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Arithmetic Progressions Test - 26

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Arithmetic Progressions Test - 26
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  • Question 1
    1 / -0
    Find the common difference in the series: 0.2, 0.9, 1.6 ..............
    Solution
    First term, $$a_1 = 0.2$$

    Second term, $$a_2 = 0.9$$

    Common difference, $$d = a_2 - a_1$$

    $$d= 0.9 - 0.2$$

    $$\therefore d = 0.7$$
  • Question 2
    1 / -0
    Find the sum of the arithmetic series $$6 + 12 + 18 + ....... 96$$.
    Solution
    Given series is  $$6+12+18+....96$$.
    Here $$a = 6$$; last term, $$l = 96, d = 12-6 =6$$
    We know that, last term, $$l = a + (n - 1) d$$
    $$\Rightarrow 96 = 6 + (n - 1) 6$$
    $$\Rightarrow 96 = 6 + 6n - 6$$
    $$\Rightarrow 96 = 6n$$
    $$\Rightarrow n = \dfrac{96}{6}$$
    $$\Rightarrow n = 16$$ = total number of terms in the series

    We know that,

    Sum $$(S_n) = \dfrac{n}{2}$$   [First term $$+$$ Last term]

    $$= \dfrac{16}{2} [6 + 96]$$

    $$= 8 [102]$$

    Therefore, $$S_{16} = 816$$
  • Question 3
    1 / -0
    Find the common difference, if the sum of first n terms will be (n - 2) (n - 1).
    Solution
    The sum of first n terms, $$S_n = \dfrac{n}{2} (2a + (n - 1)d)$$
    On comparing the equations, we get
    $$\dfrac{n}{2} (2a + (n - 1) d) = (n - 2)(n + 1)$$
    $$(2a - d) n + dn^2 = n^2 - n - 2$$
    On comparing the factors of $$n^2$$, we find the value of $$ d= 1$$
    $$\therefore$$ The common difference is 1.
  • Question 4
    1 / -0
    Find the common difference in the sequence 4, 8, 12, 16, .......... 20
    Solution
    First term, $$a_1 = 4$$
    Second term, $$a_2 = 8$$
    Common difference, $$d = a_2 = a_1$$
    $$d = 8 - 4 = 4$$
    $$\therefore$$ The common difference is 4.
  • Question 5
    1 / -0
    _____ is a list of numbers in which each term is obtained by adding a fixed number to the preceding term except the first term.
    Solution
    $$\text {Arithmetic progression}$$ is a list of numbers in which each term is obtained by adding a fixed number to the preceding term except the first term.

    Ex: $$1, 2, 3, 4 $$ ..... In this sequence, the first number is $$1$$ and the next number is $$2$$. The difference between the two numbers is $$1$$ and so on. 

    By adding $$1$$ to the preceding number, we are forming the next term and so on, and the series is in $$AP$$.
  • Question 6
    1 / -0
    Find the number of terms in an A.P: $$-1,\ -5,\ -9,\ ..,\ - 197$$
    Solution
    Given: AP: $$-1, \ -5,\ -9,\ ...,\ -197$$

    Here, First term $$a = -1$$

    Common difference $$d = a_2 - a_1 = -5 - (-1) = - 4$$

    And last term $$a_n = - 197$$

    We know that, $$a_n = a + (n - 1) d$$

    $$\Rightarrow  -197 = -1 + (n - 1) - 4$$

    $$\Rightarrow -197 = -1 - 4n + 4$$

    $$\Rightarrow -197 + 1 - 4 = -4n$$

    $$\Rightarrow n = 50$$

    $$\therefore$$  There are 50 terms in the A.P
  • Question 7
    1 / -0
    Which term of the$$ A.P. 2, 9, 16, 23 .............$$ is $$100$$?
    Solution
    $$a = 2$$
    common difference, $$d = a_2 - a_1, a - 2 = 7$$
    we know that, $$a_n = a + (n - 1) d$$
    $$a_n = 100$$
    $$100 = a + (n - 1) 7$$
    $$100 = 2 + 7n - 7$$
    $$100 - 2 + 7 = 7n$$
    $$\dfrac{105}{7} = n$$
    $$n = 15$$
    Hence, $$15th$$ term of $$A.P$$. is $$100$$.
  • Question 8
    1 / -0
    Find 11th term of the A.P. : -3, 1, 5, ........
    Solution
    First term, $$a_1 = -3$$
    Common difference, $$d = a_2 - a_1 = 1 - (-3) = 4$$

    We know that, $$a_n = a_1 + (n - 1) d$$
    $$a_{11} = - 3 + (11- 1) 4$$
    $$= -3 + (10) 4$$
    $$= - 3 + 40$$
    $$a_{11} = 37$$
  • Question 9
    1 / -0
    The sum of n terms of an arithmetic sequence can be calculated by ......................... 
    Solution
    The sum of n terms of an arithmetic sequence can be calculated by $$S_n = \dfrac{n}{2} [2a+ (n - 1) d]$$
    Where, n denotes the total number of terms
    a = first term
    d = common difference
    $$S_n$$ = Sum of n terms
  • Question 10
    1 / -0
    Choose the correct statement(s):
    $$A$$: Every sequence is a progression.
    $$B$$: Every progression is a sequence.
    Solution
    The difference between a progression and a sequence is that a progression has a specific rule to calculate its next term from its previous term, whereas a sequence can be based on a logical rule like 'a group of prime numbers'.
    Thus, every progression is a sequence but every sequence is not a sequence.
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