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  • Question 1
    1 / -0
    50 mL of 0.1M solution of a salt reacted with 25 mL of 0.1M solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is:



    If the oxidation number of metal in the salt was 3, then what would be the new oxidation number of the metal?
    Solution
    Meq of sodium sulphite = Meq of salt 25 0.1 2 = 50 0.1 n
    n = 1 (Where `n` represents valence factor for metal involving number of electrons gained)
    Thus, M+3 + e- M+2
    Hence, new oxidation number of metal 'M' = +2
  • Question 2
    1 / -0
    In the given reaction, [X] is

    Solution
    Reaction proceeds through SN1 mechanism. There is a formation of carbocation at ortho position and resonance effect is more predominant over negative inductive effect of oxygen. Thus, 3,4-dichloro-2-methoxy-1-oxacyclo hexane is formed as a major product.

  • Question 3
    1 / -0
    The molecule/ion in which the central atom violates the octet rule is:
    Solution
    In SF4, central atom 'S' has sp3d hybridisation. It forms four bonds with four flourine atoms (total 8 electrons) and has a one lone pair of electrons. Therefore, 'S' has total 10 electrons around it and it violates the octet rule.
  • Question 4
    1 / -0
    Isostructural molecules among the following pairs are:
    Solution
    Compounds having same shape involving same hybridisation of the central atom are isostructural. Both XeF2 and IF2- are linear species involving sp3d hybridisation of the central atom.
  • Question 5
    1 / -0
    Directions: In the following question, two statements are given. Examine these statements carefully and mark the correct answer accordingly.

    STATEMENT-1:
    Boat conformation of cyclohexane suffers from angle strain and torsional strain.
    STATEMENT-2: Boat conformation has bond angle 109028' and eclipsing of hydrogen takes place.
    Solution
    STATEMENT-1 is False, STATEMENT-2 is True.
    Boat conformation of cyclohexane does not suffer from angle strain but suffers from torsional strain due to eclipsing of hydrogen.

  • Question 6
    1 / -0
    The depression in freezing point for 10% (w/w) aqueous glucose (M.W: 180) is T (K). The freezing point of 10% (w/w) aqueous urea (M.W: 60) solution is:
    Solution
    Calculate the molality of glucose and urea.

    Molality =

    Molality of glucose (m1) =

    Molality of urea (m2) =

    It is clear from the above calculations,

    Molality of urea = 3 x molality of glucose

    As





    T2 = 273 - Tf = 273 - 3T
  • Question 7
    1 / -0
    A hydrogenation reaction is carried out at 500 K. If the same reaction is carried out in the presence of a catalyst at the same rate, the temperature required is 400 K. The activation energy of the reaction if the catalyst lowers the activation barrier by 20 kJ/mol is
    Solution
    Let the activation energy at 500 K be E1 and at 400 K be E2.

    Therefore, E2 = (E1 - 20) kJ/mol



    = 1

    On solving,

    -E1/R x 500 = -(E1 - 20)/R x 400

    E1 = 100 kJ

    E2 = 80 kJ
  • Question 8
    1 / -0
    Directions: In the following question, two statements are given. Examine these statements carefully and mark the correct answer accordingly.

    STATEMENT-1:
    Zn(OH)2 is amphoteric in water and Zn(NH2)2 is amphoteric in ammonia.
    STATEMENT-2: Liquid ammonia resembles the aqueous system quite closely.
    Solution
    Statements 1 and 2 are true but statement 2 is not the correct explanation of statement 1.

    Amphoteric behaviour:

    Zn(OH)2 + NaOH Na2Zn(OH)4 (in water)
    excess
    Zn(NH2)2 + KNH2 K2[Zn(NH3)4] (in ammonia)
    excess
  • Question 9
    1 / -0
    How much faster would a reaction proceed at 127oC than 27oC, if the activation energy is 92.12 J? (R = 8.3 J)
    Solution
    k = Ae-Ea/RT

    k1 = Ae-Ea/R x 400

    k2 = Ae-Ea/R x 300

    k1/k2 = e-Ea/R[1/400 - 1/300]

    Taking log both sides:

    log k1/k2 = 103.08
  • Question 10
    1 / -0
    In the reaction
    ,
    , then which of the following aryl halides is most reactive?
    Solution
    Since F is the most reactive element, density on ring carbon atom and resulting intermediate stabilises by F. Thus, Ar-F is most reactive.
  • Question 11
    1 / -0
    Dibromosuccinic acid decomposes according to the following reaction:

