Logical Reasoning & DI (LRDI) Test

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Logical Reasoning & DI (LRDI) Test - 17

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Question 1
3 / -1

Directions For Questions

Read the following scenario and answer the three questions that follow.

The following plot describes the height (in cm), weight (in kg), age (in years) and gender (F for female, M for male) of 20 patients visiting a hospital.

A person’s body mass index (BMI) is calculated as weight (in kg) divided by squared height (measured in square metres). For example, a person weighing 100 kg and of height 100 cm (1m) will have a BMI of 100. A person with BMI less than or equal to 18.5 is considered as underweight, above 18.5 but less than or equal to 25 as normal weight, above 25 but less than or equal to 30 as overweight, and above 30 as obese.

...view full instructions

The average age of the female patients who weigh 50 kg or above is approximately

A
62

B
65

C
68

D
70

Solution

There are 5 ladies whose weights are 50 or above

There ages are 50,50, 70,60 and 80

Average = 310/5 = 62
Question 2
3 / -1

Directions For Questions

The following table represents the type(s) of vehicle(s) owned by people of 5 cities.

So, in Hyderabad, there are a total of 897 people, some of whom might not own any type of vehicle. 61 people own a private jet, 131 people own a 4-wheeler, 707 people own a bike and x people own a scooter. Similarly, the other cities follow. Also, no person owns more than one vehicle of a particular type.

Based on the information given above, answer the questions that follow.

...view full instructions

What is the absolute difference between the highest possible value and the lowest possible value of (x+y+z+p+q+r+s)? All people have at least one vehicle. All the unknown variables are necessarily natural numbers.

A
6087

B
6088

C
6082

D
6081

Solution

For the highest possible value, the individual values must be equal to their maximum possible values.

x = 897 [number of people in the city]

y = 986 [number of people in the city]

z = 1034 [number of people in the city]

p = q = 564 [number of people in the city]

r = s = 1067 [number of people in the city]

x + y + z + p + q + r + s = 6179.

For the lowest possible value, the individual values must be equal to their minimum possible values.

x = 1 [total number of vehicles already exceeds the total number of people]

y = 1 [total number of vehicles already exceeds the total number of people]

z = 1 [total number of vehicles already exceeds the total number of people]

p and q are interdependent. p + q = 87 [If p+q = 87, only then can at least one person own one vehicle, that is, the number of vehicles = number of people]

r and s are interdependent. r + s = 1 + 1 = 2 [total number of vehicles already exceeds the total number of people]

Hence, x + y + z + p + q + r + s = 1 + 1 + 1 + 87 + 2 = 92

Difference = 6179 - 92 = 6087.
Question 3
3 / -1

Directions For Questions

The following table represents the type(s) of vehicle(s) owned by people of 5 cities.

So, in Hyderabad, there are a total of 897 people, some of whom might not own any type of vehicle. 61 people own a private jet, 131 people own a 4-wheeler, 707 people own a bike and x people own a scooter. Similarly, the other cities follow. Also, no person owns more than one vehicle of a particular type.

Based on the information given above, answer the questions that follow.

...view full instructions

If the total number of bikes in all 5 cities combined is 2816, what is the maximum possible number of people in Chennai who own at least 3 vehicles? It is known that all people in Chennai own at least one vehicle.

A
388

B
387

C
386

D
385

Solution

Bike owners in Chennai = 2816 – 707 – 971 – 432 – 342 = 364.

To own at least 3 vehicles, one can own either 3 or 4 vehicles.

I + II + III + IV = 1034

I + 2 II + 3 III + 4 IV = 1987

The difference has to be adjusted among people owning 2, 3 and 4 vehicles. To maximise the sum of people owning 3 and 4 vehicles, we will try to allocate the maximum possible to 3 and the remaining to 4.

1987 – 1034 = 953

2III + 3IV = 953.

III = 475

IV = 1

But, if we observe the values for Chennai, the number of people having a bike is 364 and the number of people having a private jet is 24. Hence, even if we consider that people who own a bike also own a 4-wheeler and a scooter(but not a private jet) and people who own a private jet also own a 4-wheeler and a scooter(but not a bike), we won’t be able to reach the above numbers. We would be able to achieve a maximum value of 24 + 364 = 388.

Let us verify if we can represent the above condition in a 4-set Venn Diagram.

Now, we need to arrange the remaining people who own a 4-wheeler and those who own a scooter.

I + II + III + IV = 1034

IV = 0, because we have already assigned all people who own a Private jet and a bike into III.

III = 388.

I + II = 1034 – 388 = 646

I + 2II + 3III + 4IV = 1987

I + 2II + 3 X 388 = 1987

I + 2II = 823

II = 823 – 646 = 177

I = 469

Hence, we get the following Venn Diagram:

Hence, maximum people who own 3 vehicles = 388.
Question 4
3 / -1

Directions For Questions

The following table represents the type(s) of vehicle(s) owned by people of 5 cities.

