Quadratic Equat...

If $$x^{2}-5x+1=0$$, then $$x^{5}+\dfrac {1}{x^{5}}$$ is equal to

If the equation $$(a^2+b^2)x^2-2(ac+bd)x+c^2+d^2=0$$ has equal roots, then 

If the discriminant of quadratic equation $${ b }^{ 2 }-4ac=0$$, then the roots are: 

If $$\dfrac{\sqrt{1296}}{x}=\dfrac{x}{2.25}$$ then value $$x$$ is:

Find the value of $$x:$$
$$x^2-4x+4=0$$

If an angle A of a $$\triangle ABC$$ satisfies 5cosA 7.3=0. than the roots of the quadratic equation $${ 9x }^{ 2 }+27x+20=0$$ are :

If $$\alpha ,\quad \beta $$ are the roots of the equation $${ x }^{ 2 }-2x+4=0,$$ then the value of $${ \alpha  }^{ 6 }+{ \beta  }^{ 6 }$$ is :

If $$x ^ { 2 } - 5 x + 1 = 0$$ then $$\frac { x ^ { 10 } + 1 } { x ^ { 5 } }$$ is equal to:-

$$(x+1)^2+(y-1)^2 +(x-5)^2+(y-1)^2$$ has the value equal to 

Which of the following is a quadratic equation ?