Logical Reasoning & DI (LRDI) Test

Result

Logical Reasoning & DI (LRDI) Test - 16

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
3 / -1

Directions For Questions

Four Friends, Amal, Bimal, Chetan, and Dhoni went to a fruit seller and bought a total of 55 items of fruits of 3 categories - Apple, Orange, and Banana. None of the friends bought the same number of total items and each of them bought at least one item from each category.
The following facts are also known about the categories:
i) The number of apples and bananas purchased by Amal is the same, while the number of orange items purchased by him is thrice of apples.
ii) The number of Apples purchased by Bimal is the average of the number of fruits he purchased in the other two categories. The number of Bananas purchased by Bimal is more than the number of apples he purchased.
iii) Out of the total fruits purchased by Chetan, 3/7^th belonged to apples and 2/7^th to Bananas.
iv) Apples, Oranges, and Bananas purchased by Dhoni are in the ratio 2:2:3.
v) The total number of fruits purchased by Dhoni was less than the number of oranges purchased by Amal.

...view full instructions

Which of the following cannot be the sum of the fruits bought by Chetan and Bimal?

A
16

B
23

C
24

D
33

Solution

From the data given in the question, we can make the following table,

Let (a+b)/2 = m.

Here, it is given that the number of oranges purchased by Amal is greater than the total number of fruits purchased by Dhoni.

Thus, 3x>7z

Consider the case when z = 2. So, 7z = 14

Thus, x will be atleast 5 to make 3x = 15.

Or, the total number of fruits purchased by Amal will be atleast 25(Total = 5x).

So, the number of fruits purchased by Amal and Dhoni will be atleast 25+14 = 39.

The total number of fruits left = 55 - 39 = 16.

Thus, 3m+7y = 16

This case is possible when m = 3 and y = 1.

Consider the case when z = 3. So, 7z = 21

Here 3x will be atleast 24.

Thus, the total fruits purchased by Amal will be atleast 40.

Since this is already greater than the total fruits purchased by all, this is not the correct option.

Now, consider the case when z = 1. So, 7z = 7

Thus, 3x will be atleast 9.

Thus, the total number of fruits purchased by Amal will be atleast 15.

Now, the total number of fruits purchased by Amal and Dhoni will be atleast 15+7 = 22

Since the number of fruits purchased for any of them cannot be equal, Chetan will purchase at least 14 fruits. Also, the least number of fruits that Bimal can purchase is 6(since the value s equal to 3m, and the number of bananas is greater than the number of apples)

Thus, the total number of fruits purchased by Amal, Bimal, Chetan, and Dhoni will be at least 22+14+6=42.

Thus, the difference 13(55-42) will be allotted to Amal, Bimal, and Chetan

Since we know that the total of fruits with Amal, Bimal, and Chetan is a multiple of 5, 3, and 7, respectively,

5p+3q+7r = 13, where p, q, and r are random variables.

The triplets(p,q,r) that will satisfy the above equation will be (2,1,0), and (0,2,1).

Thus, when x, m, y, and z are 5, 3, 2, and 1, respectively.

Hence, we will get the three different possible scenarios, which are given below:

Also, when x, m, y, and z are 3, 4, 3, and 1, respectively, we will get the following table:

When z =2, we get the following table:

Possible values for the sum of the fruits bought by Chetan and Bimal are (9+7), (14+9) and (12+21).

The answer is option C.
Question 2
3 / -1

Directions For Questions

Four Friends, Amal, Bimal, Chetan, and Dhoni went to a fruit seller and bought a total of 55 items of fruits of 3 categories - Apple, Orange, and Banana. None of the friends bought the same number of total items and each of them bought at least one item from each category.
The following facts are also known about the categories:
i) The number of apples and bananas purchased by Amal is the same, while the number of orange items purchased by him is thrice of apples.
ii) The number of Apples purchased by Bimal is the average of the number of fruits he purchased in the other two categories. The number of Bananas purchased by Bimal is more than the number of apples he purchased.
iii) Out of the total fruits purchased by Chetan, 3/7^th belonged to apples and 2/7^th to Bananas.
iv) Apples, Oranges, and Bananas purchased by Dhoni are in the ratio 2:2:3.
v) The total number of fruits purchased by Dhoni was less than the number of oranges purchased by Amal.

...view full instructions

If Chetan has 3k apples, where k is the number of bananas Amal has, find the total number of apples?

A
3k+11

B
3k+9

C
3k+3

D
Cannot be determined

Solution

From the data given in the question, we can make the following table,

Let (a+b)/2 = m.

Here, it is given that the number of oranges purchased by Amal is greater than the total number of fruits purchased by Dhoni.

Thus, 3x>7z

Consider the case when z = 2. So, 7z = 14

Thus, x will be atleast 5 to make 3x = 15.