So, in Hyderabad, there are a total of 897 people, some of whom might not own any type of vehicle. 61 people own a private jet, 131 people own a 4-wheeler, 707 people own a bike and x people own a scooter. Similarly, the other cities follow. Also, no person owns more than one vehicle of a particular type.

Based on the information given above, answer the questions that follow.

...view full instructions

In Bengaluru, the number of people who own zero vehicles is zero, the number of people who own 2 vehicles is 163, the number of people who own 3 vehicles is 36 and the number of people who own all 4 vehicles is more than the number of people who own 3 vehicles, what is the maximum value that y can take?

A
127

B
96

C
72

D
120

Solution

I + II + III + IV = 986

I + 2 II + 3 III + 4 IV = 1265 + y

Subtracting the first from the second,

II + 2 III + 3 IV = 279 + y

163 + 72 + 3 IV = 279 + y

y = 3 IV - 44

Now, IV > III, so , IV > 36

But IV <= 57

For maximum y, we have to put maximum IV,

y = 3 x 57 - 44 = 171 - 44 = 127
Question 5
3 / -1

Directions For Questions

The following table represents the type(s) of vehicle(s) owned by people of 5 cities.

So, in Hyderabad, there are a total of 897 people, some of whom might not own any type of vehicle. 61 people own a private jet, 131 people own a 4-wheeler, 707 people own a bike and x people own a scooter. Similarly, the other cities follow. Also, no person owns more than one vehicle of a particular type.

Based on the information given above, answer the questions that follow.

...view full instructions

If it is given that all unknowns are equal to 150, what is the maximum number of people in all 5 cities combined who owns exactly 4 vehicles? Also, every person in all of the 5 cities owns at least one vehicle.

A
337

B
327

C
336

D
326

Solution

In the following table, I represents people who own only one vehicle, II represents people who own two vehicles, III represents people who own three vehicles and IV represents people who own four vehicles.

We have to calculate the additional value for every city.

Then we try to allocate the maximum to IV for each city. If for a city, this value is more than any particular vehicle value, we take that value.

Hence sum = 326
Question 6
3 / -1

Directions For Questions

The following table represents the type(s) of vehicle(s) owned by people of 5 cities.

So, in Hyderabad, there are a total of 897 people, some of whom might not own any type of vehicle. 61 people own a private jet, 131 people own a 4-wheeler, 707 people own a bike and x people own a scooter. Similarly, the other cities follow. Also, no person owns more than one vehicle of a particular type.

Based on the information given above, answer the questions that follow.

...view full instructions

What is the difference between number of people owning vehicle in hyderabad and number of people owning vehicle in bengaluru?

A
1503

B
1504

C
1505

D
1506

Solution

Thus, in Hyderabad, the excess value is 152. We will try to allot maximum to IV, and automatically we will get the maximum I value.

152 = 3 x 50 + 2 x 1

Hence, 50 people own 4 vehicles and 1 person owns 3 vehicles.

Number of people left with 1 vehicle = 897 - 51 = 846

In Bengaluru, the excess value is 429.

But a maximum of 57 people can own all 4 vehicles. We will try to allocate the rest among III.

429 = 3 X 57 + 2 X 129

But 129 people cannot own 3 vehicles, because people owning a scooter is 150, and 57 + 129 exceeds this value.

Hence, the maximum number of people who can own 3 vehicles = 150 - 57 = 93.

Hence we are left with... 429 - 3 x 57 - 2 x 93 = 72

Hence, 57 people own 4 vehicles and 93 people own 3 vehicles, 72 people own 2 vehicles.

Number of people left with 1 vehicle =986 - 57 - 93 - 72 = 764.

Hence, difference = (846 + 764) - (50 + 57)

1503 is the right answer.
Question 7
3 / -1

Directions For Questions

Directions: Answer the question on the basis of the information given below.

There is an intense competition for getting into Indian team for two slots of openers. BCCI Selection Committee decides to closely monitor Dileep Trophy matches for the purpose. To keep the performance in proper perspective, it is, however, decided to award the players grades instead of recording the runs scored directly. Formula for grades is as under:

Performance of three of the openers P, Q and R (under consideration for selection) in the four matches in which they participated is as under:

(i) Every player scored at least one century, and at least one century was scored in every match (match I, match II, etc.).

(ii) In two of the matches, Q scored 0 and 30 runs. No other scores of Q or any other players were less than 40.

(iii) In each of the four matches, the grades obtained by the three openers were all different. However, it was only in match I and match III that grades not awarded to any of the three openers were identical.

(iv) R secured the same grade in both match II and match IV.

(v) P in match IV received the same grade as Q in his first match and R in his third match. None of them secured that grade in match II.

