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Pair of Linear Equations in Two Variables Test - 56

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Pair of Linear Equations in Two Variables Test - 56
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  • Question 1
    1 / -0
    The graph of the equations $$x + y = 5$$ and $$x -y = 1$$ will be.....
    Solution
    Take few points on bothe lines and draw the graphs of both lines.

    For $$x + y = 5$$:
    035
    520
    For $$x - y = 1$$:
    013
    -102
    From the graphs,  we can say that the lines are intesecting at $$(3,2)$$.

  • Question 2
    1 / -0
    Solve the following pairs of equations.
    $$y=2x+1$$; $$y+3x-6=0$$
    Solution
    Here given equations are $$y-2x= 1$$  ;  $$y+3x=6$$ 
     Subtract both the equations, we will get $$x=1$$.
    On substituting the value of $$x$$ in any given equations we get $$y=3$$
  • Question 3
    1 / -0
    Solve the following pairs of equations.
    $$2x-4=0$$; $$4x+y+4=0$$
    Solution
    $$2x-4= 0 \implies x=2$$

    and
    $$4x+y =-4$$
    $$4(2)+y=-4$$
    $$8+y =-4$$
    $$y =-12$$

    $$\Rightarrow x=2, y = -12 $$
  • Question 4
    1 / -0
    Solve the following equations by substitution method.
    $$\dfrac{1}{x} + \dfrac{2}{y} = 9; \dfrac{2}{x} + \dfrac{1}{y} = 12     (x \neq 0, y \neq 0)$$
    Solution

    Given equations,

    $$\dfrac{1}{x} + \dfrac{2}{y} = 9$$..............(1)
    $$\dfrac{2}{x} + \dfrac{1}{y} = 12$$..............(2)
    $$\dfrac{1}{x}=9-\dfrac{2}{y}$$.........from (1)
    putting value of $$\dfrac {1}{x}$$ in (2), we get
    $$2\left[9-\dfrac{2}{y}\right]+\dfrac{1}{y}=12$$
    $$18-\dfrac{3}{y}=12$$
    $$6=\dfrac{3}{y}$$......$$\boxed{y=\dfrac{1}{2}}$$
    putting value of $$y$$ in (1), we get
    $$\dfrac {1}{x}=9-4$$
    $$\dfrac{1}{x}=5$$......$$\boxed{x=\dfrac{1}{5}}$$
  • Question 5
    1 / -0
    Solve the following equations by substitution method.
    $$\dfrac{3}{x} + \dfrac{1}{y} = 7; \dfrac{5}{x} - \dfrac{4}{y} = 6. (x \neq 0, y \neq 0)$$
    Solution
    Given equations are,
    $$\dfrac{3}{x}+\dfrac{1}{y}=7$$
    $$\dfrac{5}{x}-\dfrac{4}{y}=6$$
    $$\dfrac{1}{x}=\dfrac{1}{3}\left(7-\dfrac{1}{y}\right)$$.................from (1)
    Putting value of $$\dfrac {1}{x}$$ in (1), we get
    $$5\left[\dfrac{1}{3}(7-\dfrac{1}{y})\right]-\dfrac{4}{y}=6$$
    $$\dfrac{35}{3}-\dfrac{5}{3y}-\dfrac{4}{y}=6$$
    $$\dfrac{17}{3}=\dfrac{5+12}{3y}$$
    $$\boxed {y=1}$$
    Putting value of $$y$$ in (1)
    $$\dfrac{1}{x}=\dfrac{1}{3}\times 6\Rightarrow \dfrac {1}{x}=2=\boxed{x=\dfrac{1}{2}}$$
  • Question 6
    1 / -0
    Solve following system of equations by elimination method.  $$x +2y=7, x-2y=1$$
    Solution
    Given equations are
    $$x+2y=7$$.......(i)

    $$x-2y=1$$.........(ii)

    Subtract equation (ii) from (i), we get
    $$2x=8$$
    $$\Rightarrow x=4$$
    put value of $$x$$ in equation (ii)
    $$4-1=2y$$
    $$3=2y$$
    $$\therefore y=\dfrac{3}{2}$$
    $$\therefore x=4 , \ y=\dfrac{3}{2}$$
  • Question 7
    1 / -0
    Solve each of the following system of equations by substitution method. 
    $$13x +11y=70, 11x+13y=74$$
    Solution
    Since, $$13x+11y=70$$...eq1          $$11x+13y=74$$......eq2
    $$x=\dfrac{70-11y}{13}$$, put this value in eq2, we get
    $$11\left[\dfrac{70-11y}{13}\right]+13y=74$$
    $$770-121y+169y=74\times 13$$
    $$\Rightarrow y=4$$ 

    and
    $$x=\dfrac{70-11(4)}{13}$$
    $$x=2$$
  • Question 8
    1 / -0
    Solve the following equations by substitution method.
    $$x + 3y = 10; 2x + y = 5$$
    Solution
    $$x+3y=10$$ .....$$(1)$$ ; 
    $$2x+y=5$$........$$(2)$$ 


    $$y=5-2x$$......from $$(2)$$

    putting in $$(1)$$, we get  

    $$\Rightarrow x+3(5-2x)=10$$

     $$\Rightarrow x+15-6x=10$$

     $$\Rightarrow -5x=-5$$

     $$\Rightarrow x=1$$ 

    $$1+3y=10$$ 
    $$y=3$$
  • Question 9
    1 / -0
    Solve the following equations by substitution method.
    $$5x + 3y = 21; 2x - y = 4$$
    Solution
    $$5x+3y=21$$.........(1)  

    $$2x-y=4$$...............(2)
    $$y=2x-4$$

    $$5x+3(2x-4)=21$$.........putting value of $$y$$ in (1)
    $$\Rightarrow 5x+6x-12=21$$
    $$\Rightarrow 11x=33$$.......................$$\boxed{x=3}$$
    Putting value of $$x$$ in (2)
    $$6-y=4$$..........................$$\boxed{y=2}$$
  • Question 10
    1 / -0
    Solve the following equations by substitution method.
    $$2x + y = 1; 3x - 4y = 18$$
    Solution

    $$2x+y=1$$...........(1) 

    $$3x-4y=18$$........(2) 

    $$y=1-2x$$...........from (1) 

    putting value of $$y$$ in (1)

    $$\Rightarrow 3x-4(1-2x)=18$$

    $$\Rightarrow 3x-4+8x=18$$ 

    $$\Rightarrow 11x=22$$       
           
    $$\Rightarrow x=2$$   
     
    Using value of $$x$$
                    
    $$\Rightarrow 4+y=1$$

    $$\Rightarrow y=-3$$
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