Or, the total number of fruits purchased by Amal will be atleast 25(Total = 5x).

So, the number of fruits purchased by Amal and Dhoni will be atleast 25+14 = 39.

The total number of fruits left = 55 - 39 = 16.

Thus, 3m+7y = 16

This case is possible when m = 3 and y = 1.

Consider the case when z = 3. So, 7z = 21

Here 3x will be atleast 24.

Thus, the total fruits purchased by Amal will be atleast 40.

Since this is already greater than the total fruits purchased by all, this is not the correct option.

Now, consider the case when z = 1. So, 7z = 7

Thus, 3x will be atleast 9.

Thus, the total number of fruits purchased by Amal will be atleast 15.

Now, the total number of fruits purchased by Amal and Dhoni will be atleast 15+7 = 22

Since the number of fruits purchased for any of them cannot be equal, Chetan will purchase at least 14 fruits. Also, the least number of fruits that Bimal can purchase is 6(since the value s equal to 3m, and the number of bananas is greater than the number of apples)

Thus, the total number of fruits purchased by Amal, Bimal, Chetan, and Dhoni will be at least 22+14+6=42.

Thus, the difference 13(55-42) will be allotted to Amal, Bimal, and Chetan

Since we know that the total of fruits with Amal, Bimal, and Chetan is a multiple of 5, 3, and 7, respectively,

5p+3q+7r = 13, where p, q, and r are random variables.

The triplets(p,q,r) that will satisfy the above equation will be (2,1,0), and (0,2,1).

Thus, when x, m, y, and z are 5, 3, 2, and 1, respectively,

Hence, we will get the three different possible scenarios, which are given below:

Also, when x, m, y, and z are 3, 4, 3, and 1, respectively, we will get the following table:

When z =2, we get the following table:

The case mentioned is the middle one.

Here k= 3, and Chetan has 9 apples.

The number of apples is equal to 6k, or 3k+9.

The correct option is B.
Question 3
3 / -1

Directions For Questions

Four Friends, Amal, Bimal, Chetan, and Dhoni went to a fruit seller and bought a total of 55 items of fruits of 3 categories - Apple, Orange, and Banana. None of the friends bought the same number of total items and each of them bought at least one item from each category.
The following facts are also known about the categories:
i) The number of apples and bananas purchased by Amal is the same, while the number of orange items purchased by him is thrice of apples.
ii) The number of Apples purchased by Bimal is the average of the number of fruits he purchased in the other two categories. The number of Bananas purchased by Bimal is more than the number of apples he purchased.
iii) Out of the total fruits purchased by Chetan, 3/7^th belonged to apples and 2/7^th to Bananas.
iv) Apples, Oranges, and Bananas purchased by Dhoni are in the ratio 2:2:3.
v) The total number of fruits purchased by Dhoni was less than the number of oranges purchased by Amal.

...view full instructions

If Bimal bought 5 bananas, what is the number of apples bought by him?

A
2

B
3

C
4

D
More than one of the above.

Solution

From the data given in the question, we can make the following table,

Let (a+b)/2 = m.

Here, it is given that the number of oranges purchased by Amal is greater than the total number of fruits purchased by Dhoni.

Thus, 3x>7z

Consider the case when z = 2. So, 7z = 14

Thus, x will be atleast 5 to make 3x = 15.

Or, the total number of fruits purchased by Amal will be atleast 25(Total = 5x).

So, the number of fruits purchased by Amal and Dhoni will be atleast 25+14 = 39.

The total number of fruits left = 55 - 39 = 16.

Thus, 3m+7y = 16

This case is possible when m = 3 and y = 1.

Consider the case when z = 3. So, 7z = 21

Here 3x will be atleast 24.

Thus, the total fruits purchased by Amal will be atleast 40.

Since this is already greater than the total fruits purchased by all, this is not the correct option.

Now, consider the case when z = 1. So, 7z = 7

Thus, 3x will be atleast 9.

Thus, the total number of fruits purchased by Amal will be atleast 15.

Now, the total number of fruits purchased by Amal and Dhoni will be atleast 15+7 = 22

Since the number of fruits purchased for any of them cannot be equal, Chetan will purchase at least 14 fruits. Also, the least number of fruits that Bimal can purchase is 6(since the value s equal to 3m, and the number of bananas is greater than the number of apples)

Thus, the total number of fruits purchased by Amal, Bimal, Chetan, and Dhoni will be at least 22+14+6=42.

Thus, the difference 13(55-42) will be allotted to Amal, Bimal, and Chetan

Since we know that the total of fruits with Amal, Bimal, and Chetan is a multiple of 5, 3, and 7, respectively,

5p+3q+7r = 13, where p, q, and r are random variables.

The triplets(p,q,r) that will satisfy the above equation will be (2,1,0), and (0,2,1).