    C2H2Br(COOH)2 C2HBr(COOH)2 + HBr

    When 50 ml of acid is titrated against standard NaOH at various time intervals, at t = 0, 30 ml of NaOH and at t = 200 min, 33 ml of NaOH were required. The extent of the reaction in mole % is
    Solution
    DBS C2HBr (COO)2 + HBr
    C(1 - x) Cx Cx
    At t = 0, C = 30
    And at t = 200 min,
    C(1 - x) + Cx + Cx = 33
    C(1 + x) = 33
    (1 + x) =
    x =
    Extent of the reaction = 0.1 x 100 = 10%
  • Question 12
    1 / -0
    Solution
    NaBH4 does not reduce acid`s derivative.
  • Question 13
    1 / -0
    The correct order of bond angles is:
    Solution
    Bond angle depends on repulsions between the lone pair and bond pair electrons.
    L.P. - L.P. > L.P. - B.P. > B.P. - B.P.
    Repulsions Repulsions Repulsions
  • Question 14
    1 / -0
    Which of the following reacts with excess methyl magnesium bromide followed by acid hydrolysis to produce 2,3,3-trimethyl-2-pentanol?
    Solution
  • Question 15
    1 / -0
    What is the product of the reaction of 1-methylcyclopentanol with sodium dichromate and acetic acid?
    Solution
    Tertiary alcohols do not undergo oxidation under normal conditions. On strong oxidation, the molecule gets cleaved and a complex mixture of products is formed.
  • Question 16
    1 / -0
    For the reaction at 184oC and 0.083 JK-1 mol-1, when Kp and Kc are compared at 184oC, it is found that
    Solution
    n = 1

    Kp = Kc (RT)1

    Kp > Kc
  • Question 17
    1 / -0
    A weak acid BOH has the dissociation constant 1 10-5 M. It forms a salt BCl on reaction with HCl. The degree of hydrolysis of 0.1 M solution of BCl is
    Solution
    h =

    h = 10-4

    %h = 10-2 = 0.01%
  • Question 18
    1 / -0


    (I) rf = kf [A]2 [B] and rb = kb [C]3 [D]
    (II) If temperature is increased, then the reaction shifts in forward direction.
    (III) Keq(P) =
    (IV) On adding an inert gas at constant pressure, the reaction shifts in the forward direction.
    Solution
  • Question 19
    1 / -0
    Solubility of BaF2 in a solution of Ba(NO3)2 will be represented by the concentration terms:
    Solution
    Let `S` be the solubility of BaF2 in a solution of BaNO3, then

    Ksp = ;

    Then, = 2s or = s
  • Question 20
    1 / -0
    Which of the following can act as a buffer?
    Solution
    NaCN (4 millimoles) and HCl (2 millimoles) on reaction give 2 millimoles of HCN and 2 millimoles of NaCN are left which act as a buffer solution
  • Question 21
    1 / -0
    Kb for the hydrolysis reaction, B+ + H2O BOH + H+ is 1.0 10-6. The hydrolysis constant of the salt is
    Solution
    For hydrolysis of B+;

    KH = = 10-8
  • Question 22
    1 / -0
    A weak acid HX (Ka = 1 10-7) on reaction with NaOH gives NaX for 0.1M aqueous solution of NaX, the percentage hydrolysis is
    Solution
    For NaX,

    h =

    =

    =

    %h = 0.1%
  • Question 23
    1 / -0
    pH of water is 7.0 at 25oC. If water is heated to 70oC, then the
    Solution
    On heating water, Kw increases and the pH value changes from 7 to some lower value.
  • Question 24
    1 / -0
    The degree of hydrolysis of a salt of a weak acid and a weak base in its 0.1M solution is found to be 50%. If the molarity of the solution is 0.2M, then the percentage hydrolysis of the salt should be
    Solution
    The degree of hydrolysis of a salt of a weak acid and a weak base is independent of the concentration of salt.
  • Question 25
    1 / -0


    C is
    Solution
    First (-OH) is protected from acylation, then methylation and substitution by chlorine take place.
  • Question 26
    1 / -0
    A solution of a substance containing 1.05 g per 100 mL was found to be isotonic with 3% glucose solution. The molecular mass of the substance is
    Solution
    If the solutions are isotonic in nature, then the concentrations of both the solutions are equal per litre of the solvent.
    Concentration of unknown substance = Concentration of glucose solution



    M = 63
  • Question 27
    1 / -0
    Consider two liquids A and B, having pure vapour pressures and respectively, forming an ideal solution. The plot of (when XA and YA are the mole fractions of A in liquid and vapour phases respectively) is linear with slope and intercepts
    Solution






    Slope: ; Intercept:
  • Question 28
    1 / -0
    In one of Bohr`s orbits of hydrogen atom, an electron possesses a wavelength of 13.32 A0. When it falls into an orbit, its wavelength is found to be 6.66 A0. The wavelength of spectral line emitted in this transition is nearly
    Solution
    Wavelength of an electron in 1st orbit of Hydrogen = 2r = 2 x 3.14 x 0.529 = 3.33 nm

    Wavelength of an electron in nth orbit = n x Wavelength of an electron in 1st orbit



    ; n2 = 4

    ; n1 = 2

    According to Reyberg's formula:




    or
    [1 m = 109 nm]

    = 486.2 nm

  • Question 29
    1 / -0
    Estimate the difference in energy between first and second Bohr's orbits for a hydrogen atom. At what minimum atomic number would a transition from n = 2 to n = 1 energy level result in the emission of X-rays with = 3 × 108 m?
    Solution
    For hydrogen atom E1 = -13.6 eV

    E2 for hydrogen = = -3.4 eV

    E2 - E1 = -3.4 - (-13.6) = 10.2 eV

    For transition of H-like atom:

  • Question 30
    1 / -0
    Identify the reaction in which the given product is not correct.
    Solution
    (A)




    (D) Houben-Hoesch reaction is an extension of Gattermann reaction. The actual product is:

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