(vi) In one of the matches, P obtained the same grade as in match III. However, the grades of Q and R in these two matches were different. Only in this particular match (other than match III), was a half century scored and a player got F grade simultaneously.

Points for grades A, B, C and F are 4, 3, 1 and 0, respectively, and top 2 batsmen out of 3 are to be selected on the basis of points in the four matches (those selected should have more points than the third player for selection based on points).

...view full instructions

At least how many runs were scored by Q in match III? Key in the value.

A
100

B
101

C
105

D
50

Solution

From the given information, we can make the following empty table:

From (ii) and (iii), we get that Q got F grade in match II and match IV.

From (v) and (vi), P got same grade in match II and match III. Now, P could obtain grade B in match II and match III (from (vi)).

Now, in every match, at least one century was scored; thus, R obtained grade A in match II and match IV (from (iv)).

Thus, grade C would be obtained by Q in match I, R in match III and P in match IV (from (iii) and (v)).

Now, remaining rows and columns can be filled giving the final table as follows:
Question 8
3 / -1

Directions For Questions

The Table gives the data for the Currency exchange rates and Stock market Indexes. Anyperson in any country can invest in any market or currency. For investing in a country one has to use homecurrency of that country. One can either invest or withdraw on 1st of each month only.

Note: The closing price of currency and Index of a month is same as opening price of the first day of thenext month

...view full instructions

If an Indian has invested Rs.93,000 in UK Stock Market in January 2019 then in which month his/her portfolio has declined by maximum percentage in rupee terms?

A
April 2019

B
May 2019

C
June 2019

D
July 2019

Solution

From the table, we can see that the % decline in the rupee was maximum in the month of July among the options and also the stock index of UK was lowest in July among the given months so the maximum decline in the portfolio was in July.
Question 9
3 / -1

Directions For Questions

Directions: Answer the question on the basis of the information given below.

There is an intense competition for getting into Indian team for two slots of openers. BCCI Selection Committee decides to closely monitor Dileep Trophy matches for the purpose. To keep the performance in proper perspective, it is, however, decided to award the players grades instead of recording the runs scored directly. Formula for grades is as under:

Performance of three of the openers P, Q and R (under consideration for selection) in the four matches in which they participated is as under:

(i) Every player scored at least one century, and at least one century was scored in every match (match I, match II, etc.).

(ii) In two of the matches, Q scored 0 and 30 runs. No other scores of Q or any other players were less than 40.

(iii) In each of the four matches, the grades obtained by the three openers were all different. However, it was only in match I and match III that grades not awarded to any of the three openers were identical.

(iv) R secured the same grade in both match II and match IV.

(v) P in match IV received the same grade as Q in his first match and R in his third match. None of them secured that grade in match II.

(vi) In one of the matches, P obtained the same grade as in match III. However, the grades of Q and R in these two matches were different. Only in this particular match (other than match III), was a half century scored and a player got F grade simultaneously.

Points for grades A, B, C and F are 4, 3, 1 and 0, respectively, and top 2 batsmen out of 3 are to be selected on the basis of points in the four matches (those selected should have more points than the third player for selection based on points).

...view full instructions

Consider following statements:

Statement I: The average of runs scored by P in a match is at least 58.
Statement II: R and P are the top performing batsmen.
Statement III: The cumulative score of the three batsmen is the least in match IV.

What is the average of maximum runs scored by Q in match I and match II? Key in the value upto 2 decimal places.

A
39.50

B
40.50

C
25.50

D
20.50

Solution

From the given information, we can make the following empty table:

From (ii) and (iii), we get that Q got F grade in match II and match IV.

From (v) and (vi), P got same grade in match II and match III. Now, P could obtain grade B in match II and match III (from (vi)).

Now, in every match, at least one century was scored; thus, R obtained grade A in match II and match IV (from (iv)).

Thus, grade C would be obtained by Q in match I, R in match III and P in match IV (from (iii) and (v)).

Now, remaining rows and columns can be filled giving the final table as follows:

Maximum runs scored by Q in match I = 49

Maximum runs scored by Q in match II = 30

Average of maximum runs scored by Q in match I and match II = (49+30)/2 = 39.5
Question 10
3 / -1

Directions For Questions

The Table gives the data for the Currency exchange rates and Stock market Indexes. Anyperson in any country can invest in any market or currency. For investing in a country one has to use homecurrency of that country. One can either invest or withdraw on 1st of each month only.

Note: The closing price of currency and Index of a month is same as opening price of the first day of thenext month

...view full instructions

If an Indian has invested Rs. 100,000 in 1st January 2019 till 1st January 2020, then whichoption is best for her?

A
Depositing in an Indian bank at 9% per annum

B
Investment in Indian Stock Market

C
Investment in USA Stock Market

D
Investment in UK Stock Market

Solution

The percentage increase in the USA market index is the maximum among the three markets in a year.