Thus, when x, m, y, and z are 5, 3, 2, and 1, respectively,

Hence, we will get the three different possible scenarios, which are given below:

Also, when x, m, y, and z are 3, 4, 3, and 1, respectively, we will get the following table:

When z =2, we get the following table:

The number of apples can be 3 or 4 with Bimal when he bought 5 bananas.

The correct option is D.
Question 4
3 / -1

Directions For Questions

Four Friends, Amal, Bimal, Chetan, and Dhoni went to a fruit seller and bought a total of 55 items of fruits of 3 categories - Apple, Orange, and Banana. None of the friends bought the same number of total items and each of them bought at least one item from each category.
The following facts are also known about the categories:
i) The number of apples and bananas purchased by Amal is the same, while the number of orange items purchased by him is thrice of apples.
ii) The number of Apples purchased by Bimal is the average of the number of fruits he purchased in the other two categories. The number of Bananas purchased by Bimal is more than the number of apples he purchased.
iii) Out of the total fruits purchased by Chetan, 3/7^th belonged to apples and 2/7^th to Bananas.
iv) Apples, Oranges, and Bananas purchased by Dhoni are in the ratio 2:2:3.
v) The total number of fruits purchased by Dhoni was less than the number of oranges purchased by Amal.

...view full instructions

What is the total number combinations possible for this distribution?

A
7

B
74

C
77

D
79

Solution

From the data given in the question, we can make the following table,

Let (a+b)/2 = m.

Here, it is given that the number of oranges purchased by Amal is greater than the total number of fruits purchased by Dhoni.

Thus, 3x>7z

Consider the case when z = 2. So, 7z = 14

Thus, x will be atleast 5 to make 3x = 15.

Or, the total number of fruits purchased by Amal will be atleast 25(Total = 5x).

So, the number of fruits purchased by Amal and Dhoni will be atleast 25+14 = 39.

The total number of fruits left = 55 - 39 = 16.

Thus, 3m+7y = 16

This case is possible when m = 3 and y = 1.

Consider the case when z = 3. So, 7z = 21

Here 3x will be atleast 24.

Thus, the total fruits purchased by Amal will be atleast 40.

Since this is already greater than the total fruits purchased by all, this is not the correct option.

Now, consider the case when z = 1. So, 7z = 7

Thus, 3x will be atleast 9.

Thus, the total number of fruits purchased by Amal will be atleast 15.

Now, the total number of fruits purchased by Amal and Dhoni will be atleast 15+7 = 22

Since the number of fruits purchased for any of them cannot be equal, Chetan will purchase at least 14 fruits. Also, the least number of fruits that Bimal can purchase is 6(since the value s equal to 3m, and the number of bananas is greater than the number of apples)

Thus, the total number of fruits purchased by Amal, Bimal, Chetan, and Dhoni will be at least 22+14+6=42.

Thus, the difference 13(55-42) will be allotted to Amal, Bimal, and Chetan

Since we know that the total of fruits with Amal, Bimal, and Chetan is a multiple of 5, 3, and 7, respectively,

5p+3q+7r = 13, where p, q, and r are random variables.

The triplets(p,q,r) that will satisfy the above equation will be (2,1,0), and (0,2,1).

Thus, when x, m, y, and z are 5, 3, 2, and 1, respectively,

Hence, we will get the three different possible scenarios, which are given below:

Also, when x, m, y, and z are 3, 4, 3, and 1, respectively, we will get the following table:

When z =2, we get the following table:

The first and third tables can have two cases each, and the second can have three cases.
Thus, the total number of possible cases will be 2+2+3 = 7.
Question 5
3 / -1

Directions For Questions

Four Friends, Amal, Bimal, Chetan, and Dhoni went to a fruit seller and bought a total of 55 items of fruits of 3 categories - Apple, Orange, and Banana. None of the friends bought the same number of total items and each of them bought at least one item from each category.
The following facts are also known about the categories:
i) The number of apples and bananas purchased by Amal is the same, while the number of orange items purchased by him is thrice of apples.
ii) The number of Apples purchased by Bimal is the average of the number of fruits he purchased in the other two categories. The number of Bananas purchased by Bimal is more than the number of apples he purchased.
iii) Out of the total fruits purchased by Chetan, 3/7^th belonged to apples and 2/7^th to Bananas.
iv) Apples, Oranges, and Bananas purchased by Dhoni are in the ratio 2:2:3.
v) The total number of fruits purchased by Dhoni was less than the number of oranges purchased by Amal.

...view full instructions

What is the maximum possible number of Bananas bought by them?

A
19

B
194

C
197

D
199

Solution

From the data given in the question, we can make the following table,

Let (a+b)/2 = m.

Here, it is given that the number of oranges purchased by Amal is greater than the total number of fruits purchased by Dhoni.

Thus, 3x>7z

Consider the case when z = 2. So, 7z = 14

Thus, x will be atleast 5 to make 3x = 15.

