Electrostatic P...

The capacitance of a parallel plate capacitor is $$2.5\mu F$$. When it is half-filled with a dielectric shown in the figure Its capacitance becomes $$5\mu F$$, the dielectric constant of the dielectric is :

In the circuit shown in figure $$C=6\mu F$$. The charge stored in the capacitor of capacity $$C$$ is($$Voltage =10V$$):

A parallel plate capacitor with air between the plates has a capacitance of 2pF. The capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6 is

A dielectric slab is inserted between the plates of a capacitor is $$Q$$ and the magnitude of the induced charges on each surface of the dielectric is $$Q$$,

Determine the equivalent capacitance between point $$S$$ and $$V$$, as shown in fig.

A parallel plate capacitor consists of two circular disc separated by a small distance it is capacitance of see the radius of discus half and separation between disc is doubled a medium of dielectric constant K is introduced between the desk the new capacitance is found to be same as that of the original capacitance C the dielectric constant of medium is

Six identical square metallic plates are arranged as shown in figure length of each plate is l the capacitance of this arrangement should be

Find the equivalent capacitance across A & B 

A capacitor of capacitance 1 $$\mu F$$ withstands the maximum voltage 6 kV while a capacitor of 2 $$\mu F$$ withstands the maximum voltage 4 kV. What maximum voltage will the system of these two capacitor withstands if they are connected in series?

The potential difference between points $$A$$ and $$B$$ in the circuit shown in figure, will be:-