Statistics Test

Result

Statistics Test - 11

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Weekly Quiz Competition

Question 1

1 / -0

The percentage of marks obtained by 100 students in an examination are as follows:

Marks	30-35	35-40	40-45	45-50	50-55	55-60	60-65
Frequency	10	15	18	22	23	8	4

The median class is

60 - 65

40 – 45

45 – 50

50 – 55

Solution

Marks	30-35	35-40	40-45	45-50	50-55	55-60	60-65
Frequency	10	15	18	22	23	8	4
Cumulative Frequency	10	25	43	65	88	96	100

Here N = 100
⇒ N/2 = 50
therefore, median class is 45 – 50.

Question 2

1 / -0

The percentage of marks obtained by 100 students in an examination are as follows:

Marks	130-135	135-140	140-145	145-150	150-155	155-160	160-165
Frequency	10	15	18	22	23	8	4

The cumulative frequency of the class interval 150 – 155 is

88

90

80

100 Solution

Marks	130-135	135-140	140-145	145-150	150-155	155-160	160-165
Frequency	10	15	18	22	23	8	4
Cumulative Frequency	10	25	43	65	88	96	100

Therefore, cumulative frequency of the class interval 150 – 155 is 88.

Question 3
1 / -0

Construction of cumulative frequency table is useful to determine

A
median

B
mode

C
all the three

D
mean

Solution

A cumulative frequency distribution is the sum of the class and all classes below it in a frequency distribution. Construction of cumulative frequency table is useful to determine Median.
Question 4
1 / -0

For the following distribution

Class 60 – 70 70 – 80 80 – 90 90 – 100 100 – 110

Frequency 10 15 12 20 9

the sum of lower limits of the median class and modal class is

A
170

B
190

C
180

D
20

Solution

Class 60 – 70 70 – 80 80 – 90 90 – 100 100 – 110

Frequency 10 15 12 20 9

Cumulative Frequency 10 25 37 57 66

Here N = 66
⇒ N/2 = 33 ∴ The median class is 80 – 90 and Modal class is 90 – 100
Sum of lower limits of Median class and Modal class = 80 + 90 = 170
Question 5
1 / -0

For the following distribution

Class 60-70 70-80 80-90 90-100 100-110

Frequency 13 10 15 8 11

the upper limit of the median class is

A
80

B
110

C
100

D
90

Solution

Class 60-70 70-80 80-90 90-100 100-110

Frequency 13 10 15 8 11

Cumulative Frequency 13 23 38 46 57

Here N = 57
⇒ N/2 = 28.5
∴ Median class is 80 – 90
The upper limit of the median class is 90.

Question 6

1 / -0

Consider the data

Class	65-85	85-105	105-125	125-145	145-165	165-185	185-205
Frequency	4	5	18	20	17	7	4

The difference of the upper limit of the median class and the lower limit of the modal class is

17

18

0

20 Solution

Class	65-85	85-105	105-125	125-145	145-165	165-185	185-205
Frequency	4	5	18	20	17	7	4
Cumulative Frequency	4	9	27	47	64	71	75

Here N = 75
⇒ N/2 = 37.5
∴∴ The median class is 125 – 145 and Modal class is 125 – 145
The difference of upper limits of Median class and lower limit of Modal class = 145 – 125 = 20

Question 7
1 / -0

The middle most value of the data is

A
mean

B
median

C
mode

D
none of these

Solution

The median of a set of data values is the middle most value when the data has been arranged in ascending order i.e. from smallest value to the largest value.

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Re-Attempt Weekly Quiz Competition

Class	60 – 70	70 – 80	80 – 90	90 – 100	100 – 110
Frequency	10	15	12	20	9

Class	60-70	70-80	80-90	90-100	100-110
Frequency	13	10	15	8	11
Cumulative Frequency	13	23	38	46	57

Statistics Test - 11

Result

Statistics Test - 11

Score

-

Rank

-

SHARING IS CARING

Question 1

60 - 65

40 – 45

45 – 50

50 – 55

Solution

Question 2

88

90

80

100

Solution

Question 3

median

mode

all the three

mean

Solution

Question 4

170

190

180

20

Solution

Question 5

80

110

100

90

Solution

Question 6

17

18

0

20

Solution

Question 7

mean

median

mode

none of these

Solution

User

Question Analysis

My Perfomance

Score

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Rank

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