Or, the total number of fruits purchased by Amal will be atleast 25(Total = 5x).

So, the number of fruits purchased by Amal and Dhoni will be atleast 25+14 = 39.

The total number of fruits left = 55 - 39 = 16.

Thus, 3m+7y = 16

This case is possible when m = 3 and y = 1.

Consider the case when z = 3. So, 7z = 21

Here 3x will be atleast 24.

Thus, the total fruits purchased by Amal will be atleast 40.

Since this is already greater than the total fruits purchased by all, this is not the correct option.

Now, consider the case when z = 1. So, 7z = 7

Thus, 3x will be atleast 9.

Thus, the total number of fruits purchased by Amal will be atleast 15.

Now, the total number of fruits purchased by Amal and Dhoni will be atleast 15+7 = 22

Since the number of fruits purchased for any of them cannot be equal, Chetan will purchase at least 14 fruits. Also, the least number of fruits that Bimal can purchase is 6(since the value s equal to 3m, and the number of bananas is greater than the number of apples)

Thus, the total number of fruits purchased by Amal, Bimal, Chetan, and Dhoni will be at least 22+14+6=42.

Thus, the difference 13(55-42) will be allotted to Amal, Bimal, and Chetan

Since we know that the total of fruits with Amal, Bimal, and Chetan is a multiple of 5, 3, and 7, respectively,

5p+3q+7r = 13, where p, q, and r are random variables.

The triplets(p,q,r) that will satisfy the above equation will be (2,1,0), and (0,2,1).

Thus, when x, m, y, and z are 5, 3, 2, and 1, respectively,

Hence, we will get the three different possible scenarios, which are given below:

Also, when x, m, y, and z are 3, 4, 3, and 1, respectively, we will get the following table:

When z =2, we get the following table:

Thus, the maximum number of bananas bought by them will be in the middle case.

The correct answer is 19.
Question 6
3 / -1

Directions For Questions

ABC is a data entry firm which assesses the performance of its employees based on their accuracy. The table given below gives the number of employees corresponding to their accuracy percentage and years of experience.

Note : [10-20) indicates 10 $$\leq$$ % of Accuracy < 20

...view full instructions

A group of 80 employees is given a bonus of Rs.20,000/-.Which of the following can be true about the group.

A
All had at least 9 years of experience and 60% accuracy.

B
Ability to perform was at least 80% accurate.

C
All at least 8 years of experience and 80% accuracy.

D
None of these

Solution

Let us try to evaluate the options

Option A:

We have to calculate the number of employees in [9-11) and [11-13) slab and at least 60% accurate.

=62

But our group had 83 employees .A is incorrect choice

Options B : Number of employees with 80% accuracy = Number of employees in [80-90) and [90-100) slab

= 83 . Hence All 80 members can be frm=om this group.

B is the correct answer.

Option C: The number of employees having at least 8 years experience and 80% accuracy =

Since we have to maximize the number of employees having 8 years experience ,we have to consider all the employees in [7-9) to have at least 8 years of experience

=13+25+10+12+2+7

=69

Since the group can have a maximum of 69 employees C is the incorrect choice.
Question 7
3 / -1

Directions For Questions

ABC is a data entry firm which assesses the performance of its employees based on their accuracy. The table given below gives the number of employees corresponding to their accuracy percentage and years of experience.

Note : [10-20) indicates 10 $$\leq$$ % of Accuracy < 20

...view full instructions

There is a committee visiting the organization to evaluate the employees. So the organization has divided them into 4 groups.An employee can be a member of only one group.
Managerial group $$G_1$$: Employees with at least 11 yrs of exp and 80% accuracy
Decisional group $$G_2$$: Employees with at least 9 yrs of exp and 60% accuracy and less than 11 years of experience and 80% accuracy
Interpersonal group $$G_3$$: Employees with at least 5 yrs of exp and 40% accuracy and less than 11 years of experience and 60% accuracy
Informational group $$G_4$$: Employees having at least 20% accuracy and less than 2 years of experience and 80% accuracy

Which among the following options is correct?

A
$$G_1$$*$$G_2$$=$$G_3$$

B
Probability of an employee being selected from $$G_1$$ is less than $$G_2$$

C
$$G_3$$*$$G_2$$=240

D
$$G_3$$+$$G_4$$=82

Solution

Let us calculate the number of employees in each- of the groups

$$G_1$$ : Number of employees in the range of [80-100) and [11-13) slab

=17

$$G_2$$ : Number of employees in the range of [60-80) and [9-11) slab

=6+2=8

$$G_3$$ : Number of employees in the range of [40-60) and [5-11) slab

=1+4+5+6+11+13=40

$$G_4$$ : Number of employees in the range of [20-80) and [0-2) slab

=2+7+3+2+21+7=42

Let's evaluate the options one by one.

