Self Studies

Probability Test - 11

Result Self Studies

Probability Test - 11
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    A lot consists of 40 mobile phones of which 32 are good, 3 have only minor defects and 5 have major defects. Ram will buy a phone if it is good or have minor defects. One phone is selected at random. The probability that it is acceptable to Ram is___.

    Solution

    Number of phones which are good and minor defects = 32 + 3 = 35
    Number of possible outcomes = 35
    Number of Total outcomes = 40
    ∴ Required Probability = 35/40 = 7/8

  • Question 2
    1 / -0

    1000 tickets of a lottery were sold and there are 5 prizes on these tickets. If Ramesh has purchased one lottery ticket, the probability of winning a prize is

    Solution

    Number of possible outcomes = 5
    Number of total outcomes = 1000
    ∴ Required Probability = 5/1000 = 1/200

  • Question 3
    1 / -0

    A bag contains 6 red, 8 white, 4 green and 7 black balls. One ball is drawn at random. The probability that the ball drawn is neither green nor white is

    Solution

    Total number of balls = 25
    Number of Green and White balls = 4 +8 = 12
    Number of balls neither green nor white = 25 - 12 =13
    Number of possible outcomes = 13
    Number of total outcomes = 25
    ∴ Required Probability = 13/25

  • Question 4
    1 / -0

    Cards marked with numbers 2 to 101 are placed in a box and mixed thoroughly. One card is drawn from the box. The probability that the number on the card is a prime number less than 20 is

    Solution

    Prime numbers less than 20 are 2, 3, 5, 7, 11, 13, 17, 19 = 8
    Number of possible outcomes = 8
    Number of total outcomes = 100
    ∴ Required Probability = 8/100 = 2/25

  • Question 5
    1 / -0

    The king, queen and jack of clubs are removed from a deck of 52 cards and the remaining cards are shuffled. A card is drawn from the remaining cards. The probability of getting a king is

    Solution

    K , Q , J  of clubs i.e  3 cards are removed , therefore remaining cards = 52 - 3 = 49
    3 kings are left in the pack
    Number of possible outcomes = 3
    Number of total outcomes = 52 – 3 = 49
    ∴ Required Probability = 3/49

  • Question 6
    1 / -0

    Raju bought a fish from a shop for his aquarium. The shop keeper takes out one fish from a tank containing 15 male fish and 18 female fish. The probability that the fish taken out is a male fish is

    Solution

    Total number of fish = 15 + 18 = 33
    Male fish = 15
    Number of possible outcomes = 15
    Number of total outcomes = 15 + 18 = 33
    Required Probability = 15/33 = 5/11

  • Question 7
    1 / -0

    A die is thrown twice. The probability that 5 will come up at least once is

    Solution

    Elementary events are
    (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) 
    (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) 
    (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
    (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
    (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
    (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
    ∴ Number of Total outcomes = 36
    And Number of possible outcomes = 11
    ∴ Required Probability = 11/36

  • Question 8
    1 / -0

    Two dice are thrown simultaneously. The probability that the sum of the numbers appearing on the dice is 1 is

    Solution

    Elementary events are
    (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
    (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
    (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
    (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
    (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
    (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
    ∴ Number of Total outcomes = 36
    And Number of possible outcomes (sum of numbers appearing on die is 1) = 0
    ∴ Required Probability = 0/36 = 0

  • Question 9
    1 / -0

    Two dice are thrown simultaneously. The probability that the product of the numbers appearing on the dice is 7 is

    Solution

    Elementary events are
    (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
    (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
    (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
    (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
    (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
    (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
    ∴ Number of Total outcomes = 36
    And Number of possible outcomes (product of numbers appearing on die is 7) = 0
    ∴ Required Probability = 0/36 = 0

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now