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Statistics Test - 55

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Statistics Test - 55
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  • Question 1
    1 / -0
    Which of the following has the same mean and mode?
    Solution
    (a) The given data is, $$6,2,5,4,3,4,1$$
    $$\Rightarrow\ Mean=\dfrac{1+2+3+4+4+5+6}{7}$$
    $$=\dfrac{25}{7}$$
    $$=3.57$$

    $$Mode = 4$$    because it occurs two times.
    Therefore, mean is not equal to mode.

    (b) The given data is, $$4,2,2,1,3,2,3$$
    $$\Rightarrow    Mean=\dfrac{1+2+2+2+3+3+4}{7}$$
    $$=\dfrac{17}{7}$$
    $$=2.42$$
    $$Mode = 2$$     because it occurs two times 
    Therefore, mean is not equal to mode.

    (c) The given data is,, $$2,3,7,3,8,3,2$$
    $$\Rightarrow\ Mean=\dfrac{2+2+3+3+7+8}{7}$$
    $$=\dfrac{28}{7}$$
    $$=4$$
    $$Mode = 3$$because it occurs three times 
    Therefore, mean is not equal to mode
     
    (d) The given data is,, 4,3,4,3,4,6,4
    $$\Rightarrow, Mean=\dfrac{3+3+4+4+4+4+6}{7}$$
    $$= \dfrac{28}{7}$$
    $$=4$$
    $$Mode = 4$$ because it occurs 4 times.
    Therefore, mean is equal to mode.
     
    Hence, the correct option is (D).
  • Question 2
    1 / -0
    The number of trees in different parks of a city is $$ 33,38,48,33,34,34,33$$ and $$ 24$$. The mode of this data is
    Solution
    The given data in ascending order is $$24,33,33,33,34,34,38$$  and  $$48$$,
    The mode of data is $$33$$ because the frequent of occurrence of $$33$$ is highest.
  • Question 3
    1 / -0
    The choices of the fruits of 42 students in a class are as follows:
    A, O, B, M, A, G, B, G, A, G, B, M. A, O, M, A, B, G, M, B, A, O, M, O, G, B, O, M, G, A, A, B, M, O, M, G, B, A, M, O, M, O,
    where A, B, G, M, and O stands for Apple, Banana, Grapes, Mango and Orange respectively.
    which fruit is liked
    by most of the students?
    Solution
    The number of $$A$$ appearing in the list is $$9$$

    The number of $$B$$ appearing in the list is $$8$$

    The number of $$G$$ appearing in the list is $$7$$

    The number of $$M$$ appearing in the list are $$10$$

    The number of $$O$$ appearing in the list are $$8$$

    So, $$M$$ appeared the most, and $$M$$ stands for Mango.

    So, Mango $$M$$ is the fruit that is liked by most of the students.
  • Question 4
    1 / -0
    The median of the data : $$ 3,4,5,6,7,3,4$$ is  
    Solution
    Rearranging the given data into ascending order, we get 
    $$3,3,4,4,5,6,7,$$
    Total number of observations $$=7$$ which is odd
    Hence, the $$4^{th}$$ term is the median.
    $$\therefore$$ Median $$=4$$

    Hence, option (C) is the correct answer.
  • Question 5
    1 / -0
    For the following distribution:
    MarksNumber of students
    Below $$10$$$$3$$
    Below $$20$$$$12$$
    Below $$30$$$$27$$
    Below $$40$$$$57$$
    Below $$50$$$$75$$
    Below $$60$$$$80$$
    The modal class is
    Solution
    MarksNumber of students              Cumulative Frequency
    Below $$10$$             $$3$$ $$3$$
    $$10-20$$$$12-3=9$$$$12$$
    $$20-30$$$$27-12=15$$$$27$$
    $$30-40$$$$57-27=30$$$$57$$
    $$40-50$$$$75-57=18$$$$75$$
    $$50-60$$$$80-75=5$$$$80$$

    Here, we see that the highest frequency is $$30,$$ which lies in the interval $$30-40$$, and the class with the highest frequency is known as modal class.
    Hence, option $$C$$ is correct.
  • Question 6
    1 / -0
    What is the mode of $$19, 19, 15, 20, 25, 15, 20, 15$$?
    Solution
    Since observation $$15$$ is occuring the most in the data
    $$19,19,15,20,25,15,20,15$$
    19,19,15,20,25,15,20,15

    So, the mode of the given data is $$15$$
    .
    Hence, the correct alternative answer is (A).
  • Question 7
    1 / -0
    The class whose cumulative frequency is greater than (and nearest to) $$ \dfrac{N}{2} $$, is called
    Solution
    The class whose cumulative frequency is greater than (and nearest to) $$ \dfrac{N}{2} $$, is called Median class
  • Question 8
    1 / -0
    Number of students in a school according to their age are as follows :
    Age (in yrs.)No. of students
    815
    925
    1040
    1136
    1241
    1337
    1420
    1513
    165
    173
    Their mode is
    Solution
    From above table it is clear that frequency 41 is maximum and its mavimum and its corresponding age group of 12 . So its mode will be 12.
    Thus (B) is correct.
  • Question 9
    1 / -0
    The mode of the data$$4, 3, 4, 5, 4, 2, 4, 1$$ will be :
    Solution
    Arranging the numbers with the same values together, we get
    $$1,2,3,4,4,4,4,5$$
    Mode of this data is $$4$$ because it occurs more frequently than other observations.
  • Question 10
    1 / -0
    Read the following news report and answer on the basis of the same: For an examination, 60 students of a school appeared. Marks obtained by the 12 students were 25 each. The number of students who scored 20 and 5 each was three more than the students who scored 25. Also, 8 students who scored 10 marks each. The students who scored 15 marks each were half the students who scored 10 each and remaining students had scored 30 each. Answer the following question:
    The series so obtained from the given paragraph is:
    Solution

     Marks

    Number of students 

    15 = 12 + 3

    10 

    15 

    20 

    15 = 12 + 3

    25 

    12 

    30 

    Total 

    60 

    Hence, correct answer is option B.
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