Option A:$$G_1$$*$$G_2$$=17*8=136 which is not equal to $$G_3$$.A is a wrong choice.

Option B:Total number of employees=400

Probability of an employee being selected from $$G_1$$ = $$\frac{17}{400}$$ = 0.0425

Probability of an employee being selected from $$G_2$$ = $$\frac{8}{400}$$ =0.02.

Since the probability of an employee being selected from $$G_1$$ is greater than $$G_2$$.B is a wrong choice.

Option C:$$G_3$$*$$G_2$$ = 8*40=320 .C is a wrong choice.

Option D:$$G_3$$+$$G_4$$ = 40+42=82.D is the correct answer.
Question 8
3 / -1

Directions For Questions

ABC is a data entry firm which assesses the performance of its employees based on their accuracy. The table given below gives the number of employees corresponding to their accuracy percentage and years of experience.

Note : [10-20) indicates 10 $$\leq$$ % of Accuracy < 20

...view full instructions

In the age group of [9-11),the accuracy percentage is at least

A
38.89

B
39.93

C
41.58

D
40

Solution

Since we have to find the limiting case ,we will consider the lowest accuracy tile for all the cases.

=$$\frac{2*0+27*10+15*20+23*30+13*40+11*50+6*60+2*70+2*80+25*90}{2+27+15+23+13+11+6+2+2+25}$$

=$$\frac{5240}{126}$$

=41.59

Hence C is the correct answer.
Question 9
3 / -1

Directions For Questions

ABC is a data entry firm which assesses the performance of its employees based on their accuracy. The table given below gives the number of employees corresponding to their accuracy percentage and years of experience.

Note : [10-20) indicates 10 $$\leq$$ % of Accuracy < 20

...view full instructions

For the employees with accuracy in the range [80-90), the average work experience would be atleast

A
8.34

B
9.57

C
9

D
7.53

Solution

Since we have to minimize the work experience of the employees ,we have to consider all the employees in the range of [80-90) to have the lowest work experience in the given range.

=$$\frac{1*0+1*2+3*5+12*7+2*9+7*11}{1+1+3+12+2+7}$$

=$$\frac{196}{26}$$

=7.53

Hence D is the correct answer.
Question 10
3 / -1

Directions For Questions

ABC is a data entry firm which assesses the performance of its employees based on their accuracy. The table given below gives the number of employees corresponding to their accuracy percentage and years of experience.

Note : [10-20) indicates 10 $$\leq$$ % of Accuracy < 20

...view full instructions

Due to the pandemic, ABC started laying off employees with an accuracy of less than 50% or having an experience of fewer than 7 years. What is the approximate percentage decrease in the number of employees who have an experience of atleast 5 years but less than 9 years?

A
76

B
72

C
79

D
67

Solution

First, we need to find out the number of employees in the experience group [5,9)

The total number of employees in [5,9) = $$(8+3+1+7+1+4+25+29+1+3) + (13+12+8+4+5+6+22+4+19+1) = 176$$

Now, the employees in the age group [5-7) will be laid off along with employees having an accuracy of less than 50.

Thus, the number of laid-off employees = $$82+(6+22+4+19+1)=134$$

Thus, the percentage decrease = $$\frac{134}{176}\times\ 100\approx\ 76\%$$

The correct option is A.
Question 11
3 / -1

Directions For Questions

Ravi Shastri wants to select a 5 member team to represent India in England. The team must have 2 bowlers and 3 batsmen.
1. Ishant, Ashwin, Bhuvi and Jadeja are the available bowlers whereas Rohit, Virat, Dhoni, Pant, Shikhar and Rahane are the available batsmen.
2. Ashwin and Jadeja are spinners whereas other 2 are pacers. Ravi Shastri insists on having 1 spinner and 1 pacer in the team.
3. Ishant has a feud with Jadeja. Thus, they cannot play together. Same is the case with Bhuvi and Ashwin.
4. Rahane and Shikhar must be selected together
5. Rohit cannot play with either Virat or Dhoni.

...view full instructions

In how many possible ways can we select the team?

A
10

B
8

C
9

D
6

Solution

From the given conditions we can see that among the bowlers Ishant-Ashwin and Bhuvi-Jadeja are the only pairs possible.
Since Rahane and Shikhar must be selected together. Thus, possible pairs are:-
Rahane-Shikhar-Rohit
Rahane-Shikhar-Virat
Rahane-Shikhar-Dhoni
Rahane-Shikhar-Pant
Also, one possible combination is
Virat-Pant-Dhoni
Thus, there are 5 batting combinations.
For every batting combination, there are 2 bowling combinations.
Hence, a total of 10 possible combinations.
Hence, option A is the correct answer.
Question 12
3 / -1

Directions For Questions

Ravi Shastri wants to select a 5 member team to represent India in England. The team must have 2 bowlers and 3 batsmen.
1. Ishant, Ashwin, Bhuvi and Jadeja are the available bowlers whereas Rohit, Virat, Dhoni, Pant, Shikhar and Rahane are the available batsmen.
2. Ashwin and Jadeja are spinners whereas other 2 are pacers. Ravi Shastri insists on having 1 spinner and 1 pacer in the team.
3. Ishant has a feud with Jadeja. Thus, they cannot play together. Same is the case with Bhuvi and Ashwin.
4. Rahane and Shikhar must be selected together
5. Rohit cannot play with either Virat or Dhoni.

