged as shown in figure length of each plate is l the capacitance of this arrangement should be
  • Question 8
    1 / -0
    Find the equivalent capacitance across A & B 

    Solution
    The Capacitance $$23\mu f$$ and $$12\mu f,1\mu f$$  and $$1\mu f$$  are connected in paralled so their equivalent capacitance is : $$(23+12)\mu f,(1+1)\mu f$$ respectively i,e
    $$35\mu f$$ and $$2\mu f$$
    Now  the whole circuit is in form  of wheatsfftone bridge with : 
    $$C_{1}=35\mu f,C_{2}=\mu f,C_{3}=10\mu f$$ and $$C_{4}=2\mu f$$
    Clearly, $$\dfrac{C_{1}}{C_{2}}=\dfrac{C_{3}}{C_{4}}=5$$
    So  $$13\mu f$$ capacitor is neglected 
    Now  equivalent capacitance of $$C_{1}$$  and $$C_{2}$$  in series =  $$\dfrac{C_{1}C_{2}}{C_{1}+C_{2}}\mu f$$
    Equivalent capacitance of $$C_{3} $$ and $$C_{4}$$  in series = $$\dfrac{10\times 2}{10+2}=\dfrac{20}{12}$$$$\mu f$$
    Now these  two  equivalent capacitances are  connected in parallel so  their equivalent is : 
    $$C_{eq}=\dfrac{245}{42}+\dfrac{20}{12}=\dfrac{15}{2}\mu f$$
  • Question 9
    1 / -0
    A capacitor of capacitance 1 $$\mu F$$ withstands the maximum voltage 6 kV while a capacitor of 2 $$\mu F$$ withstands the maximum voltage 4 kV. What maximum voltage will the system of these two capacitor withstands if they are connected in series?
    Solution

  • Question 10
    1 / -0
    The potential difference between points $$A$$ and $$B$$ in the circuit shown in figure, will be:-

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now