...view full instructions

If Rohit is selected then which of the following player must be selected?

A
Ishant

B
Pant

C
Ashwin

D
Shikhar

Solution

From the given conditions we can see that among the bowlers Ishant-Ashwin and Bhuvi-Jadeja are the only pairs possible.
Since Rahane and Shikhar must be selected together. Thus, possible pairs are:-
Rahane-Shikhar-Rohit
Rahane-Shikhar-Virat
Rahane-Shikhar-Dhoni
Rahane-Shikhar-Pant
Also, one possible combination is
Virat-Pant-Dhoni
Thus, there are 5 batting combinations.
For every batting combination, there are 2 bowling combinations.
Hence, a total of 10 possible combinations.
Thus, if Rohit is selected then Shikhar must be selected.
Hence, option D is the correct answer.
Question 13
3 / -1

Directions For Questions

Ravi Shastri wants to select a 5 member team to represent India in England. The team must have 2 bowlers and 3 batsmen.
1. Ishant, Ashwin, Bhuvi and Jadeja are the available bowlers whereas Rohit, Virat, Dhoni, Pant, Shikhar and Rahane are the available batsmen.
2. Ashwin and Jadeja are spinners whereas other 2 are pacers. Ravi Shastri insists on having 1 spinner and 1 pacer in the team.
3. Ishant has a feud with Jadeja. Thus, they cannot play together. Same is the case with Bhuvi and Ashwin.
4. Rahane and Shikhar must be selected together
5. Rohit cannot play with either Virat or Dhoni.

...view full instructions

If Dhoni is selected then how many teams are possible?

A
2

B
3

C
4

D
5

Solution

From the given conditions we can see that among the bowlers Ishant-Ashwin and Bhuvi-Jadeja are the only pairs possible.
Since Rahane and Shikhar must be selected together. Thus, possible pairs are:-
Rahane-Shikhar-Rohit
Rahane-Shikhar-Virat
Rahane-Shikhar-Dhoni
Rahane-Shikhar-Pant
Also, one possible combination is
Virat-Pant-Dhoni
Thus, there are 5 batting combinations.
For every batting combination, there are 2 bowling combinations.
Hence, a total of 10 possible combinations.
Thus, if Dhoni is selected then 4 teams are possible.
Hence, option C is the correct answer.
Question 14
3 / -1

Directions For Questions

Ravi Shastri wants to select a 5 member team to represent India in England. The team must have 2 bowlers and 3 batsmen.
1. Ishant, Ashwin, Bhuvi and Jadeja are the available bowlers whereas Rohit, Virat, Dhoni, Pant, Shikhar and Rahane are the available batsmen.
2. Ashwin and Jadeja are spinners whereas other 2 are pacers. Ravi Shastri insists on having 1 spinner and 1 pacer in the team.
3. Ishant has a feud with Jadeja. Thus, they cannot play together. Same is the case with Bhuvi and Ashwin.
4. Rahane and Shikhar must be selected together
5. Rohit cannot play with either Virat or Dhoni.

...view full instructions

In how many different teams can Pant and Rohit be together?

A
0

B
04

C
07

D
09

Solution

From the given conditions we can see that among the bowlers Ishant-Ashwin and Bhuvi-Jadeja are the only pairs possible.
Since Rahane and Shikhar must be selected together. Thus, possible pairs are:-
Rahane-Shikhar-Rohit
Rahane-Shikhar-Virat
Rahane-Shikhar-Dhoni
Rahane-Shikhar-Pant
Also, one possible combination is
Virat-Pant-Dhoni
Thus, there are 5 batting combinations.
For every batting combination, there are 2 bowling combinations.
Hence, a total of 10 possible combinations.
Thus, Rohit and Pant cannot be selected together.
The answer is 0.
Question 15
3 / -1

Directions For Questions

Ravi Shastri wants to select a 5 member team to represent India in England. The team must have 2 bowlers and 3 batsmen.
1. Ishant, Ashwin, Bhuvi and Jadeja are the available bowlers whereas Rohit, Virat, Dhoni, Pant, Shikhar and Rahane are the available batsmen.
2. Ashwin and Jadeja are spinners whereas other 2 are pacers. Ravi Shastri insists on having 1 spinner and 1 pacer in the team.
3. Ishant has a feud with Jadeja. Thus, they cannot play together. Same is the case with Bhuvi and Ashwin.
4. Rahane and Shikhar must be selected together
5. Rohit cannot play with either Virat or Dhoni.

...view full instructions

If all the possible teams are considered then which player will be selected the least no of times? (according to the given conditions)

A
Pant - 2 times

B
Rohit - 3 times

C
Either Virat or Dhoni - 4 times

D
Rohit - 2 times

Solution

From the given conditions, we can easily infer that Rohit can only be selected with Rahane and Shikhar since 1. Rohit cannot be picked with either Dhoni or Virat.
2. Shikhar and Rahane must be selected together.
If we select Rohit and Pant together, then we will not be able to select the third batsman.
So, only one possibility to select the three batsmen, and we already know that there are two possibilities to select two bowlers.
So Rohit can only be selected in 2 ways,
1. (Rohit, Rahane, Shikhar, Ishant, Ashwin)
2. (Rohit, Rahane, Shikhar, Bhuvi, Jadeja)
For, Pant, it has to be (2*2=4 ways), and the same goes for Virat and Dhoni (2*2=4 ways).
Question 16
3 / -1

Directions For Questions

Read the following information carefully and answer the questions which follow.

In a society consisting of 200 people, each person reads at least one newspaper among ‘Hindu’, ‘Indian Express’ and ‘Times of India’. It is known that 130 people read ‘Times of India’. The number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’. 100 people read ‘Hindu’. Number of people reading only ‘Indian Express’ and ‘Times of India’ is half of the number of people reading only ‘Hindu and Indian Express. The number of people reading at least 2 newspapers is 50 more than then the number of people who read at least 3 newspapers. 60 people read Indian Express.

...view full instructions

How many people read only ‘Hindu’?

A
30

B
40

C
50

D
60

Solution

We have been given that the number of people reading at least two newspapers is 50 more than the number of people reading at least three newspapers.
Let ‘a’ be the people who read only one newspaper, ‘b’ be the people who read exactly two newspapers and ‘c’ be the people who read exactly three newspapers.
We know that a + b + c = 200
a + 2b + 3c = 130 + 100 + 60 = 290
Subtracting the two equations, we get
b + 2c = 90
We have been given that
(b + c) = 50 + c
=> b = 50
Hence, there are exactly 50 people who read two newspapers. Thus, from equation 1 and 2, we can figure out that a = 130 and c = 20.
Hence, 20 people read all three newspapers. From this we can also figure out that only 10 people read ‘only Indian Express’(number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’). We have also been given that Number of people reading only ‘Indian Express’ and ‘Times of India’ is twice the number of people reading only ‘Hindu and Indian Express. Hence, 10 people must be reading the ToI and IE and 20 people must be reading IE and Hindu. So we have, the following venn diagram.
Question 17
3 / -1

Directions For Questions

Read the following information carefully and answer the questions which follow.

In a society consisting of 200 people, each person reads at least one newspaper among ‘Hindu’, ‘Indian Express’ and ‘Times of India’. It is known that 130 people read ‘Times of India’. The number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’. 100 people read ‘Hindu’. Number of people reading only ‘Indian Express’ and ‘Times of India’ is half of the number of people reading only ‘Hindu and Indian Express. The number of people reading at least 2 newspapers is 50 more than then the number of people who read at least 3 newspapers. 60 people read Indian Express.

...view full instructions

How many people read only Times of India?

A
80

B
804

C
807

D
809

Solution

We have been given that the number of people reading at least two newspapers is 50 more than the number of people reading at least three newspapers.
Let ‘a’ be the people who read only one newspaper, ‘b’ be the people who read exactly two newspapers and ‘c’ be the people who read exactly three newspapers.
We know that a + b + c = 200
a + 2b + 3c = 130 + 100 + 60 = 290
Subtracting the two equations, we get
b + 2c = 90
We have been given that
(b + c) = 50 + c
=> b = 50
Hence, there are exactly 50 people who read two newspapers. Thus, from equation 1 and 2, we can figure out that a = 130 and c = 20.
Hence, 20 people read all three newspapers. From this we can also figure out that only 10 people read ‘only Indian Express’(number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’). We have also been given that Number of people reading only ‘Indian Express’ and ‘Times of India’ is twice the number of people reading only ‘Hindu and Indian Express. Hence, 10 people must be reading the ToI and IE and 20 people must be reading IE and Hindu. So we have, the following venn diagram.

The answer is 80.
Question 18
3 / -1

Directions For Questions

Read the following information carefully and answer the questions which follow.

In a society consisting of 200 people, each person reads at least one newspaper among ‘Hindu’, ‘Indian Express’ and ‘Times of India’. It is known that 130 people read ‘Times of India’. The number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’. 100 people read ‘Hindu’. Number of people reading only ‘Indian Express’ and ‘Times of India’ is half of the number of people reading only ‘Hindu and Indian Express. The number of people reading at least 2 newspapers is 50 more than then the number of people who read at least 3 newspapers. 60 people read Indian Express.

...view full instructions

How many people read exactly two newspapers?

A
50

B
504

C
507

D
509

Solution

We have been given that the number of people reading at least two newspapers is 50 more than the number of people reading at least three newspapers.
Let ‘a’ be the people who read only one newspaper, ‘b’ be the people who read exactly two newspapers and ‘c’ be the people who read exactly three newspapers.
We know that a + b + c = 200
a + 2b + 3c = 130 + 100 + 60 = 290
Subtracting the two equations, we get
b + 2c = 90
We have been given that
(b + c) = 50 + c
=> b = 50
Hence, there are exactly 50 people who read two newspapers. Thus, from equation 1 and 2, we can figure out that a = 130 and c = 20.
Hence, 20 people read all three newspapers. From this we can also figure out that only 10 people read ‘only Indian Express’(number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’). We have also been given that Number of people reading only ‘Indian Express’ and ‘Times of India’ is twice the number of people reading only ‘Hindu and Indian Express. Hence, 10 people must be reading the ToI and IE and 20 people must be reading IE and Hindu. So we have, the following venn diagram.

The answer is 50.
Question 19
3 / -1

Directions For Questions

Read the following information carefully and answer the questions which follow.

In a society consisting of 200 people, each person reads at least one newspaper among ‘Hindu’, ‘Indian Express’ and ‘Times of India’. It is known that 130 people read ‘Times of India’. The number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’. 100 people read ‘Hindu’. Number of people reading only ‘Indian Express’ and ‘Times of India’ is half of the number of people reading only ‘Hindu and Indian Express. The number of people reading at least 2 newspapers is 50 more than then the number of people who read at least 3 newspapers. 60 people read Indian Express.

...view full instructions

What is the difference between the number of people who read only Hindu and Indian express and the number of people who read only Hindu and Times of India?

A
0

B
5

C
10

D
15

Solution

We have been given that the number of people reading at least two newspapers is 50 more than the number of people reading at least three newspapers.
Let ‘a’ be the people who read only one newspaper, ‘b’ be the people who read exactly two newspapers and ‘c’ be the people who read exactly three newspapers.
We know that a + b + c = 200
a + 2b + 3c = 130 + 100 + 60 = 290
Subtracting the two equations, we get
b + 2c = 90
We have been given that
(b + c) = 50 + c
=> b = 50
Hence, there are exactly 50 people who read two newspapers. Thus, from equation 1 and 2, we can figure out that a = 130 and c = 20.
Hence, 20 people read all three newspapers. From this we can also figure out that only 10 people read ‘only Indian Express’(number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’). We have also been given that Number of people reading only ‘Indian Express’ and ‘Times of India’ is twice the number of people reading only ‘Hindu and Indian Express. Hence, 10 people must be reading the ToI and IE and 20 people must be reading IE and Hindu. So we have, the following venn diagram.
Question 20
3 / -1

Directions For Questions

Read the following information carefully and answer the questions which follow.

In a society consisting of 200 people, each person reads at least one newspaper among ‘Hindu’, ‘Indian Express’ and ‘Times of India’. It is known that 130 people read ‘Times of India’. The number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’. 100 people read ‘Hindu’. Number of people reading only ‘Indian Express’ and ‘Times of India’ is half of the number of people reading only ‘Hindu and Indian Express. The number of people reading at least 2 newspapers is 50 more than then the number of people who read at least 3 newspapers. 60 people read Indian Express.

...view full instructions

What is the number of people who read at most 2 newspapers?

A
160

B
180

C
190

D
185

Solution

We have been given that the number of people reading at least two newspapers is 50 more than the number of people reading at least three newspapers.
Let ‘a’ be the people who read only one newspaper, ‘b’ be the people who read exactly two newspapers and ‘c’ be the people who read exactly three newspapers.
We know that a + b + c = 200
a + 2b + 3c = 130 + 100 + 60 = 290
Subtracting the two equations, we get
b + 2c = 90
We have been given that
(b + c) = 50 + c
=> b = 50
Hence, there are exactly 50 people who read two newspapers. Thus, from equation 1 and 2, we can figure out that a = 130 and c = 20.
Hence, 20 people read all three newspapers. From this we can also figure out that only 10 people read ‘only Indian Express’(number of people reading all three newspapers is twice the number of people who read only ‘Indian Express’). We have also been given that Number of people reading only ‘Indian Express’ and ‘Times of India’ is twice the number of people reading only ‘Hindu and Indian Express. Hence, 10 people must be reading the ToI and IE and 20 people must be reading IE and Hindu. So we have, the following venn diagram.